Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to three decimal places.
Q: A car company claims that its new SUV gets better gas mileage than its competitor's SUV. A random…
A: For the company's SUV:The sample size, n1=41The sample mean gas mileage, x¯1=15.2The population…
Q: A random sample of 57 chemists from Washington state shows an average salary of $42635, the…
A: Let μ1 denotes the population mean salary for Washington state, and μ2 denotes the population mean…
Q: The tensile strength of paper using 5% hardwood and 10% hardwood are to be compared. A random sample…
A: Let A: Tensile strength of paper using 5% hardwood B: Tensile strength of paper using 10% hardwood…
Q: Are low-fat diets or low-carb diets more effective for weight loss? A sample of 51 subjects went on…
A:
Q: A car company claims that its new SUV gets better gas mileage than its competitor’s SUV. A random…
A: New SUVSample size, Sample mean, Population standard deviation, Competitor' SUVSample size, Sample…
Q: The historical reports from two major networks showed that the mean number of commercials aired…
A: There are two independent samples which are first station and second station. We have to test…
Q: An experiment was conducted to compare the difference in weight loss between aerobics (group 1) and…
A: Given: x¯1=5.7 x¯2=3.5s1=1.9 s2=0.7n1=27 n2=30
Q: An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 7070 type K…
A: From the provided information,
Q: At a local store, Sixty-five female employees were randomly selected and it was found that their…
A: Given that, n1=65, x1=640, s1=122n2=75, x2=682, s2=169 The null and alternative hypothesis is,…
Q: The type of alloy used in manufacturing electric wire is important in reducing resistance. It has…
A:
Q: A car company claims that its new SUV gets better gas mileage than its competitor’s SUV. A random…
A: Given : Population 1 :x1 = 13.6σ1 = 0.5n1 = 32Population 1 :x1 = 13.4σ1 = 0.6n1 = 47
Q: 4. Felician University uses hundreds of fluorescent light bulbs each year. The brand of bulb it…
A: The mean lifetime of current brand that it uses is of 900 hours. The mean and standard deviation of…
Q: A researcher is investigating whether a difference exists in the mean weight of green-striped…
A: Given that,X¯1=18σ1=2n1=43andX¯2=20σ2=1.7n2=40
Q: According to a research paper, the carbon monoxide exposure of someone riding a motorbike for 5 km…
A: From the provided information, Mean (µ) = 18.4 ppm Population standard deviation (σ) = 5.3 ppm X~N…
Q: Employees of a large corporation are concerned about the declining quality of medical services…
A:
Q: gets better gas mileage than its competitor's SUV. A random sample of 36 of its SUVs has a mean gas…
A:
Q: A car company claims that its new SUV gets better gas mileage than its competitor’s SUV. A random…
A: From the provided information,
Q: edical researchers interested in determining the relative effectiveness of two different drug…
A:
Q: A scientific supply company has developed a new breed of lab rat, which it claims weighs the same as…
A: Given that, A scientific supply company has developed a new breed of lab rat, which it claims weighs…
Q: State the null hypothesis H0 and the alternative hypothesis H1. b. Find the value of the test…
A: Given Data : For first group x̄1 = 163.0 s1 = 9.0 n1 = 8 For second…
Q: ates, two color variants of the Eastern Gray Squirrel-gray and black-are found in the rrels in a…
A:
Q: Based on sample data, newborn males have weights with a mean of 3281.4 g and a standard deviation of…
A:
Q: In a random sample of 8 cell phones, the mean full retail price was $521.70 and the standard…
A: A random sample of 8 cell phones, the mean full retail price was $521.70 and the standard…
Q: Steve believes that his wife’s cell phone battery does not last as long as his cell phone battery.…
A: From the given information,
Q: A biologist is interested in comparing the size of blue crabs in two river basins: Cooper River and…
A:
Q: A car company claims that its new SUV gets better gas mileage than its competitor's SUV. A random…
A: For population 1, sample size n1 = 32, sample mean = 13.6 and population SD = 0.5 For population 2,…
Q: Answer: What is the null distribution of the test statistic? Select one O a. AT distribution with 35…
A:
Q: An endocrinologist is interested in the effects of depression on the thyroid. It is believed that…
A: It is given that the p value is 0.0124 and the test is whether the mean thyroxin level is different…
Q: Population 1 and let the competitor's SUVs be Population 2. Step 3 of 3 : Draw a conclusion and…
A: n1=32,n2=41
Q: A comparison between species: Biologists comparing the gestation period of two newly discovered…
A: a) Denote μA, μB as the true average gestation period of frogs of species A and Species B,…
Q: A psychologist reports that the average length of R.E.M. sleep in his test subjects was 10 minutes.…
A: Hypothesis Testing: Hypothesis is a procedure by which we can tests an assumption regarding a…
Q: To determine the effects, researchers measured the LDL levels of 36 randomly selected men and 41…
A: Solution-: Given: For women:n1=41,x1¯=15.4,σ1=1.9 and For men: n2=36,x2¯=13.3,σ2=1.3…
Q: Pilots who cannot maintain regular sleep hours due to their work schedule often suffer from…
A: Answer Sample size [n] =28Standard deviation =1.7Variance [1.7]^2 =2.89
Q: A random sample of 42 chemists from Washington state shows an average salary of $46283, the…
A:
Q: The Weston Rescue Service and the Mid-Valley Ambulance Service are tested for response times. A…
A: Provided information is, the Weston Rescue Service and the Mid-Valley Ambulance Service are tested…
Q: The population standard deviation for the competitor is known to be 0.70.7 mpg. Test the company’s…
A: We want to find null hypothesis, alternate hypothesis and test statistics
Q: A car company claims that its new SUV gets better gas mileage than its competitor's SUV. A random…
A: The given values are:Sample size of Population 1 (n1) = 35Sample mean of Population 1 (x1) = 16.7…
Q: A comparison between species: Biologists comparing the gestation period of two newly discovered…
A: (a) State the hypotheses. That is, there is no evidence that the average lengths of the gestation…
Q: Steve believes that his wife’s cell phone battery does not last as long as his cell phone battery.…
A: Method By using the 90% confidence level to construct a confidence interval.
