A bent tube is attached to a wall with brackets as shown.. A force of F = 980 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components →> parallel and perpendicular to the position vector FDA. Express each of these vectors in Cartesian components. 2013 Michael Swanbom BY NC SA g סוי B Z N< d A У каж FK b с Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value a. F = a 8 in b C 12 in 15 in d 36 in h 23 in g 28 in b. FDA = ( FLDA = ( ĵ+ + + k) lb k) lb k) lb

A bent tube is attached to a wall with brackets as shown.. A force of F = 980 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components →> parallel and perpendicular to the position vector FDA. Express each of these vectors in Cartesian components. 2013 Michael Swanbom BY NC SA g סוי B Z N< d A У каж FK b с Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value a. F = a 8 in b C 12 in 15 in d 36 in h 23 in g 28 in b. FDA = ( FLDA = ( ĵ+ + + k) lb k) lb k) lb

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)

5th Edition

ISBN:9781305084766

Author:Saeed Moaveni

Publisher:Saeed Moaveni

Chapter12: Electric Current And Related Variables In Engineering

Section12.2: Electrical Circuits And Components

Problem 6BYG

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