A scientist uses transduction to map genes in a strain of E. coli. For this experiment, the donor strain is leu+ phe+lys-+arg+. The recipient is leu-phe-lys-arg- Co-transduction rates were • leut and phe+ = 29% • leu+ and arg+ = 46% • leu+ and lys+ = 6% Which gene is furthest from leu? lys phe arg leu Is the percentage is the chance of being co-transduction
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A scientist uses transduction to map genes in a strain of E. coli. For this experiment, the donor strain is leu+ phe+lys-+arg+. The recipient is leu-phe-lys-arg- Co-transduction rates were
• leut and phe+ = 29% • leu+ and arg+ = 46% • leu+ and lys+ = 6%
Which gene is furthest from leu?
lys
phe
arg
leu
Is the percentage is the chance of being co-transduction
Step by step
Solved in 2 steps
- In five Hfr strains, each of which was used to build a time-of-transfer map, the genes entered the recipient cells as follows: Strain 1: S L A C T F Strain 2: N P F T C A Strain 3: T F P N U Y Strain 4: S H Y U N P Strain 5: U N P F T C Which of the following represents a correct gene map of these results? N P F T S L A C H U Y S L A C T F P N H Y U C T F P N U Y H S L A T C A L S P N U Y H F U N P C A L S F T H YIn E. coli, the gene bioD+ encodes an enzyme involved in biotin synthesis, and galK+ encodes an enzyme involved in galactose utilization. An E. coli strain that contained wild-type versions of both genes was infected with P1 phage, and then a P1 lysate was obtained. This lysate was used totransduce (infect) a strain that was bioD− and galK−. The cellswere plated on a medium containing galactose as the sole carbonsource for growth to select for transduction of the galK+ gene.This medium also was supplemented with biotin. The resultingcolonies were then restreaked on a medium that lacked biotin tosee if the bioD+ gene had been cotransduced. The following resultswere obtained:What information do you know based onthe question and your understanding of the topic?In E. coli, the gene bioD+ encodes an enzyme involved in biotin synthesis, and galK+ encodes an enzyme involved in galactose utilization. An E. coli strain that contained wild-type versions of both genes was infected with P1 phage, and then a P1 lysate was obtained. This lysate was used totransduce (infect) a strain that was bioD− and galK−. The cellswere plated on a medium containing galactose as the sole carbonsource for growth to select for transduction of the galK+ gene.This medium also was supplemented with biotin. The resultingcolonies were then restreaked on a medium that lacked biotin tosee if the bioD+ gene had been cotransduced. The following resultswere obtained:What topic in genetics does this question address?
- Bacteriophage P22 was used in generalised transduction experiments to infect the Salmonella typhimurium donor strains described in the table below. The resulting phage lysates were then used to infect the recipient strains of S. typhimurium recipient strains listed in the table. In each cross, a phenotype was selected for one of the selected for one of the three genetic markers studied (str, aceA, thrA), and were made to select the recombinants corresponding to the other two markers. markers. The results are given in the following table: Strain I donor str thrA aceA thrA str aceA+ Strain recipient strs thrA+ aceA thrA str aceA Phenotype selected Str Ace+ Str recombinants selected ThrA ThrA ThrA ThrA Ace Ace Number 60 40 95 5 10 90 str: gene involved in streptomycin resistance, aceA: gene involved in the use of acetate as a carbon source, thrA: gene involved in threonine biosynthesis. 1) What are the selective media used in these three transduction experiments? to obtain the selected…A transduction experiment was carried out to map the his and leu genes, which are involved in amino acid biosynthesis, of E. coli using a his+ leu+ donor and a his- leu- recipient. his+ leu- transductants will grow on agar media with: OA lacking histidine, containing leucine O B. containing histidine, containing leucine OC containing histidine, lacking leucine O D.a and b are correct O E. a, b and c are correctWild-type bacteria were used as donors to transduce the following recipient genotypes with the results indicated as the number of wild type colonies: Recipient Recipient leu- phe+ his- met+ tyr+ leu- phe+ his+ met- tyr+ leu- phe+ his+ met+ tyr- leu- phe- his+ met+ tyr+ leu+ phe+ his-met- tyr+ 127 leu+ phe-his- met+ tyr+ #wild type 37 138 132 1 leu+ phe+ his- met+ tyr- leu+ phe-his+ met- tyr+ leu+ phe-hist met+ tyr- leu- phe+ his+ met+ tyr+ 22 6 leu+ phe+ his+ met- tyr- 148 31 304 leu+ phe+ his+ met+ tyr- What is the order of the genes? tyr-leu-his-phe-met O leu-met-phe-his-tyr leu-his-met-tyr-phe his-tyr-leu-phe-met #wild type 356 10
