A magizine claimed that more than 55% of adults skip breakfast at least 3 days a week. To test this, a dietician selected a random sample of 80 adults and asked them how many days a week they skip breakfast. 45 of them responded that they skip breakfast at least 3 days a week. At a= .10, test

A magizine claimed that more than 55% of adults skip breakfast at least 3 days a week. To test this, a dietician selected a random sample of 80 adults and asked them how many days a week they skip breakfast. 45 of them responded that they skip breakfast at least 3 days a week. At a= .10, test

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher believes that 52.5% of people who grew up as the only child have an IQ score over 100. However, unknown to the researcher, this figure is actually 50%, which is the same as in the general population.To attempt to find evidence for the claim, the researcher is going to take a random sample of 400 people who grew up as the only child. Let p be the proportion of people in the sample with an IQ score above 100. Answer the following: a) Find the mean of p: b)Find the standard deviation of p: c) Compute an approximation for P(p ≥ 0.525), which is the probability that there will be 52.5% or more people with IQ scores over 100 in the sample. Round your answer to four decimal places.
A physical therapist claims that 75% of people lose their balance if they close their eyes while standing on one foot. A gymnast feels that the rate is less than 75%. To test this, she randomly selects 100 people and finds that 80 of them lose their balance while standing on one foot. To determine if these data provide convincing evidence that the proportion of people who lose their balance while standing on one foot and closing their eyes is less than 75%, 150 trials of a simulation are conducted. The gymnast is testing the hypotheses: H0: p = 75% and Ha: p < 75%, where p = the true proportion of people who will lose their balance while standing on one foot and closing their eyes. Based on the results of the simulation, what is the estimate of the P-value of the test? A) 0.1133 B) 0.17 C) 0.887 D) 0.92
A software company is interested in improving customer satisfaction rate from the 75% currently claimed. The company sponsored a survey of 190 customers and found that 155 customers were satisfied. What is the test statistic z?
Sebastian throws 850 pitches, of which 782 are strikes. To a 1% level of significance, is he right in his boast that over 90% of his pitches (in general) are strikes?
A study was performed to determine the percentage of people who wear life vests while out on the water. A researcher believed that the percentage was different for those who rode jet skis compared to those who were in boats. Out of 500500 randomly selected people who rode a jet ski, 85%85% wore life vests. Out of 250250 randomly selected boaters, 90.4%90.4% wore life vests. Using a 0.050.05 level of significance, test the claim that the proportion of people who wear life vests while riding a jet ski is not the same as the proportion of people who wear life vests while riding in a boat. Let jet skiers be Population 1 and let boaters be Population 2. Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. H0Ha: p1=p2: p1⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯p2 Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places. 3) draw a conclusion and form a decision (word it like "we fail to reject the null hypothesis and…
In a sample of 202 men, 77 said they used seat belts. In a sample of 311 women, 84 said they used seat belts. Test the claim that men are more safety conscious than women, at a=0.01?
Supposed that in the past, 10% of women in the Philippines have severe dysmenorrhea. Do we have enough reason to believe that the proportion of women having terrible cramps has decreased if, in a random barangay population of 1,256 women, 122 have severe enough cramping to interfere with their daily lives? Use a = 0.05
A Verizon researcher compared the number of text messages sent by a sample of teenage boys to the population mean for all Verizon users. She found no evidence to conclude that there was a difference. Unfortunately, her conclusion was in error. (a) What type of error did she make? (b) What conclusion should she have reached?
The authors of a paper randomly selected two samples of patients admitted to the hospital after suffering a stroke. One sample was selected from patients who received biofeedback weight training for 8 weeks, and the other sample was selected from patients who did not receive this training. At the end of 8 weeks, the time it took (in seconds) to stand from a sitting position and then to sit down again (called sit-stand-sit time) was measured for the people in each sample. Data consistent with summary quantities given in the paper are given below. For purposes of this exercise, you can assume that the samples are representative of the population of stroke patients who receive the biofeedback training and the population of stroke patients who do not receive this training. Biofeedback Group 2.1 2.8 4.5 2.3 2.9 4.3 3.4 4.2 3.4 3.7 3.0 3.7 3.7 2.5 3.3 No Biofeedback Group 5.2 4.8 4.0 4.3 4.8 4.4 4.3 5.2 3.5 4.3 5.2 4.5 4.1 3.5 4.0 Conduct a test of hypothesis to test whether…
A group of 320 male students from the local high school have a mean mass of 70.41 kg. Records of similar students countrywide show a mean mass of 70.0 kg. A researcher wishes to determine whether the local students differ from the national group. what would be the research problem?
According to the Humane Society, 33% of households in the United States own at least one cat. You are interested in determining whether the proportion of households of the students at your school that own at least one cat is different from the national proportion. Suppose you survey an SRS of students at your school and find that 25% of them own cats, which yields a p-value of .092. Interpret this p-value.
The CEO of a large electric utility claims that at least 80 percent of his one million customers are very satisfied with the service they receive. A local newspaper surveyed 300 customers randomly. 73 percent said they were very satisfied. The test statistic is (Round answer to two decimal places. Do not write 0.12 as .12.)