eter rule is anchored at the point O and is ough O and perpendicular to the plane of of equal magnitudes act on the ruler at diff te is 24.0 N and 0 =30°. The distances alon ntities are correct to 3 significant figures.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question

Please help with the last part of (f). It is not 0.600.

A meter rule is anchored at the point O and is free to rotate about an axis passing through O and perpendicular to the plane of the meter rule. Forces \( F_1, F_2, F_3, F_4 \), and \( F_5 \) of equal magnitudes act on the ruler at different locations. The magnitude of each force is \( 24.0 \, \text{N} \) and \( \theta = 30^\circ \). The distances along the ruler are given in cm. Assume all quantities are correct to 3 significant figures.

### Diagram Explanation:
The diagram depicts a horizontal meter rule anchored at one end, O. Five forces are applied at different points along the ruler:

- \( F_1 \) acts vertically downward at O.
- \( F_2 \) and \( F_3 \) act at 30 cm and 60 cm from O, both inclined at angle θ downwards.
- \( F_4 \) acts vertically downward at 60 cm from O.
- \( F_5 \) acts horizontally at 100 cm from O.

### Analysis and Calculations:

(a) **Determine rotational effect of each force:**
- \( F_1 \): No rotation because it is on the pivot point.
- \( F_2 \): Yes, it can rotate the ruler.
- \( F_3 \): Yes, it can rotate the ruler.
- \( F_4 \): Yes, it can rotate the ruler.
- \( F_5 \): No rotation because the force is horizontal at a distance.

(b) **Comparing torques \( F_3 \) and \( F_4 \):** 
- \( F_3 \) produces a larger torque because it is perpendicular.

(c) **Calculate torques \( T_{F_3} \) and \( T_{F_4} \):** 
- \( T_{F_3} = -14.4 \, \text{Nm} \) (negative for clockwise)
- \( T_{F_4} = -12.5 \, \text{Nm} \) (negative for clockwise)

(d) **Comparing torques \( F_2 \) and \( F_4 \):**
- \( F_4 \) produces the larger torque because it has a larger moment arm.

(e) **Calculate torque \( T_{F_2} \):**
Transcribed Image Text:A meter rule is anchored at the point O and is free to rotate about an axis passing through O and perpendicular to the plane of the meter rule. Forces \( F_1, F_2, F_3, F_4 \), and \( F_5 \) of equal magnitudes act on the ruler at different locations. The magnitude of each force is \( 24.0 \, \text{N} \) and \( \theta = 30^\circ \). The distances along the ruler are given in cm. Assume all quantities are correct to 3 significant figures. ### Diagram Explanation: The diagram depicts a horizontal meter rule anchored at one end, O. Five forces are applied at different points along the ruler: - \( F_1 \) acts vertically downward at O. - \( F_2 \) and \( F_3 \) act at 30 cm and 60 cm from O, both inclined at angle θ downwards. - \( F_4 \) acts vertically downward at 60 cm from O. - \( F_5 \) acts horizontally at 100 cm from O. ### Analysis and Calculations: (a) **Determine rotational effect of each force:** - \( F_1 \): No rotation because it is on the pivot point. - \( F_2 \): Yes, it can rotate the ruler. - \( F_3 \): Yes, it can rotate the ruler. - \( F_4 \): Yes, it can rotate the ruler. - \( F_5 \): No rotation because the force is horizontal at a distance. (b) **Comparing torques \( F_3 \) and \( F_4 \):** - \( F_3 \) produces a larger torque because it is perpendicular. (c) **Calculate torques \( T_{F_3} \) and \( T_{F_4} \):** - \( T_{F_3} = -14.4 \, \text{Nm} \) (negative for clockwise) - \( T_{F_4} = -12.5 \, \text{Nm} \) (negative for clockwise) (d) **Comparing torques \( F_2 \) and \( F_4 \):** - \( F_4 \) produces the larger torque because it has a larger moment arm. (e) **Calculate torque \( T_{F_2} \):**
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Knowledge Booster
Design of Permanent Joints
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY