For the following, put all final answers in the +20V table below or sketch a similar table. a. Solve for the equivalent resistance of the circuit. Put your final answer in the table. 20 b. Solve for the voltage across and the current 12 Q through each resistor in the circuit. Fill in the 10 table. 50 20 Ω Equivalent Resistance = Resistor (0) |AV| (V)| |I| (A) Ω 1 2 12 20
For the following, put all final answers in the +20V table below or sketch a similar table. a. Solve for the equivalent resistance of the circuit. Put your final answer in the table. 20 b. Solve for the voltage across and the current 12 Q through each resistor in the circuit. Fill in the 10 table. 50 20 Ω Equivalent Resistance = Resistor (0) |AV| (V)| |I| (A) Ω 1 2 12 20
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter23: Series And Parallel Circuits
Section23.1: Simple Circuits
Problem 24SSC
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Transcribed Image Text:**Instructions:**
For the following, put all final answers in the table below or sketch a similar table.
**a.** Solve for the equivalent resistance of the circuit. Put your final answer in the table.
**b.** Solve for the voltage across and the current through each resistor in the circuit. Fill in the table.
**Diagram:**
- A circuit is shown with a 20V battery.
- Five resistors are connected: 1Ω, 2Ω, 12Ω, 5Ω, and 20Ω.
- The 1Ω and 12Ω resistors are in series with the battery.
- The 2Ω, 5Ω, and 20Ω resistors form a combination of parallel and series connections.
**Table:**
| **Equivalent Resistance =** | \( \Omega \) |
| --- | --- |
| Resistor (Ω) | \(|\Delta V| \) (V)| \( |I| \) (A) |
| 1 | | |
| 2 | | |
| 5 | | |
| 12 | | |
| 20 | | |
- Fill in the table with calculated values for the voltage across (\(|\Delta V|\)) and the current through (\(|I|\)) each resistor, as well as the overall equivalent resistance.
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