Physics for Scientists and Engineers
10th Edition
ISBN: 9781337553278
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Textbook Question
Chapter 23, Problem 37AP
Find the electric flux through the plane surface shown in Figure P23.37 if θ = 60.0°, E = 350 N/C, and d = 5.00 cm. The electric field is uniform over the entire area of the surface.
Figure P23.37
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A uniform electric field of magnitude E = 435 N/C makes an angle of O = 65.0° with a plane surface of area A = 3.50 m2 as in Figure P15.40. Find the electric flux through this surface.
Consider the uniform electric field E = (3.5 j + 3.5 k) × 103 N/C.
a) Calculate the electric flux through a circular area of radius 1.75 m that lies in the yz-plane. Give your answer in N·m2/C.
b) Repeat the electric flux calculation for the circular area for the case when its area vector is directed at 45° above the xy-plane. Give your answer in N·m2/C.
A uniform electric field of magnitude E = 435 N/C makes an angle of θ = 65.0° with a plane surface of area A = 3.50 m2 as in Figure P15.44. Find the electric flux through this surface.
Chapter 23 Solutions
Physics for Scientists and Engineers
Ch. 23.2 - Suppose a point charge is located at the center of...Ch. 23.3 - If the net flux through a gaussian surface is...Ch. 23 - A negatively charged rod of finite length carries...Ch. 23 - A positively charged disk has a uniform charge per...Ch. 23 - A uniformly charged ring of radius 10.0 cm has a...Ch. 23 - The electric field along the axis of a uniformly...Ch. 23 - Example 23.3 derives the exact expression for the...Ch. 23 - A uniformly charged rod of length L and total...Ch. 23 - A continuous line of charge lies along the x axis,...Ch. 23 - A thin rod of length and uniform charge per unit...
Ch. 23 - (a) Consider a uniformly charged, thin-walled,...Ch. 23 - A vertical electric field of magnitude 2.00 104...Ch. 23 - A flat surface of area 3.20 m2 is rotated in a...Ch. 23 - A nonuniform electric field is given by the...Ch. 23 - An uncharged, nonconducting, hollow sphere of...Ch. 23 - Find the net electric flux through the spherical...Ch. 23 - Four closed surfaces, S1 through S4 together with...Ch. 23 - A charge of 170 C is at the center of a cube of...Ch. 23 - (a) Find the net electric flux through the cube...Ch. 23 - A particle with charge of 12.0 C is placed at the...Ch. 23 - A particle with charge Q = 5.00 C is located at...Ch. 23 - A particle with charge Q is located at the center...Ch. 23 - (a) A panicle with charge q is located a distance...Ch. 23 - Find the net electric flux through (a) the closed...Ch. 23 - Figure P23.23 represents the top view of a cubic...Ch. 23 - Determine the magnitude of the electric field at...Ch. 23 - In nuclear fission, a nucleus of uranium-238,...Ch. 23 - Suppose you fill two rubber balloons with air,...Ch. 23 - A large, flat, horizontal sheet of charge has a...Ch. 23 - A nonconducting wall carries charge with a uniform...Ch. 23 - A uniformly charged, straight filament 7.00 m in...Ch. 23 - You are working on a laboratory device that...Ch. 23 - Consider a long, cylindrical charge distribution...Ch. 23 - Assume the magnitude of the electric field on each...Ch. 23 - A solid sphere of radius 40.0 cm has a total...Ch. 23 - A cylindrical shell of radius 7.00 cm and length...Ch. 23 - You are working for the summer at a research...Ch. 23 - You are working for the summer at a research...Ch. 23 - Find the electric flux through the plane surface...Ch. 23 - Three solid plastic cylinders all have radius 2.50...Ch. 23 - A line of charge starts at x = +x0 and extends to...Ch. 23 - Show that the maximum magnitude Emax of the...Ch. 23 - A line of positive charge is formed into a...Ch. 23 - A very large conducting plate lying in the xy...Ch. 23 - A sphere of radius R = 1.00 m surrounds a particle...Ch. 23 - A sphere of radius R surrounds a particle with...Ch. 23 - A slab of insulating material has a nonuniform...Ch. 23 - A sphere of radius 2a is made of a nonconducting...Ch. 23 - An infinitely long insulating cylinder of radius R...Ch. 23 - A particle with charge Q is located on the axis of...Ch. 23 - Review. A slab of insulating material (infinite in...Ch. 23 - Identical thin rods of length 2a carry equal...Ch. 23 - A solid insulating sphere of radius R has a...
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- A circular loop of wire with a diameter of 0.626 m is rotated in a uniform electric field to a position where the electric flux through the loop is a maximum. At this position, the electric flux is 7.50 x 105 N-m²/C. Determine the magnitude of the electric field. O 2.44 × 106 N/C O 4.24 × 106 N/C O 1.07 x 106 N/C O 8.88 x 105 N/C O.6.00 x 106 N/C eTextbook and Mediaarrow_forwardFigure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m². The con- stant electric field É has mag- nitude 3.50 x 10% N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines pass through the curved surface. Calculate the electric flux through the cylinder's (a) top and (b) bottom surfaces. (c) Determine the amount of charge inside the cylinder. Figure P15.49arrow_forwardA uniform electric field of magnitude E = 38.5 N/C makes and angle of θ = 67.3° relative to a line normal to a surface with area A = 3.01 m2. What is the electric flux (Φ) that passes through this surface? Your answer should be in N·m2/Carrow_forward
- a circular surface with a radius of 0.061 m is exposed to a uniform electric field of magnitude 1.88E4 N/C. The electric flux through the surface is 77 Nm^2/C. What is the angle between the diraction of the electric field and the normal to the surfacearrow_forwardConsider the uniform electric field E = (3.5 jˆ + 3.5 kˆ) × 103 N/C. A) Calculate the electric flux through a circular area of radius 1.75 m that lies in the yz-plane. Give your answer in N·m2/C. B) Repeat the electric flux calculation for the circular area for the case when its area vector is directed at 45° above the x-axis (pointing in the direction of iˆ+kˆ). Give your answer in N·m2/C.arrow_forwardA circular surface with a radius of 0.066 m is exposed to a uniform electric field of magnitude 1.90 × 104 N/C. The electric flux through the surface is 52 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?arrow_forward
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Electric Fields: Crash Course Physics #26; Author: CrashCourse;https://www.youtube.com/watch?v=mdulzEfQXDE;License: Standard YouTube License, CC-BY