2. A proposed road centerline to be constructed is shown below. The horizontal curve has aradius of 485.00', starts 1114.23' from the beginning of the new alignment(PCSTA=11+14.23), and ends 1500.34' from the beginning of the new alignment. Calculatethe curve data (L, I, T,NWoter Tower 24 from Edge of TrovelP.C. Sto11+14.23P.T.3. Use the same alignment as in Problem 2. Does the Water Tower obstruct the westbounddriver's sight distance from the PT to the PC? Assume 12 feet from the center line to edge oftravel. (Thus it is 30' (i.e. 12'/2 + 24') from the centerline of the inside lane to the edge ofthe water tower.)4. For this same curve, what would the acceptable posted speed / design speed (assume to bethe same) be to ensure stopping sight distance.

Answered: 2. A proposed road centerline to be…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Two straight roadways AB and BC intersect at B with a deviation angle of 12°00'00". They are to be joined by a circular curve of 500 m radius from A to C. The curve is to be set out at 20 m chainage intervals, from point A. Given that the chainage of point B is 842.750 m, calculate: the chainage points of the setting out pegs along the curve (set out clearly in a table); the tangential angles required to set out the curve from the initial tangent point in degrees (") minutes (') seconds (").
Assignment 3: Vertical Curve Design Question 2 The reduced level at the intersection of a rising gradient of P % and a falling gradient of Q % on a proposed road is XX.XX m. Given that K value is KK. The throught chainage of the intersection point is YYYY.YY m and proposed vertical curve is to have equal tangent. As a civil engineering you are required to prepare the following vertical curve design calculations: a) The through chainage of the points of the vertical curve if the minimum required length is to be used (Lv) and the vertical curve setting out data at 20 metres interval. b) The chainage and reduced level of the highest point on the curve. c) Through chainage at highest point was located exactly under a bridge, if the RL of soffit is SS.SS m, calculate the headroom based on proposed vertical curve design.
Determine the value VPc in m2 Determine the value of heigt in 1+1800 Determine the value Vp
Given broken line AB = 57.6 m., BC = 91,5 m. and CD = 91.5 m. arranged as shown. A reverse curve is to connect these three lines thus forming the center line of a new road. %3D a) Find the length of the common radius of the reverse curve, b) Find the total length of the reverse curve, CIf the P.C. is at Sta. 10+000, what are the stationing of P.R.C, and P.T. Solu tion: a) T, =Rtan 11 %3D T = R tan 32 T+T = 91.5 91.5 m R (tan 11 + tan 32 ) = 91.5 PT R = 111.688 m. 82 RI IR 7,5 7.5 64 56.7 G'16
solve example 1.4 please 1.3 example solved in my previous question of bartelby
This question about Transportation Engineering
Given: Stationing B= 18 + 685 Stationing C= 19 + 125 Tangent Lines: AB: Azim= 224° 24' BC: Azim= 264° 29' CD: Azim= 3150 28' A proposed highway curve is to connect these three tangents. Find: Radius of simple curve that connects these tangents. b. Sta PC. c. Length of the curve from PC to PT. a.
A property line AD instersects a simple curve at point B whose radius is 120 m. long. The azimuth of the propertyline is 300° while that back asimuth is 220°. A random line was run from the P.C. of the curve towards theproperty line which intersects at point A with an azimuth and distance of 190° and 42.50 m respectively.Compute the central angle of arc EB.provide a short solution and illustrate a free body diagram
clean and understandable solutions and box the final answers... Thank you
need to solve the question. engineering survey
Given an equal tangent vertical curve, in feet, with the following known information: • STA A (Beginning of Curve) = 13+00 o Elevation A = 220.00 feet • L= 900.0 feet G1 = -4.25% and G2 = +3.25% What is elevation of the low point on the curve, in feet? rrect Answer O 209.16 u Answered O 220.00 O 209.76 O 215.51
For a proposed highway curve with a radius of 500.00 meters, the point of curvature (PC) or beginning of curve station 10+00.00 and the point of tangency (PT) or end of curve station 14+00.00. The definition of station is 1 station = 100 meters. The CHORD length from the PC to the PT is %3! 1) 402.22 meters 2) 397.34 meters 3) none 4) 400.00 meters 5) 399.17 meters

SEE MORE QUESTIONS

Recommended textbooks for you

Structural Analysis

Civil Engineering

ISBN:

9781337630931

Author:

KASSIMALI, Aslam.

Publisher:

Cengage,

Structural Analysis (10th Edition)

Civil Engineering

ISBN:

9780134610672

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Principles of Foundation Engineering (MindTap Cou…

Civil Engineering

ISBN:

9781337705028

Author:

Braja M. Das, Nagaratnam Sivakugan

Publisher:

Cengage Learning

Structural Analysis

Civil Engineering

ISBN:

9781337630931

Author:

KASSIMALI, Aslam.

Publisher:

Cengage,

Structural Analysis (10th Edition)

Civil Engineering

ISBN:

9780134610672

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Principles of Foundation Engineering (MindTap Cou…

Civil Engineering

ISBN:

9781337705028

Author:

Braja M. Das, Nagaratnam Sivakugan

Publisher:

Cengage Learning

Fundamentals of Structural Analysis

Civil Engineering

ISBN:

9780073398006

Author:

Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel Lanning

Publisher:

McGraw-Hill Education

Sustainable Energy

Civil Engineering

ISBN:

9781337551663

Author:

DUNLAP, Richard A.

Publisher:

Cengage,

Traffic and Highway Engineering

Civil Engineering

ISBN:

9781305156241

Author:

Garber, Nicholas J.

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS