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eter rule is anchored at the point O and is ough O and perpendicular to the plane of of equal magnitudes act on the ruler at diff te is 24.0 N and 0 =30°. The distances alon ntities are correct to 3 significant figures.

eter rule is anchored at the point O and is ough O and perpendicular to the plane of of equal magnitudes act on the ruler at diff te is 24.0 N and 0 =30°. The distances alon ntities are correct to 3 significant figures.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Please help with the last part of (f). It is not 0.600.

A meter rule is anchored at the point O and is free to rotate about an axis passing through O and perpendicular to the plane of the meter rule. Forces \( F_1, F_2, F_3, F_4 \), and \( F_5 \) of equal magnitudes act on the ruler at different locations. The magnitude of each force is \( 24.0 \, \text{N} \) and \( \theta = 30^\circ \). The distances along the ruler are given in cm. Assume all quantities are correct to 3 significant figures. ### Diagram Explanation: The diagram depicts a horizontal meter rule anchored at one end, O. Five forces are applied at different points along the ruler: - \( F_1 \) acts vertically downward at O. - \( F_2 \) and \( F_3 \) act at 30 cm and 60 cm from O, both inclined at angle θ downwards. - \( F_4 \) acts vertically downward at 60 cm from O. - \( F_5 \) acts horizontally at 100 cm from O. ### Analysis and Calculations: (a) **Determine rotational effect of each force:** - \( F_1 \): No rotation because it is on the pivot point. - \( F_2 \): Yes, it can rotate the ruler. - \( F_3 \): Yes, it can rotate the ruler. - \( F_4 \): Yes, it can rotate the ruler. - \( F_5 \): No rotation because the force is horizontal at a distance. (b) **Comparing torques \( F_3 \) and \( F_4 \):** - \( F_3 \) produces a larger torque because it is perpendicular. (c) **Calculate torques \( T_{F_3} \) and \( T_{F_4} \):** - \( T_{F_3} = -14.4 \, \text{Nm} \) (negative for clockwise) - \( T_{F_4} = -12.5 \, \text{Nm} \) (negative for clockwise) (d) **Comparing torques \( F_2 \) and \( F_4 \):** - \( F_4 \) produces the larger torque because it has a larger moment arm. (e) **Calculate torque \( T_{F_2} \):**
Transcribed Image Text:A meter rule is anchored at the point O and is free to rotate about an axis passing through O and perpendicular to the plane of the meter rule. Forces \( F_1, F_2, F_3, F_4 \), and \( F_5 \) of equal magnitudes act on the ruler at different locations. The magnitude of each force is \( 24.0 \, \text{N} \) and \( \theta = 30^\circ \). The distances along the ruler are given in cm. Assume all quantities are correct to 3 significant figures. ### Diagram Explanation: The diagram depicts a horizontal meter rule anchored at one end, O. Five forces are applied at different points along the ruler: - \( F_1 \) acts vertically downward at O. - \( F_2 \) and \( F_3 \) act at 30 cm and 60 cm from O, both inclined at angle θ downwards. - \( F_4 \) acts vertically downward at 60 cm from O. - \( F_5 \) acts horizontally at 100 cm from O. ### Analysis and Calculations: (a) **Determine rotational effect of each force:** - \( F_1 \): No rotation because it is on the pivot point. - \( F_2 \): Yes, it can rotate the ruler. - \( F_3 \): Yes, it can rotate the ruler. - \( F_4 \): Yes, it can rotate the ruler. - \( F_5 \): No rotation because the force is horizontal at a distance. (b) **Comparing torques \( F_3 \) and \( F_4 \):** - \( F_3 \) produces a larger torque because it is perpendicular. (c) **Calculate torques \( T_{F_3} \) and \( T_{F_4} \):** - \( T_{F_3} = -14.4 \, \text{Nm} \) (negative for clockwise) - \( T_{F_4} = -12.5 \, \text{Nm} \) (negative for clockwise) (d) **Comparing torques \( F_2 \) and \( F_4 \):** - \( F_4 \) produces the larger torque because it has a larger moment arm. (e) **Calculate torque \( T_{F_2} \):**
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