A vertical parabolic curve is to be used as a sag curve, and it is desired to know thelocation and elevation of the low point. The curve is 750 ft long, and the minus grade of3.6 percent intersects a plus grade of 6.2 percent at station 240+80.00. Calculate the lowpoint of the curve if the intersection at station 240+80.00 is at elevation 426.84.

Answered: A vertical parabolic curve is to be…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

1. If PVI at sta 5+650 has an elevation of 122.45 m what is the elevation of the grade tangent at station 5+684? Given grade is +3%. 2. If a 26-degree curve consists of a 14 degree simple curve, what is the angle of the transition curves?
A symmetrical parabolic summit curve connects two grades of +4.9% and -3.2%. It is to pass through a point "D" on the curve at station 25 + 180m . If the stationing of the grade intersection is 25 + 145m and the stationing of PVC is 24 + 979m determine the following: Length of the parabolic curve Stationing of the highest point. Difference in elevation between PVC and PVI Difference in elevation between PVC and point D
A vertical parabolic curve is to be used under a grade-separation structure. The curve is 250 m long and the minus grade of 3.8 percent intersects the plus grade of 5.4 percent at station of 0+120.424. Calculate the low point of the curve if the intersection at station 0+120.424 is at elevation 230.085 m.
An equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?
A symmetrical parabolic commit curve connects two grades of +6% and -4%. It is to pass a point "A" on the curve at station 20+100 having an elevation of 98.134m. If the elevation of the grade intersection is 100m with stationing of 20+120. Evaluate the length of the vertical curve.
A vertical parabolic curve has a back tangent of -5% and a forward tangent of +3% intersecting at station 1 + 240 at an elevation of 100.00 m. If the stationing of P.C. is at 1 + 120. Evaluate the stationing of the lowest point in the curve. Evaluate the elevation of the lowest point in the curve. Evaluate the rate of change of grade of the sag curve per 20 m length.
A simple curve having a degree of curve equal to 3.8-degree has central angle of 55.5-degree. It is required to replace the simple curve to another circular curve by connecting a transition curve at each and by maintaining the radius of the old curve and the center of the new central curve is moved away by 6.8m from the intersection point. If the stationing at Pl is at 4 + 657.89, determine the stationing of the start of central curve.
A Vertical parabolic curve of length 180m has the following specifications. The point of interaction of grade lines is at station 4 + 316 and its elevation is 38m. The backwards tangent has a grade of -2.2% and the grade of the forward tangent is +3%. Under this conditions determine the following: (a) Station and elevation of PC & PT (b) Station of the lowest point of the curve (c) Elevation of the lowest point of the curve
Example: A grade g1 of -2% intersects g2 of +1.6% at a vertex whose station and elevation are 87+00 and 743.24, respectively. A 400' vertical curve is to be extended back from the vertex, and a 600’ vertical curve forward to closely fit ground conditions. Compute and tabulate the curve for stakeout at full stations.
A vertical parabolic curve has a back tangent of -5% and a forward tangent of +3% intersectingat station 1+240 at an elevation of 100.00m. If the stationing of PC is at 1+120,a.) Evaluate the stationing at the lowest point of the curve.b.) Evaluate the elevation of the lowest point in the curve. c.) Evaluate the grade at the first quarter point.
1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC and the PVI? [Answer: PVI station: 110+50.3; PVI elevation: 930.6']
A vertical parabolic curve is to be used as a grade-separation structure. The curve is 242 m long and the grade of -3.8% intersects the grade of +5.4% at station 0+120.424. Calculate the low point of the curve (location and elevation) if the intersection at station 0+120.424 is at elevation 230.425.

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