- In a generalized-transduction experiment, phages arecollected from an E. coli donor strain of genotype cys+leu+ thr+ and used to transduce a recipient of genotypecys- leu- thr-. Initially, the treated recipient populationis plated on a minimal medium supplemented with leucine and threonine. Many colonies are obtained.a. What are the possible genotypes of these colonies?b. These colonies are then replica plated onto threedifferent media: (1) minimal plus threonine only, (2)minimal plus leucine only, and (3) minimal. Whatgenotypes could, in theory, grow on these three media?c. Of the original colonies, 56 percent are observed togrow on medium 1, 5 percent on medium 2, and nocolonies on medium 3. What are the actual genotypes ofthe colonies on media 1, 2, and 3?d. Draw a map showing the order of the three genes andwhich of the two outer genes is closer to the middle geneIn Hershey-Chase experiment, bacteriophages protein coats were tagged with radioactive isotope S-32. These phages were used to infect E. coli cells and the cells were further centrifuged to form pellets. Why was the radioactivity level of S-32 found greater outside the cells compared to the E. coli cell pellets? Explain briefly. If the experiment is repeated in the same manner but this time the phage protein coats are labelled with isotope X and the phage DNA with isotope Y, which isotope’s radioactivity will be found in greater amounts in the E. coli cell pellets after centrifugation? Explain briefly.Austin Taylor and Edward Adelberg isolated some new strains of Hfr cells that they then used to map several 200 mal+ genes in Escherichia coli by using interrupted conjugation. 150 In one experiment, the researchers mixed cells of Hfr strain AB-312, which were xyl* mtl* mal* met* and sensitive to phage T6, with F strain AB-531, which was xyl mtl mal met and resistant to phage T6. The 100 mt/+ cells were allowed to undergo conjugation. At regular intervals, the researchers removed a sample of cells and 50 met+ interrupted conjugation by killing the Hfr cells with phage T6. The F cells, which were resistant to phage T6, survived and were then tested for the presence of 0. 20 40 60 80 100 genes transferred from the Hfr strain. The results of this experiment are shown in the graph. Time of sampling (minutes) On the basis of these data, give the order of the xyl, mtl, mal, and met genes on the bacterial chromosome and the minimum distances between them in minutes. The origin of transfer is…
- Austin Taylor and Edward Adelberg isolated some new strains of Hfr cells that they then used to map several genes in E. coli by using interrupted conjugation . In one experiment, they mixed cells of Hfr strain AB-312, which were xyl+ mtl+ mal+ met+ and sensitive to phage T6, with F− strain AB-531, which was xyl− mtl− mal− met− and resistant to phage T6. The cells were allowed to undergo conjugation. At regular intervals, the researchers removed a sample of cells and interrupted conjugation by killing the Hfr cells with phage T6. The F− cells, which were resistant to phage T6, survivedand were then tested for the presence of genes transferred from the Hfr strain. The results of this experiment are shown in the accompanying graph. On the basis of these data, give the order of the xyl, mtl, mal, and met genes on the bacterial chromosome and indicate the minimum distances between them.Cre-Lox system is used for site-specific modification of DNA for genetic engineering applications. The reporter gene construct shown below is used to test the Cre-Lox system. Cells are transfected with the construct shown below and the activity of the constructs is determined by visualizing the cells with a fluorescence microscope. Match the following conditions with the expected cell observations. Hint: Make sure you note the position of the Start and Stop. The GFP and RFP genes shown do not have start codons. Cre/Lox Reporter Gene ATG LoxP CMV-Pro A. No Expression GFP Stop B. GFP Only LoxP Absence of Cre Cells treated with drug that induces expression of Cre RFP C. RFP Only A. Image A B. Image B C. Image C D Image D express ? D. RFP and GFPBy conducting conjugation experiments between Hfr and recipientstrains, Wollman and Jacob mapped the order of many bacterialgenes. Throughout the course of their studies, they identified severaldifferent Hfr strains in which the F-factor DNA had been integratedat different places along the bacterial chromosome. A sample of theirexperimental results is shown in the following table:What information do you know based on the question and your understanding of the topic?