What is the p-value?
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A: 3.95 4.07 4.14 4.04 4 3.93 3.98 4.01 3.9 4.03 4.13 3.88 4.03 4.1 3.81…
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Q: ) Which of the following figures (next page) best describes the p-value for this hypothesis testing…
A: Sample size=26
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A: Given that Sample sizes n1=402 , n2=319 Sample proportion p1^=0.224 , p2^=0.251
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A: Given information: μ=1.50x¯=1.35s=0.50n=9α=0.10
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A: If a person has a z-score of –2.00
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A: Hence, the population mean is $21.84
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A: Note: Thank you for the question. Since only 25 data values are given, we have obtained mean and…
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A: n1=n2=28 X1-bar=15.2 X2-bar=12.3 S1=2.5 S2=1.9
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The worldwide market share for a web browser was 20.5% in a recent month. Suppose that a sample of 200 random students at a certain university finds that 50 use the browser.
What is the p-value?
Here sample size is too large so use z test for proportion
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- Your statistics instructor often ponders the relationship between commute time and job satisfaction while driving back and forth to campus. Your instructor hypothesizes that people with a shorter commute time will have higher degrees of job satisfaction. Randomly sampling 600 Valley commuters, the instructor finds the following data listed in frequencies: Table 2: Commuters by Length of Commute and Job Satisfaction Job Satisfaction Number Who Commute 20 Minutes or Less Number Who Commute 21 to 40 Minutes Number Who Commute 41 Minutes or More Total Number for Each Level of Job Satisfaction Dissatisfied 10 60 140 210 Neutral 45 59 51 155 Satisfied 145 60 30 235 Total Number for Each Commute Time Range 200 179 221 1. Change frequencies to column percentages.An auto shop wants to examine the proportion of customers that have to return after an appointment. Last year, an examination of 375 customers found that 26.9% had to return after an appointment. You instituted some changes at the auto shop this year, and found from a sample of 430 customers that 33.9% had to return after an appointment. You want to conduct an analysis to determine if there has been an increase in the proportion of customers that need to return after an appointment since the past year, with a significance level of 1%. Using this information, what is the test statistic of your analysis? For the purposes of this analysis, use - Pcurrent year Plast Round any intermediate numbers to four decimal year. places and choose the closest choice to your answer. 2.575 1.03 2.15 1.64 3.30In a study comparing banks in two countries, a sample of 142 matched pairs of banks was formed. Each pair contained one bank from country x and one from country y. The pairings were made in such a way that the two members were as similar as possible in regard to such factors as size and age. The ratio of total loans outstanding to total assets was calculated for each of the banks. For this ratio, the sample mean difference (country x - country y) was 0.0579, and the sample standard deviation of the differences was 0.3086. Test, against a two-sided alternative, the null hypothesis that the two population means are equal. (Assume α = 0.01.) Click the icon to view the critical values of the Student's t distribution. Which of the following correctly states Ho and H₁ ? A. Ho: Mx Hy = 0 H₁: Hx-Hy >0 OC. Ho: Mx Hy ‡0 Hi HxHy=0 - O E. Ho: Mx Hy = 0 H₁: Hx-Hy <0 B. Ho: Mx Hy = 0 H₁: Hx-Hy #0 D. Ho: Hx-Hy = 0 H₁: Hx-Hy 20 OF. Ho: Mx Hy = = 0 H₁: Hx-Hy ≤0
- In a study comparing banks in two countries, a sample of 142 matched pairs of banks was formed. Each pair contained one bank from country x and one from country y. The pairings were made in such a way that the two members were as similar as possible in regard to such factors as size and age. The ratio of total loans outstanding to total assets was calculated for each of the banks. For this ratio, the sample mean difference (country x - country y) was 0.0579, and the sample standard deviation of the differences was 0.3086. Test, against a two-sided alternative, the null hypothesis that the two population means are equal. (Assume α = 0.01.) Click the icon to view the critical values of the Student's t distribution. The test statistic is t = 2.236. (Round to three decimal places as needed.) The critical value(s) is(are) (Round to three decimal places as needed. Use a comma to separate answers as needed.)Save Suppose that in a random selection of 100 colored candies, 23% of them are blue. The candy company claims that the percentage of blue candies is equal to 21%. Use a 0.05 significance level to test that claim. Identify the pull and alternaThe Substance Abuse and Mental Health Services Administration (SAMHSA, 2017) estimates that 10.9% of the population of the United States age 18–24 had an episode of depression in the previous 12 months. Suppose a researcher takes a random sample of 225 United States adults aged 18–24. Determine the value of the sample proportion, p, such that 5% of samples of 225 United States adults age 18–24 are greater than p. You may find software or a z-table useful. Give your answer precise to three decimal places. p = II
