Need help with this. If dot product is required please should and explain it Determine the resultant moment (in Cartesian vector form) of the forces about point O. Also the moment'smagnitude, and direction angles.(ANS: (301-40) + 60k) lb ft, 78.1 lb ft, 67.4, 121, 39.8°)F,-1-601 +40j + 20k] lbAF,- (50j] lb2 ft4 ftB5 It(F,- (801 +40j - 30k) lb

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Answered: Determine the resultant moment (in…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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F1 F2 ba C F3 A B d. b F4 Consider the following values: - F5 a = 7 m; b = 3 m; c = 7 m; d = 3 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30° e = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 90.8 kN.m b) 72.7 kN.m c) 14.6 kN.m d) 55.9 kN.m e) 21.6 kN.m f) 61.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 77.8 kN.m b) 25.7 kN.m c) 38.6 kN.m d) 18.9 kN.m e) 37.9 kN.m f) 84.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 35.7 kN.m b) 21.1 kN.m c) 714.6 kN.m d) 69.1 kN.m e) 51.4 kN.m f) 85.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 17.8 kN.m b) 55.7 kN.m c) 44.6 kN.m d) 18.9 kN.m e) 21.5 kN.m f) 30.1 kN.m 5] What is the moment of the force F2 about point E? a) 81.7 kN.m b) 78.1 kN.m c) 64.6 kN.m d) 73.1 kN.m e) 54.6 kN.m f) 61.3 kN.m
Consider the frame below with F = 550 N. 0.3 m F 0.3 m 0 100 N 0.4 m -200 N Determine the magnitude of the resultant moment about point O. Provide your answer in Nm to 4 decimal places. Magnitude of the resultant moment about point 0 [Nm] =
pleassssse solve question 6, statics
a) Express F1, F2, and F3 in Cartesian form.b) Find the resultant moment about point A using the scalar method.c) Find the resultant moment about point B using the vector method. Express your answer in Cartesian form
pleassssse solve question 5, statics
Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35° and 02 = 03 = 20°. Calculate the moment that the force, F, exerts about the point A. F B 02 O3 A
5.) If the resultant force (single equivalent force) of the given system is known to pass through point B, what must the magnitude of the applied moment couple M be? Report a positive answer if M must be counterclockwise and a negative answer if M must be clockwise. [Answer: M = -8600 N m] 650 N 30° M -3 m 300 N -5 m- 500 N Ka -2 m- B
F1 F2 a F3 A F4 F5 Consider the following values: - a = 25 m; b = F1 = 7 kN; F2 = 8 kN; F3 = 9 kN; F4 = 10 kN; F5 = 11 kN; 5 m; c 25 m; d =5 m; a = 30° , 8 = 60° , B = 30° Tor a) ou. . 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 117.8 kN.m b) 82.7 kN.m c) 121.9 kN.m d) - 259.9 kN.m e) 127.1 kN.m f) 300.1 kN.m Activate 5] What is the moment of the force F2 about point E? a) 151.7 kN.m b) 118.1 kN.m c) 214.6 kN.m d) 158.6 kN.m e) 101.1 kN.m bo
195 and 745 are separately answered. I am not sure these are correct. please do this carefully.
Need only a handwritten solution only (not a typed one).
Determine the moment (in kip-ft)about point A of each of the three forces acting on the beam. Consider the counterclockwise direction to be positive moment, if F1=300 lb, F2=500 lb, F3= 200 Ib. [ Select ] (MF1)A, (MF2)A, (MF3)A = [ Select ] kip-ft [ Select ] F1 F2 4 0.5 ft 8 ft 6 ft 5 ft- 30°
The moment of the force F=120 lb about the point O in Cartesian vector form is. F= 120 lb 1 ft 4 ft 2 ft 4 ft Select one: O a. Mo = 200j – 400k O b. Mo = -2007 + 400k O c. Mo = -2007j – 400k O d. Mo = 200j + 400k EN

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Determine the resultant moment (in Cartesian vector form) of the forces about point O. Also the moment's magnitude, and direction angles. (ANS: (301-40) + 60k) lb ft, 78.1 lb ft, 67.4, 121, 39.8°) F,-1-601 +40j + 20k] lb A F,- (50j] lb 2 ft 4 ft B 5 It (F,- (801 +40j - 30k) lb