Q: Are low-fat diets or low-carb diets more effective for weight loss? A sample of 72 subjects went on…
A:
Q: A car company claims that its new SUV gets better gas mileage than its competitor's SUV. A random…
A: Step 1:Step 2: Step 3:Step 4:Step 5:
Q: A car company claims that its new SUV gets better gas mileage than its competitor’s SUV. A random…
A:
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 7070 type K batteries and a sample of 8585 type Q batteries. The type K batteries have a
Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to three decimal places.
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 1 images
- Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 40 randomly selected people who train in groups, and finds that they run a mean of 46.6 miles per week. Assume that the population standard deviation for group runners is known to be 4.6 miles per week. She also interviews a random sample of 45 people who train on their own and finds that they run a mean of 48.8 miles per week. Assume that the population standard deviation for people who run by themselves is 2.4 miles per week. Test the claim at the 0.02 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.A certain type of battery supercharger was found to take a mean of 12.3 minutes to charge a standard electric vehicle (EV) battery. A firmware update for this type of supercharger was recently released, but the update has received negative reviews from users. A researcher suspects the mean time the updated superchargers take to charge a standard EV battery is greater than 12.3 minutes. To test his claim, he chooses 21 of the updated superchargers at random and measures the time it takes each one to charge a standard EV battery. He finds that the superchargers take a sample mean of 12.9 minutes to charge a standard EV battery, with a sample standard deviation of 1.3 minutes. Assume that the population of amounts of time to charge a standard EV battery using the updated superchargers is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to support the claim that u, the mean time…A comparison between species: Biologists comparing the gestation period of two newly discovered species of frog collected data from 11 frogs of species A and 22 frogs of species B. Species A exhibited an average gestation period of 13 days with a standard deviation of 3.6 days while species B had a gestation period of 19 days and a standard deviation of 4.4 days. The researchers want to know whether the average lengths of the gestational periods differ between the two species. Conduct a hypothesis test at a significance level of a = 0.01. a) The hypotheses for this test are: O Họ: HA - PB = 0 Ha: HA - HB 0 O Họ: HB = 13 Ha: Hg = 13 O Họ: HA - HB = 0 Hạ: HA - PB = 0 What is the test statistic for this test? test statistic = (Report answer accurate to 2 decimal places.) What is the p-value for this test? p-value = (Report answer accurate to 4 decimal places.) The decision reached is O Fail to reject Ho O Reject Ho and accept Ha As such, the final conclusion is that O There is…
- An engineer would like to design a parking garage in the most cost-effective manner. He reads that the average height of pickup trucks, which is the largest type of vehicle that should be expected to fit into the parking garage, is 76.4 inches. To double-check this figure, the engineer employs a statistician. The statistician selects a random sample of 100 trucks and finds the mean height of the sample to be 77.1 inches with a standard deviation of 5.2 inches. The statistician will determine if these data provide convincing evidence that the true mean height of all trucks is greater than 76.4 inches. The statistician plans to test the hypotheses, H0: μ = 76.4 versus Ha: μ > 76.4, where μ = the true mean height of all trucks. The conditions for inference are met. The test statistic is t = 1.35 and the P-value is between 0.05 and 0.10. What conclusion should be made at the significance level, ? Reject H0. There is convincing evidence that the true mean height of all trucks is…An ecologist is examining whether the number of fish caught in a large river basin has changed since a fire burned some of the surrounding forested area and vegetation along the river. Data in the form of fishing reports was available for a five-year period before the fire. From a random sample of 195 fishing reports before the fire, the mean catch was 6.3 fish with a standard deviation of 1.6. In a random sample of 143 reports three years after the fire, the mean catch was 7.1 fish with a standard deviation of 2.1. Which of the following represents the standard error of the difference in the mean number of fish caught before and after the fire?Steve believes that his wife's cell phone battery does not last as long as his cell phone battery. On ten different occasions, he measured the length of time his cell phone battery lasted and calculated that the mean was 24.1 hours with a standard deviation of 10.3 hours. He measured the length of time his wife's cell phone battery lasted on eight different occasions and calculated a mean of 16.8 hours with a standard deviation of 7.8 hours. Assume that the population variances are the same. Let Population 1 be the battery life of Steve's cell phone and Population 2 be the battery life of his wife's cell phone. Step 2 of 2: Interpret the confidence interval obtained in Step 1. Answer 1 Point E Tables E Keypad Keyboard Shortcuts O Since the confidence interval contains zero, the data do not provide evidence that the population means are unequal at a 99% confidence level. Since the confidence interval does not contain zero, the data do not provide evidence that the population means are…
