a 69-lb force F is applied to the control pedal as shown. This force lies in a plane parallel to x-z plane and is perpendicular to BC. b a 15° F Given: a= 7.6 in b= 6.6 in c= 7.6 in
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what are the x,y, and z components for the moment about O
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- Consider the following coplanar system of tensile forces: F1 = 90 N at 180°, F2 = 150 N at 310° and Fy = 400 N at 0°. Use the counter clockwise direction as the positive direction of the angle from the positive x-axis. Provide the answers to 2 decimal places.Answer problem 3Springs OA and OB are originally unstretched in a vertical position. Find the horizontal force, F, when the springs are held in the position as shown, given: k = 550 lb/ft, L1 = 0.6 ft, L2 = 1.3 ft
- Kindly show the complete step-by-step solution. I hope the picture of the asnwer will be clear. Please see the attached photo for the given problem. I will rate you with “like/upvote” after if its clear and understandable.When activated by the force P,the gripper on a robotic arm is able to pick up objects by applying the gripping force F as shown in the figure below. Given that P = 120N,calculate the gripping force F in N for the position shown.Must solve all the parts of Problem 1.
- The force vector F has a magnitude of F = 385 lb and acts at point A at an angle 0 = 17.8° with respect to vertical as shown. The force F is balanced by the tension forces parallel to the two rods AC and AB such that the vector equation F+FAC+ FAB = 0 is satisfied. Determine the tension forces in the two rods in Cartesian components. C mintono cc) + Ⓡ BY NC SA 2013 Michael Swanbom Variable Value 4.6 ft 2.7 ft 4 ft a b C FAB F Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. FAC= a = For the component notation, use an 'xy' coordinate system with 'y' poining up and 'x' pointing to the right. î A + 0 + b B 3) lb 3) lbTwo forces are applied to a hook. Variable F₁₂ Ą a b FR= d FR=( Q= B. values for the figure are given in the following table. Note the figure may not be to scale. value 75 lb 35 lb 2.5 ft B= Y = 4.5 ft 9 ft 1 ft Z a. write each force (F₁,F) as cartesian vectors. b. Find the resultant force FR express as a cartesian vector c. Find the magnitude of the resultant force FR i. a ii. B iii. Y Round your final answers to 3 significant digits/figures. Submit Question → d. Determine the coordinate direction angles of the resultant force FR lb 13/12 a degrees F₂ degrees F₁ degrees A A) lb y e) lb AlbAn eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F1=200 lbf, F2=250 lbf, and F3=100 lbf with 0 = 30 degrees and p=24.1 degrees. If the eye bolt is in equilibrium, what is the x-component of the sum of other forces on the bolt (force from the nut and plate on the bolt) ? If you add up the three force vectors, the sum other force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The x-direction is positive to the right. For example, if you find the sum of forces 1, 2, and 3 are 100 Ibf to the right, then the other forces in the x-direction must be pointing to the left (-100 lbf) to put the eye bolt in equilibrium. Eye bolt 2steel 3 plate Nut t Wonsher
- do itFL y b C Z Determine the moment about O due to the force F shown, the magnitude of the force F = 76.0 lbs. Note: Pay attention to the axis. Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.90 ft b 2.80 ft с 2.60 ft d 2.30 ft Mo 144 ft-lb = -212 × 1 + xk) ☑+2123m Find the rectangular representation of the force F, given that its magnitude 240 N. * F = -135.76 i+ 169.71 j– 101.82 k F = 135.76 i + 169.71 j+ 101.82 k F = 135.76 i - 169.71 j+ 101.82 k F = -135.76i+ 169.71 j+ 101.82 k