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- The rectangular framework is subjected to the following non-concurrent system of forces: a 30lb- force below the origin, a 20 lb-force,3ft above the origin and making an angle of30°N of E, a 100lb-force with a horizontal distance of 3ft and a vertical distance of 4ftfrom the origin and making an angle of 45°NW , a 60lb -force with the same distance like the previous force but along the positive x-axis, and a 100lb- force 4ft tothe right of the origin and making an angle of 60° S of W . Determine the magnitude and direction of the resultant, as well as its moment arm relative to the origin.Consider the following coplanar system of tensile forces: F1 = 90 N at 180°, F2 = 150 N at 310° and Fy = 400 N at 0°. Use the counter clockwise direction as the positive direction of the angle from the positive x-axis. Provide the answers to 2 decimal places.5
- 2:04 Laz ו 59% ב Statics assignment 1.pub soln.pdf Problem Number 3: The block shown in the figure below is acted on by its weight, W = 650 KN, a horizontal force H = 450 KN., and the pressure P exerted by the inclined plane. The resultant R of these forces is parallel to the incline. Determine the Forces P and R. Does the block move up or down the incline? Y-axis W = 650 KN P = ? X axis H = 450 KN H=450 KN 35° 40° P= ? W=650 Forces X- Component Y- Component W = 650 KN Wx = -650sin 35 Wy = -650 cos 35 -372.824 -532.449 H = 450 KN Hx = 450 cos 35 Hy = - 450 sin 35 368.618 - 258.109 P = ? Px = - P sin 5 Py = P cos 5 S Rx =R 0.000 PREVIOUS 3/3 NEXT IIPlease within 20minutes. UrgentKindly show the complete step-by-step solution. I hope the picture of the asnwer will be clear. Please see the attached photo for the given problem. I will rate you with “like/upvote” after if its clear and understandable.
- Finding the bar forces by the nodal point methodThe force system acting on the machine part is equivalent to the single force R = 475 i + 50 j acting at O. What is the value of the y-component of P? y P 1500 N+ 240 mm 300 N 30° 120 mm 1000 NProblem 8: Values: d₁ = 6.5 ft d₂ = 2.75 ft Force in cable AB = 475 lb Use the dot product to determine the following: a) The magnitude of the force projected along the axis of the pipe (axis AC) b) The angle between the cable and the axis of the pipe (axis AC) d₂ d₂ N d₂ 8 B d₁ A