4 ft A 4 ft W 60° B 4 ft C Р E
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The wall crane supports a load P = 500 lb. The jib ABC has a weight of 90 lb and member BD has a weight of 35 lb. Each member is uniform and has a center of gravity at its center. Determine the following:
[9] Reaction at pin A (Answer: 1532.847 lb) and the resultant force at pulley B (Answer: 250.000 lb)
[10] Force in the cable at winch W (Answer: 250.000 lb) and the horizontal component of the reaction at pin D (Answer: 1324.006 lb)
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- Identify the equations that go with these concepts: Conservation of Energy (for conservative forces) b. Work-Energy Principle C. Force of gravity for an object near the surface of the Earth Force of gravity for an object far from the surface of the Earth d. T1+ V1 = T2+ V2 T1 + U1->2= T2 F = mg F= (GMm)/r^2The 7-kg sphere is projected horizontally with a velocity of 14 m/s against the 40-kg carriage which is backed up by the spring with stiffness of 1390 N/m. The carriage is initially at rest with the spring uncompressed. If the coefficient of restitution is 0.69, calculate the rebound velocity v', the rebound angle 8, and the maximum travel o of the carriage after impact. 7 kg Answers: 14 m/s k= 1390 N/m. 55⁰ 40 kgtion 4 If the perpendicular force of 1000 N, acting on a surface of area, 0.05 m^2, calculate the pressure on the surface 20000 Pa 1000 Pa C300 Pa 50 Pa Ouestion 5
- 1-The magnitude of N2 (normal force on Surface-2) is _____N 2-The magnitude of F2 (friction force on Surface-2) is _____N. 3- Consider the FBD of the Wedge: The direction of N2 (normal force on Surface-2) is _____degrees. Please need help. use that fig to respond to questions 1, 2, 380 lb/ft В - 5 ft – 2-5 5 ft A 60 lb/ft 12 ftConverting units how many required in the question shown in the picture below
- 74. A 65-kg swimmer pushes on the pool wall and accelerates at 6 m/s. The friction experienced by the swimmer is 100N. What is the magnitude of the force that the swimmer applies on the wall?" - 490 N 490 N O 290 N O : 290 NThe figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 3 4 PV = constant %3D Heat IN Adiabatic expansion 2 Heat OUT (Constant volume heat rejection) Constant volume heat addition 1 Adiabatic compression Volume (V) Using the Dual Air Standard Cycle and the following data: • Assume constant properties of air. R= 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK; y = 1.4 • Cycle compression ratio = 14 (V1/v2) • Air conditions prior to compression: Pressure = 1.3 bar; Temperature = 293K • Heat added at constant volume = 280000 J/kg • Heat added at constant pressure = 662000 J/kg Pressure (P)What form of energy from the list below is an extensive system property (choose all what apply) total energy of a system potential energy kinetic energy O internal energy
- In the Figure shown, find the Pressure difference between A and B. Given: Specific Gravity of Oil, SGoil = 0.85, Specific Gravity of Mercury, SGmercury = 13.6, Specific Gravity of Kerosene, SGkerosene = 0.81, Specific Weight of Water, Ywater= 9790 N/m², Specific Weight of Air, yair = Also, hi = 20.0 cm, h2 = 14.0 cm, h3 = 10.0 cm, h4= 8.0 cm, h5 = 4.0 cm. 12 N/m³. Show all calculations. Kerosene Air IB A oil hay hi Water Mercuryr= 2.20 ft F has a mgnitude of 570 lb (F=570 lb)2- The area of piston 1 is 15 times smaller than the area of piston 2. If you want to lift the car 1ft, how much you should push down piston 1? F2 = P2A2 F = P\A| A1 (1) Pi A2- P2