5. DETAILS MY NOTES ASK YOUR TEACHER An electron travels to the right, as shown in the figure below, starting in a region of zero magnetic field, and then entering a region of uniform magnetic field, pointing into the page, with a magnitude of b = 1.55 mT. ** ***** * * * B=0 ***** B=b i (a) Once the electron enters the region of nonzero magnetic field, it travels in a complete semicircle before exiting the region of field again. (That is, it exits the region moving to the left.) How long (in s) is the electron in the region of nonzero field? S (b) The electron penetrates a maximum depth of 3.05 cm into the region of nonzero field. What is the kinetic energy (in eV) of the electron? eV

5. DETAILS MY NOTES ASK YOUR TEACHER An electron travels to the right, as shown in the figure below, starting in a region of zero magnetic field, and then entering a region of uniform magnetic field, pointing into the page, with a magnitude of b = 1.55 mT. *** * * * B=0 ***** B=b i (a) Once the electron enters the region of nonzero magnetic field, it travels in a complete semicircle before exiting the region of field again. (That is, it exits the region moving to the left.) How long (in s) is the electron in the region of nonzero field? S (b) The electron penetrates a maximum depth of 3.05 cm into the region of nonzero field. What is the kinetic energy (in eV) of the electron? eV

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter28: Magnetic Fields

Section: Chapter Questions

Problem 46AP: Why is the following situation impossible? Figure P28.46 shows an experimental technique for...

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An electron is accelerated through 2.40 103 V from rest and then enters a uniform 1.70-T magnetic field. What are (a) the maximum and (b) the minimum values of the magnetic force this particle experiences?
An alpha-particle ( m=6.641027kg , q=3.21019C ) travels in a circular path of radius 25 cm in a uniform magnetic field of magnitude 1.5 T. (a) What is the speed of the particle? (b) What is the kinetic energy in electron-volts? (c) Through what potential difference must the particle be accelerated in order to give it this kinetic energy?
(a) An oxygen16 ion with a mass at 2.661026kg travels at 5.00106m/s perpendicular to a 1.20T magnetic field, which makes it move in a circular arc with a 0.231-m radius. What positive charge is on the ion? (b) What is the radio of this charge to the charge of an electron? (c) Discuss why the radio found in (b) should be an integer.
Unreasonable results A charged particle having mass 6.641027kg (that of a helium atom) moving at 8.70105m/s perpendicular to a 1.50-T magnetic field travels in a circular path of radius 16.0 mm. (a) What is the charge of the particle? (b) What is unreasonable about this result? (c) Which assumptions are responsible?
Electrons in Earths upper atmosphere have typical speeds near 6.00 105 m/s. (a) Calculate the magnitude of Earths magnetic field if an electrons velocity is perpendicular to the magnetic field and its circular path has a radius of 7.00 102 m. (b) Calculate the number of times per second that an electron circles around a magnetic field line.
A singly charged ion of mass m is accelerated from rest by a potential difference V. It is then deflected by a uniform magnetic field (perpendicular to the ions velocity) into a semicircle of radius R. Now a doubly charged ion of mass m' is accelerated through the same potential difference and dellected by the same magnetic field into a semicircle of radius R' = 2R. What is the ratio of the masses of the ions?
A particle’s path is bent when it passes through a region of non-zero magnetic field although its speed remains unchanged. This is very useful for “beam steering’’ in particle accelerators. Consider a proton of speed 4106m/s entering a region of uniform magnetic field 0.2 T over a 5-cm-wide region. Magnetic field is perpendicular to the velocity of the particle. By how much angle will the path of the proton be bent? (Hint: the particle comes out tangent to a circle.
The current through a circular wire loop of radius 10 cm is 5.0 A. (a) Calculate themagnetic dipole moment of the loop. (b) What is the torque on the loop if it is in a uniform 0.20-T magnetic field such that p and B are directed at 300 to each other? (C) For this position, what is the potential energy of the dipole?
A laboratory electromagnet produces a magnetic field of magnitude 1.50 T. A proton moves through this field with a speed of 6.00 106 m/s. (a) Find the magnitude of the maximum magnetic force that could be exerted on the proton. (b) What is the magnitude of the maximum acceleration of the proton? (c) Would the field exert the same magnetic force on an electron moving through the field with the same speed? (d) Would the electron undergo the same acceleration? Explain.
A toroid has 250 trims of wire and carries a current of 20 A. Its inner and outer radii are 8.0 and 9.0 cm. What are the values of its magnetic field at r = 8.1, 8.5, and 8.9 cm?
A proton moving horizontally enters a region where a uniform magnetic field is directed perpendicular to the proton's velocity as shown in Figure OQ29.4. After the proton enters the field, does it (a) deflect downward, with its speed remaining constant; (b) deflect upward, moving in a semicircular path with constant speed, and exit the field moving to the left; (c) continue to move in the horizontal direction with constant velocity; (d) move in a circular orbit and become trapped by the field; or (e) deflect out of the plane of the paper?
A 5.0-m section of a long, straight wire carries a current of 10 A while in a uniform magnetic field of magnitude 8.0103T . Calculate the magnitude of the force on the section if the angle between the field and the direction of the current is (a) 45°; (b) 90°; (C) 0°; or (d) 180°.