- Twelve percent of the world's population is left-handed. A researcher claims that left-handed individuals are more creative than those who aren't left-handed. In order to support his claim, he takes a sample of 1650 artists and finds that 14% of.them are left-handed. Español Answer the following. (If necessary, consult a list of formulas.) (a) Find the mean of p, where p is the proportion of left-handed individuals in a random sample of 1650. 00 (b) Find the standard deviation of p. (c) Compute an approximation for P (p s0.14), which is the probability that there will be 14% or fewer left-handed people in a random sample of 1650. Round your answer to four decimal places. Save For Later Submit Assignment Check Terms of Use Privacy Center Accessibility acer esc backspaThe Wall Street Journal asked Concur Technologies, Inc., an expense management company, to examine data from 8.3 million expense reports to provide insights regarding business travel expenses. Their analysis of the data showed that New York was the most expensive city. The following table shows the average daily hotel room rate (*) and the average amount spent on entertainment (y) for a random sample of 9 of the 25 most-visited U.S. cities. These data lead to the estimated regression equation ŷ = 17.49 +1.0334x. For these data SSE = 1541.4. Click on the datafile logo to reference the data. Use Table 1 of Appendix B. DATA file City Boston Denver Nashville New Orleans Phoenix San Diego San Francisco San Jose Room Rate ($) 148 96 91 110 90 102 136 90 82 Tampa a. Predict the amount spent on entertainment for a particular city that has a daily room rate of $89 (to 2 decimals). $ Entertainment ($) 161 105 101 142 ***** b. Develop a 95% confidence interval for the mean amount spent on…Suppose that a recent article by a historian stated that the mean time spent in jail by a first–timeconvicted burglar in the 20th century was 2.5 years. A study was then done to see if the mean time has increasedin the new century. A random sample of 26 first-time convicted burglars in a recent year was picked. The meanlength of time in jail from the survey was 3 years. Suppose that it is somehow known that the population standarddeviation is 1.8 years and that the population is normally distributed.The hypotheses can then be framed as:H0 : μ = 2.5 vs. Ha : μ > 2.5(a) Which of the following figures (next page) best describes the p-value for this hypothesis testingproblem. Explain your reasoning. (numbers above red shaded area represent the corresponding probabilities). (b) Write the decision and conclusion for this hypothesis testing problem if the significance level, α,is 0.1.
- A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in Connecticut and California. Due to recent trends in the childcare industry, the firm suspects that the that the mean annual income of childcare workers in the state of Connecticut is greater than the mean annual income of childcare workers in California. To see if this is true, the firm selected a random sample of 10 childcare workers from Connecticut and an independent random sample of 10 childcare workers from California and asked them to report their mean annual income. The data obtained were as follows. 80°F Partly sunny Annual income in dollars Connecticut 42438, 52287, 46837, 49334, 52848, 52929, 57111, 51860, 44967, 52174 California 50998, 38334, 56804, 50919, 49446, 41141, 45717, 43963, 55156, 47295 LL D 144Hz Send data to calculator V The population standard deviations for the annual incomes of childcare workers in Connecticut and in California are estimated as 6300 and 6100,…The plant-breeding department at a major university developed a new hybrid boysenberry plant called Stumptown Berry. Based on research data, the claim is made that from the time shoots are planted 90 days on average are required to obtain the first berry. A corporation that is interested in marketing the product, tests 60 shoots by planting them and recording the number of days before each plant produces its first berry. The sample mean is 92.3 days. The corporation will not market the product if the mean number of days is more than the 90 days claimed. The hypotheses are: H0:μ = 90 H1:μ > 90 What is a type I error in the context of this problem