- A researcher is interested in examining the difference in the average egg incubation temperature of two lizards in North Carolina, the native green anoles versus the invasive brown anoles. To investigate this, she takes two random samples from both of the lizard populations and calculates the average egg incubation temperature, standard deviation, and sample size for each of the two samples. The average incubation temperature for the 25 sampled brown anoles is 83.2 degrees Fahrenheit, with a sample standard deviation of 20.2 degrees Fahrenheit. The average incubation temperature the 28 samples green anoles is 80.1 degrees Fahrenheit, with a sample standard deviation of 17.4 degrees Fahrenheit. She has also determined that the two samples do not exhibit strong skewness and appear approximately normal. Determine the appropriate t∗ critical value for a 99% confidence interval for the difference between the true mean incubation temperatures for the two different anole species, μ1−μ2.…In an experimental study of the longevity of Drosophila melanogaster (fruit fly) 70 male adults and 75 female adults were observed until the death of the last member in each group. The mean lifetime for the males was found to be 43.2 days with a standard deviation of 9.1 days. The corresponding figures for the females were 37.5 days and 8.8 days. Would you conclude that the male Drosophila has a greater longevity than the female? Alpha = 0.01A recent study showed that the average number of sticks of gum a person chews in a week is 13. The population standard deviation was 1.1. A college student believes that the guys in his dormitory chew a different amount of gum in a week. He conducts a study and samples 43 of the guys in his dorm and finds that on average they chew 11 sticks of gum in a week. Test the college student's claim at a=0.05. The correct hypotheses would be: Ο H: μ 13 (claim) Но: д > 13 HA: µ < 13 (claim) Ho: µ = HA:H + 13 (claim) 13 Since the level of significance is 0.05 the critical value is 1.96 and -1.96 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that a different amount of gum in a week. O There is not enough evidence to reject the claim that a different amount of gum in a week. O There is enough evidence to support the claim that a…
- A car company claims that its new SUV gets better gas mileage than its competitor's SUV. A random sample of 41 of its SUVS has a mean gas mileage of 15.2 miles per gallon (mpg). The population standard deviation is known to be 1.4 mpg. A random sample of 49 competitor's SUVs has a mean gas mileage of 14.8 mpg. The population standard deviation for the competitor is known to be 0.9 mpg. Test the company's claim at the 0.02 level of significance. Let the car company's SUVs be Population 1 and let the competitor's SUVs be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.Are low-fat diets or low-carb diets more effective for weight loss? A sample of 61 subjects went on a low-carbohydrate diet for six months. At the end of that time, the sample mean weight loss was 2.1 kilograms with a sample standard deviation of 4.71 kilograms. A second sample of 63 subjects went on a low-fat diet. Their sample mean weight loss was 3.7 kilograms with a standard deviation of 5.67 kilograms. Can you conclude that the mean weight loss of subjects having low-carb diets is less than the mean weight loss of subjects having low-fat diets? Let μ1 denote the mean weight loss on the low-carb diet and μ2 denote the mean weight loss on the low-fat diet. Use the =α0.05 level and the critical value method. 1) State the appropriate null and alternate hypotheses. 2)Choose a significance level and find the critical value. 3)Compute the test statistic. To compute the test statistic, we use the formula 4)Determine whether to reject H0.In a school district, all sixth grade students take the same standardized test. The superintendant of the school district takes a random sample of 30 scores from all of the students who took the test. She sees that the mean score is 169 with a standard deviation of 7.0674. The superintendant wants to know if the standard deviation has changed this year. Previously, the population standard deviation was 13. Is there evidence that the standard deviation of test scores has decreased at the α=0.005 level? Assume the population is normally distributed. Step 4: Make a decision. Is it reject Null hypothesis or Fail to reject Null hypothesis? Step 5: What is the conclusion? Is there sufficient evidence or there is not sufficient evidence to show that the standard deviation of the test scores has decreased?
