The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water 175 g |3D Can you find: mwater =? g Twater = Tatum 20°C (water and cup of room temperature) Teyl = 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) kCal Catum = 0.22, Cwater = 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul · How we find it? Plug all the numbers into the equation (1), Ccul will be one
The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water 175 g |3D Can you find: mwater =? g Twater = Tatum 20°C (water and cup of room temperature) Teyl = 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) kCal Catum = 0.22, Cwater = 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul · How we find it? Plug all the numbers into the equation (1), Ccul will be one
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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
Transcribed Image Text:The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right
side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm
up. Because it is the same energy, they are equal.
What is known in this equation?
Mcyl
411.7 g, malum
46.5 g, malum+water
= 175 g
Can you find: mwater =? g
Twater = Talum = 20°C (water and cup of room temperature)
90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures)
Tcyl
kCal
Calum = 0.22, Cwater
1 (specific heat of water and aluminum, measured in units
kg-°C
What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one
unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms!
After
you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper).
|Ceyl -0.093|
% :
· 100%
0.093
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