W= 9kN/m P= 60 kN a= 4m b=2m ++ 4b 4P P D E 9 P 25 2b F + a 2b Question 1 W = 9 kN/m P= 60.KN a=4m b = 2m i) Reactions at support A and B. Vertical force: Fy ot Ray + Roy 4P-46W= 0 RAY+RBY = 4P + 46W RAY + 46y = 4×60 + 4×2×9 RAY+RBY = 312 KN EM@AOA (4Pxa) + 4bWx (a + b/2) - 2a RBy = 0 960 + 72 x (4 + 2/2) - 8RBY = 0 -8RBY =- 1320 RBY = 165 kN upwards ↑ EM@BOA 4pa + 45W x (a + b/2) - 2a RBy = 0 2aRBY = 4bwx (a+b/2) + 4 Pa RBY = 4bwx (a+b/2) + 4 pa 29 RBy = bw (1+ b/a)+2p -Sub into RAY + RBY = 312 RAY + bw (1 +5/a) +2p₁ = 4P + 4bW RAY = 2P - bw x1-b/a) = RAY 111 KN
W= 9kN/m P= 60 kN a= 4m b=2m ++ 4b 4P P D E 9 P 25 2b F + a 2b Question 1 W = 9 kN/m P= 60.KN a=4m b = 2m i) Reactions at support A and B. Vertical force: Fy ot Ray + Roy 4P-46W= 0 RAY+RBY = 4P + 46W RAY + 46y = 4×60 + 4×2×9 RAY+RBY = 312 KN EM@AOA (4Pxa) + 4bWx (a + b/2) - 2a RBy = 0 960 + 72 x (4 + 2/2) - 8RBY = 0 -8RBY =- 1320 RBY = 165 kN upwards ↑ EM@BOA 4pa + 45W x (a + b/2) - 2a RBy = 0 2aRBY = 4bwx (a+b/2) + 4 Pa RBY = 4bwx (a+b/2) + 4 pa 29 RBy = bw (1+ b/a)+2p -Sub into RAY + RBY = 312 RAY + bw (1 +5/a) +2p₁ = 4P + 4bW RAY = 2P - bw x1-b/a) = RAY 111 KN
Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter8: Engineering Materials
Section: Chapter Questions
Problem 85CQ
Related questions
Question
For the three-pinned frame shown in picture i am trying to detemine the:
1. Determine the reactions at supports A and B.
2. Draw the shear force diagram for member AC.
3. Draw the bending moment diagram for member BFE.
4. Draw the axial force diagram for member CD.
5. Determine the maximum bending moment in member AC.
Detail answer with actual calculations and drawings please for better comprehension. I have tried to attempt this question multiple times, however if seems to be incorrect. I need help especially with question 4 find the N component..I will upvote, if answer is detailed Thank you
Transcribed Image Text:W= 9kN/m
P= 60 kN
a= 4m
b=2m
++
4b
4P
P
D
E
9
P
25
2b
F +
a
2b
Transcribed Image Text:Question 1
W = 9 kN/m
P= 60.KN
a=4m b = 2m
i) Reactions at support A and B.
Vertical force:
Fy ot
Ray + Roy
4P-46W= 0
RAY+RBY = 4P + 46W
RAY
+ 46y = 4×60 + 4×2×9
RAY+RBY
=
312 KN
EM@AOA
(4Pxa) + 4bWx (a + b/2) - 2a RBy = 0
960 + 72 x (4 + 2/2) - 8RBY = 0
-8RBY
=- 1320
RBY =
165 kN upwards ↑
EM@BOA
4pa + 45W x (a + b/2) - 2a RBy = 0
2aRBY
= 4bwx (a+b/2) + 4 Pa
RBY
=
4bwx (a+b/2) + 4 pa
29
RBy = bw (1+ b/a)+2p
-Sub into RAY + RBY = 312
RAY + bw (1 +5/a) +2p₁ = 4P + 4bW
RAY
=
2P
-
bw x1-b/a)
=
RAY 111 KN
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