Problem 815 Find the moment at R2 and R3 of the continuous beam shown in Fig. P- 815. Solution 815 300 lb 300 lb 135 lb/ft MATHali MATHalin 4 ft R: 4 ft 4 ft' 10 ft 8 ft Rz R Figure P-815 ▾ Click here to expand or collapse this section Y 135 8 18 y = 60 lb/ft Ri 300 lb 300 lb 135 lb/ft MATHalino.com MATHаinc.com 4ft 4ft 4 ft 10 ft 8 ft R₂ Ra Moment under R3 M3 = (8y)|(8)]=-32y = -32 (60) M3 =-640 lb ft answer Solving for moment under R2 6A₁ā₁ 6A252 M1L1+2M2(L1 + L2) + M3L2 + + = 0 L1 L2 Where M₁ = 0 L₁ =3(4) 12 ft L2 = 10 ft 6A₁ā₁ Pa Στ (Ι? - ?) L₁ 6A₁ā₁ L1 12 300(4) (122-42)+ 300(8) (122 - 82) 12 6A₁ā₁ =28 800 lb ft² Li 6A252 8w,L³ 7yL³ + L2 60 60 6A252 8(135) (103) 7(60) (103) + L2 60 60 6A252 = 25 000 lb ft². L2 Thus, 6A₁ā₁ 6A252 M1L1+2M2(L1 + L2) + M3L2 + + = 0 L₁ L2 0+2M2 (12+ 10) - M2-1077.27 lb.ft 640(10) + 28 800 + 25 000 = 0 answer

Problem 815 Find the moment at R2 and R3 of the continuous beam shown in Fig. P- 815. Solution 815 300 lb 300 lb 135 lb/ft MATHali MATHalin 4 ft R: 4 ft 4 ft' 10 ft 8 ft Rz R Figure P-815 ▾ Click here to expand or collapse this section Y 135 8 18 y = 60 lb/ft Ri 300 lb 300 lb 135 lb/ft MATHalino.com MATHаinc.com 4ft 4ft 4 ft 10 ft 8 ft R₂ Ra Moment under R3 M3 = (8y)|(8)]=-32y = -32 (60) M3 =-640 lb ft answer Solving for moment under R2 6A₁ā₁ 6A252 M1L1+2M2(L1 + L2) + M3L2 + + = 0 L1 L2 Where M₁ = 0 L₁ =3(4) 12 ft L2 = 10 ft 6A₁ā₁ Pa Στ (Ι? - ?) L₁ 6A₁ā₁ L1 12 300(4) (122-42)+ 300(8) (122 - 82) 12 6A₁ā₁ =28 800 lb ft² Li 6A252 8w,L³ 7yL³ + L2 60 60 6A252 8(135) (103) 7(60) (103) + L2 60 60 6A252 = 25 000 lb ft². L2 Thus, 6A₁ā₁ 6A252 M1L1+2M2(L1 + L2) + M3L2 + + = 0 L₁ L2 0+2M2 (12+ 10) - M2-1077.27 lb.ft 640(10) + 28 800 + 25 000 = 0 answer

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

150 150 159 Q: Calculate the Nominal Strength for the beam shown. D00 f -40 MPa , f, - 400 MPa 250 %3D 600 4625 65 500
*2-92. Express each of the forces in Cartesian vector form and determine the magnitude and coordinate direction angles of the resultant force. 0.75 m FAS FAS = 250 N FAC = 400 N 3 m 40 2 m im- -1m- Ргob. 2-92
The length of the 2 mm diameter steel wire CD has been adjusted so that with no load applied, a gap of 2 mm exists between the end B of the rigid beam ACB and a contact point E. Knowing that E=200GPA, determine where a 20 kg block should be placed on the beam in order to cause contact between B and E. D 0.3 m | 20 kg 2 mm 0.3 m 0.1 m
Question 1. Specify the forces applied to the beams of the beam structure and the load patterns of the horizontal bar BDF. Question 2. Calculate the cutting force developed by the cutters shown in the picture, as well as the force applied to the hinge pin cutting force: (10kp = 100N)
Explain your answer Don't copy!!
3. The length of 2-mm diameter steel wire CD has been adjusted so that with no load applied, a gap of 1.5 mm exists between the end B of the rigid beam ACB and a contact point E. If E = 200 GPa, determine where a 20 kg block should be placed on the beam in order to cause contact between B and E. D X 0.25 m 20 kg A 1.5 mm C 0.08 m 0.32 m E
Determine the reactions and draw the shear and moment diagram of the indeterminate beam given below using Consistent Deformation Method. Consider the support reaction at point C to be the redundant. 50 k 50 k -8 tt 8n 8 it 21 Upload Choose a File
I'll give a thumbs up. Please help me
es A 4-m cantilever beam is loaded as shown. The cross section is formed with two concentric circles of radii 45 mm and 35 mm. If the allowable stress is 150 MPa, F Ra 1 X Y 12 Determine the section modulus of the beam. Select the correct response: 72113.831 mm³ 87833.695 mm³ 57962.384 mm3 45378.561 mm³ Ri 12
QUESTION: Can you please explain where did the "10" from 8/10 and 6/10 came from?
The beam in the figure below is fabricated by attaching a C180x14.6 channel to a W250x17.9 shape with 15-mm-dia rivets at uniform spacing "s". The maximum shear force in the beam is 65 kN. Given properties: CI80x14.6: A- 1850 mm^2; d- 178 mm; Kg 13.8 mm I, -0.405x106 mm^4; t. - 5.3 mm; t- 9.3 mm W250x17.9: A - 2270 mm 2; d - 251 mm; I, – 22.4x10°6 mm^4 ty - 4.8 mm; t- 5.3 mm CI80 x 14.6 W250 x 17.9 1. Calculate the moment of inertia of the built up section about the horizontal axis located 78.26 mm from the top. The answer is in x10°6 mm^4. A. 36,76 В. 22.80 C. 27.46 D. 31.06 2. Determine the strength (kN) of the connection within spacing "s" based on rivet shear if the working stress for a rivet is 100 MPa. A. 140 В. 35.34 C. 180 D. 200 3. Determine the shear flow "q" (N/mm) that must be sustained by the rivets A. 243.72 В. 172.39 C. 191.02 D. 211.84 Find the maximum allowable spacing (mm) of the rivets if the working. A. 140 4. В. 160 C. 180 D. 200 5. What is the corresponding…
need help - physics