A lever is attached to a shaft with a square shear key as shown. The force applied to the lever is P = 400 N. If the shear stress in the key must not exceed 71 MPa, determine the minimum dimension "a" that must be used if the key is 19 mm long. 42 mm O 9.02 mm O 13.59 mm 8.24 mm ○ 7.03 mm ○ 9.88 mm Shear key 700 mm Shear key detail Current Attempt in Progress The rigid beam BC is supported by rods (1) and (2). The cross-sectional area of rod (1) is 7 mm². The cross-sectional area of rod (2) is 15 mm². For a uniformly distributed load of w = 4.1 kN/m, determine the length a so that the normal stress is the same in each rod. Assume L = 3.40 m. (1) B Answer: a = i L พ m (2)

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
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Author:Saeed Moaveni
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Chapter12: Electric Current And Related Variables In Engineering
Section12.2: Electrical Circuits And Components
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A lever is attached to a shaft with a square shear key as shown. The force applied to the lever is P = 400 N. If the shear stress in the key
must not exceed 71 MPa, determine the minimum dimension "a" that must be used if the key is 19 mm long.
42 mm
O 9.02 mm
O 13.59 mm
8.24 mm
○ 7.03 mm
○ 9.88 mm
Shear key
700 mm
Shear key detail
Transcribed Image Text:A lever is attached to a shaft with a square shear key as shown. The force applied to the lever is P = 400 N. If the shear stress in the key must not exceed 71 MPa, determine the minimum dimension "a" that must be used if the key is 19 mm long. 42 mm O 9.02 mm O 13.59 mm 8.24 mm ○ 7.03 mm ○ 9.88 mm Shear key 700 mm Shear key detail
Current Attempt in Progress
The rigid beam BC is supported by rods (1) and (2). The cross-sectional area of rod (1) is 7 mm². The cross-sectional area of rod (2) is 15
mm². For a uniformly distributed load of w = 4.1 kN/m, determine the length a so that the normal stress is the same in each rod.
Assume L = 3.40 m.
(1)
B
Answer: a =
i
L
พ
m
(2)
Transcribed Image Text:Current Attempt in Progress The rigid beam BC is supported by rods (1) and (2). The cross-sectional area of rod (1) is 7 mm². The cross-sectional area of rod (2) is 15 mm². For a uniformly distributed load of w = 4.1 kN/m, determine the length a so that the normal stress is the same in each rod. Assume L = 3.40 m. (1) B Answer: a = i L พ m (2)
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