Part AA person with body resistance between his handsof 12 k accidentally grasps the terminals of a16-kV power supply.If the internal resistance of the power supply is 2300 2, what is the current through the person's body?Express your answer using two significant figures.I =ΜΕ ΑΣΦSubmitRequest AnswerPart BWhat is the power dissipated in his body?Express your answer using two significant figures.ΕΕ ΑΣΦP =SubmitRequest AnswerPart C??AWIf the power supply is to be made safe by increasing its internal resistance, what should the internalresistance be for the maximum current in the above situation to be Imax = 1.00 mA or less?Express your answer using two significant figures.r =ΕΠΙ ΑΣΦSubmitRequest Answer?Ω

Part A:I=RV=12k+230016k=1.1188≈1.12APart B:P=VI=I2R=(1.12)2(12k)=15.0528⋅103=15.05kWPart…

Answered: Part A A person with body resistance…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter21: Circuits And Dc Instruments

Section: Chapter Questions

Problem 26PE: A person with body resistance between his hands of 1.00 k accidentally grasps the terminals of a...

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