5.6 Assume E constant and A zero for all members; calculate u, v, and 0 for joint a. Also calculate the distribution of internal forces. Why isn't the answer realistic? What is the shortcoming of the solution and how can it be corrected? What answers would one obtain to the same problem using moment distribution? What assumptions as to deformation are implicit in the moment distribution solution? 5.6 Assume E = constant and A = zero for all members; calculate u, v, and 0 forjoint a. Also calculate the distribution of internal forces. Why isn't the answer realistic?What is the shortcoming of the solution and how can it be corrected? What answerswould one obtain to the same problem using moment distribution? What assumptionsas to deformation are implicit in the moment distribution solution?I2L1bI1PmIL2LProblem 5.6Id

Answered: Image /qna-images/answer/fc8e2fd2-6d30-403d-aa48-c5d87d35f15f.jpg

5.6 Assume E = constant and A = zero for all members; calculate u, v, and 0 for joint a. Also calculate the distribution of internal forces. Why isn't the answer realistic? What is the shortcoming of the solution and how can it be corrected? What answers would one obtain to the same problem using moment distribution? What assumptions as to deformation are implicit in the moment distribution solution? I 2L 1b I 1 Pm I L 2L Problem 5.6 I d

5.6 Assume E = constant and A = zero for all members; calculate u, v, and 0 for joint a. Also calculate the distribution of internal forces. Why isn't the answer realistic? What is the shortcoming of the solution and how can it be corrected? What answers would one obtain to the same problem using moment distribution? What assumptions as to deformation are implicit in the moment distribution solution? I 2L 1b I 1 Pm I L 2L Problem 5.6 I d

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

1)
9. For this 2D truss problem, find a) The system stiffness matrix b) The displacements at each node c) The reaction forces d) The forces in each element e) The state of each element (tension or compression). The node numbers are given in blue squares 1 kN 1 kN 1 kN 0.25 m 1 kN 1 kN 0.25 m 10 0.2 m 11 12 0.2 m 0.25 m 0.25 m 0.25 m 0.25 m 0.2 m E = 13.1 GPa A = 5 mm x 5 mm
Problem 2
Determine the stiffness matrix of the given system and obtain the condensed stiffness matrix at the dynamic DOFs if the dynamic forces applied in-plane translational DOFs. All members are axially rigid. E=30000 MPa; I=8x10⁹ mm4; L= 4000 m. Hint: Evaluate the stiffness matrix applying the unit deformation metod as given example in the figure!!! m m m U3 U₂ U₁ mm. u₁=1 and urest=0 U4 U3 2m) U₂ EI, L (2m) U₁ 2EI, L
Displacement components at a point in a solid u(x, y,t) = 2y²x+2t v(x, y, t) = 8y'x + 5t2 w(x, y, t) = 3zy'x + 5xt² |3D a) the strain tensor, b) stress tensor c) Find out if the strain satisfies the fit equations?
Please solve part A
Truss problems
The cantilever beam has a steel cable of circular cross-section area at the end. What is the area of the cable’s cross section area if there is no observed deflection at point B? The modulus of elasticity of both beam and cable is 200GPa, and the beam is a steel section with I = 120 x 106 mm4 (Hint: recall axial deformations) USE THE DOUBLE INTEGRATION METHOD.
PROBLEM 1: The frame shown in the figure is carrying a traingular distributed load. Pins at A and B are forced in single shear while the pin at C is forced in double shear. If the allowable tensile stress of bar BC is 300 MPa and the allowable shear stress of pins is 150MP3; (a) The cross sectional area of BC (b) The required diameters of pins A, B and C as multiples of mm. w = 8 kN/m 6 m 5 m 3 m
Please show solution: thanks
The figure shown is the cross section of an endspan of a fully restrained beam that carries a moment of 200 kN-m. Determine the following: a. The centroid of the cross-section b. The moment of inertia of the cross-section. С. The bending stress on the extreme tension fiber. d. The compressive force due to bending. Check your answer using the force and moment checks. e. 100 mm, 90 mm 250 mm 100 mm, 90 mm 200 mm 110 mm 100 mm 100 mm 80 mm 70 mm 150 mm 260 mm 100 mm 150 mm 60 mm 50 mm 100 mm 100 mm 70 mm 80 mm
n= 8