A non-uniform electric field is given by the expression Ex = (2xy) Ey = (3yz) Ez = (-4xz). Determine the electric flux through a surface in the xz-plane, extending from x=0 to x=5m and z=0 to z=8m
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A non-uniform electric field is given by the expression Ex = (2xy) Ey = (3yz) Ez = (-4xz). Determine the electric flux through a surface in the xz-plane, extending from x=0 to x=5m and z=0 to z=8m
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- A surface with area 2m2 in lies in the y-z plane. What is the flux through this area created by an electric field with components: Ex=24N/C Ey=30N/C Ez=16N/C 32 Nm2/C 60 Nm2/C 48 Nm2/C 29 Nm2/C 75 Nm2/CA solid conducting sphere, which has a charge Q1 =84Q and radius rg = 1.5R is placed inside a very thin spherical shell of radius rp = 3.4R and charge Q2 =15Q as shown in the figure below. Q2 Tb Q1 ra Find the magnitude of the electric field at r=6.2. Express your answer using one decimal point in units 1 where k = 4περ of kAn infinite cylindrical conductor has an inner radius ra =57.9mm and an outer radius 70.4mm. The conductor has a linear charge density of A₁ =136. On the axis of the cylinder is an infinite line charge with linear charge density ₂ = -9€. Determine the electric field magnitude at the point r = 31.03mm (in) C O
- The electric field of a thin uniformly charged disk of radius 2.5 m very close to disk center is 263 N/C. The disk is centered on the xy plane. Calculate the magnitude of the electric field ( in N/C) on the z-axis at a distance 4 m from the center of the disk.A closed surface with dimensions a = b = 0.208 m and c = 0.3328 m is located as in the figure. The electric field throughout the region is nonuniform and defined by E (a + Bx²) î where x is in meters, a = 5 N/C, and 3 = 6 N/(C · m²). Y E Answer in units of C a x k What is the magnitude of the net charge enclosed by the surface? Answer in units of C. part 2 of 2 What is the sign of the charge enclosed in the surface?A concentric hollow insulating spherical shell with inner radius rj=1.59R and outer radius ry=3.88R has a point charge Q1=-10.43Q at the center. If the insulating shell has a uniform volume charge density p=9.25(Q/R), find the electric field at a point midway between inner and outer surface of the insulating sphere, Er= 1+/2, Q -and radial unit vector. (Express your answer in 2 decimal places). interms of 4 TTEOR?
- A nonuniform electric field is given by the expression E = (3.00x? i + 5.00y j) N/C and passes through a square surface of side length 2.00 m parallel to the xz-plane at y = 1.00 m. Using the area vector from the previous question, what is the electric flux through the surface? O Nm^2/C O 15.0 Nm^2/C O 20.0 Nm^2/C O 12.0 Nm^2/cA solid conducting cylinder, which has a charge Q1 =61Q and radius ra = 1.7R is placed inside a very thin cylindrical shell of radius rp = 4.1R and charge Q2 =-8Q as shown in the figure below. Q2 R2 Q1 R Find the magnitude of the electric field at r=5.3R. Express your answer using one decimal point in units of TTEORLCalculate the absolute value of the electric flux for the following situations (In all case provide your answer in N m2/C): c. A uniform electric field E = (−350 i + 350 j + 350 k) N/C through a disk of radius 3 cm in the x-z plane.
- A disk of radius 0.10 m is oriented with its normal unit vector în at 30° to a uniform electric field of magnitude 2.0 × 10³ N/C. What is the electric flux through the disk? r = 0.10 m 30A solid insulating sphere of radius a=5.0 cm carries a net positive charge of Q=6.0 µC uniformly distributed throughout its volume. Concentric with this sphere is a conducting spherical shell with inner radius b=10 cm and outer radius c=15 cm and having net charge Q2= -8 µC, as shown. The electric field at a point r=12 cm from the center is: Insulator Conductor O 1.3×106 N/C O 3.8×106 N/C 5.0x106 N/C zeroAn electric field has a uniform value (doesn't change with position) that can be described by the following equation: E = (Aĵ + B k) N/C where A and B are given by the values below. A = 1.35 B = 1.80 There is a flat circular surface that is in the x-y plane and centered at the origin point (0,0,0). This surface has a radius of 1.65 m. Calculate the magnitude of the electric flux through the surface due to the electric field described above. Your units should be Nm²/C.