For the slider-crank linkage shown, write the appropriate vector equations and solve them using vector polygons determining: (a) vc (b) @3 (c) the velocity of the midpoint of link 3. A OB 5" 8" 2 α2=0 @2= 10 rad/s A+ 45° 3 C 04 1 Position Diagram (scale: 1 in = 1 cm) X0° Velocity Polygon (scale: 10 in/s = 1 cm)
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- The general linkage configuration and terminology for an offset fourbar slider-crank linkage are shown in Figure below. The link lengths and the values of 02 and w2 are defined in. For the row(s) b and c, find the velocities of the pin joints A and B and the velocity of slip at the sliding joint using an analytical method. Draw the linkage to scale and label it before setting up the equations. y A 03 B Y 4 Link 3 A W2 Offset 02 04 = 90° Link 2 X 02 Slider position d TABLE P6-2 Data for Problems 6-6 to 6-7† Row Link 2 Link 3 Offset 02 02 a 1.4 4 1 45 10 2 -3 60 -12 3 8 2 -30 -15The general linkage configuration and terminology for an offset fourbar slider-crank linkage are shown in Figure below. The link lengths and the values of 02 and w2 are defined in. For the row(s) b and c, find the velocities of the pin joints A and B and the velocity of slip at the sliding joint using an analytical method. Draw the linkage to scale and label it before setting up the equations. Link 3 Offset 04 = 90° Link 2 02 Slider position d TABLE P6-2 Data for Problems 6-6 to 6-7† Row Link 2 Link 3 Offset 02 1.4 4 1. 45 10 2 6. -3 60 -12 3 8. -30 -15Find the velocity of point B and angular velocity in link 3 using relative analysis and polygon method. Note the drawing is not in scale. B 02 @2=1 rad/s 2 30° A 1 3 4 04 02A=4" AB=7" 0204-=9" 04B=8"
- 1 of 1 3. A four-bar linkage is shown below. (A) the directions of each. (B) E on link 3. Use the method of velocity vector polygons to calculate w, and wq. Report Find and report the magnitude and direction of the absolute velocity of point RAD = 10 cm, Rap = 15 cm, Ra = 60 cm; R = 65 cm; Rp = 15 cm W2 = 2 rad/s cw (Note: ADB and FEC are right triangles.) link 3 A. link 2I want a detailed explanation of the two areas marked in red. Firstly, why + and - became in derivation all - Secondly, why did we put it above C dot and why did we delete a? I want an explanation about this derivation with a detailed explanation of its drawing, please.5. The figure shows a scaled kinematic diagram of a linkage. The velocity magnitude of joint A is 10 in/s and its direction is as shown in the figure. Find the velocity magnitude of joint B using the instant center method. AC= 1.95" AD = 2.0" V42 DE = 1.1" BD = 0.9" BE = 1.9" A B 3 2 C (3.35", 0.3") E Rectangular Snip 1.0"-
- Figure out the 2D sketch of housing using AutoCAD and mention all the dimensions. Colour the hatched lines which are inside the curve (red) 37 30 14 R 2 holes 72 Dia 12R 60R 30 R 24 10 R 15R Housing 60 Ractuating limb angular position is given as 812= 60° and the speed of the mechanism is given as é12= 50 rad/s. Do the following operations respectively. Kinematic diagram and limb dimensions are given below, in the arm slide mechanism, the a-Write the Vector Closure Equation into scalar form. b-Find S13, 014 by position analysis. C-Find Sı3Ö14 by analyzing velocity. A9A = r2 = 0.2 m A,Bo = r = 0.5 m 012 = 60° 012 = 50 rad/s S13 014 Bo 012 ri A0theta O = 55 The link length and value of O2 for some four bar linkage are defined below, (drive link =4.2 cm , coupler link =5.9 cm , follower link = 5.9 cm, fixed link= 6.85 cm 1. draw the linkage to scale and graphically find all possible solution (both open and cross) for 03 and O4 2. If w = 2 rad /s (CCW) find the angular velocity for bar 3 and 4 3.if a= 5 rad/s? (Ccw) find the normal and tangential acceleration for link 3 and 4
- A‚A = r2 = 0.2 m ABo = rị = 0.5 m = 60° Kinematic diagram, the limb dimensions are given below, the drive link in the arm slide mechanism angular position 012 = 600 and the speed of the mechanism is constant 0 12 = as 50 rad /s 012 12 = 50 rad/s are given. Do the following operations respectively. a- Write the Vector Closure Equation and bring it into scalar %3D form. AO b- Find S13, 014 Konum by doing position analysis. c- Analyzing speed S13, 014 S13 Find 014 Bo 012 AoEXAMPLE TL ROBOT - In a TL robot, assume that the origin of global coordinate system is at J2 · Determine the coordinate of the ef point if the joint twist by an angle of 30 degrees and the variable length is Im. · Determine the variable link length and angle twist if the ef is located at (0.7071,0.7071) J2(X2. Y2) Ean + (x, y) Jq(X1, Y1)The general linkage configuration and terminology for an offset fourbar slider- crank linkage are shown in the figure. The link lengths and the values of d, d.d and d..d are defined in the table. For row a, using graphical method, the value the acceleration of pin joint A is Row la b C d le If g 02 002 Link 2 1.4 2 3 3.5 5 3 0₂ Y Link 2 O 792.064 in/sec2 0₂ 291.385 in/sec2 O 1,593 in/sec2 O 1,779 in/sec2 Link 3 14 16 18 10 20 13 25 Link 3 Offset 1 -3 2 1 -5 10 10 Offset 03 Slider position d, d, d d 2.5 5 8 -8 15 -12 25 y B d.d d..d 10 -12 15 -15 -10 24 -4 -50 10 -45 50 100 18 04 = 90° 10 X