5' CCTAGCTTTCCGATAAAGCTATTCAAGT 3' The Alu1 enzyme cuts at this sequence: 5' AGCT 3' sequence. How many DNA fragments will you get within the sequence above? One Two Three None
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- Given: BamHI, cleaves after the first G: 5’ G GATCC 3’ 3’ CCTAG G 5’ AND BclI cleaves after the first T: 5’ T GATCA 3’ 3’ ACTAG T 5’ THEN -- Given the DNA shown below: 5’ATTGAGGATCCGTAATGTGTCCTGATCACGCTCCACG3’ 3’TAACTCCTAGGCATTACACAGGACTAGTGCGAGGTGC5’ i) If this DNA was cut with BamHI, how many DNA fragments would you expect? ii) If the DNA shown above was cut with the enzyme BclI, how many DNA fragment would you expect?What would be the percentage of G, C, A, and T in each column? Have to calculate the nucleotide frequency from my sequence.This is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: top strand is the coding strand). 5'-AACGCATGAGAAAGCCCCCCGGAAGATCACCTTCCGGGGGCTTTATATAATTAGC-3' 3'-TTGCGTACTCTTTCGGGGGGCCTTCTAGTGGAAGGCCCCCGAAATATATTAATCG-5' (i) Draw the structure of hairpin loop that will be formed during the end of transcription. (ii) Describe the function of the hairpin loop during transcription.
- In the following gel showing stained bands of the Alu insertion sequence, what is the genotype of individual 2? 941 bp 641 bp->>> 1 2 3 4 5 6 Homozygous for the 641 bp sequence that does not contain in the Alu insertion Heterozygous, containing one 941 bp sequence and one 641 bp sequence O Homozygous for the 941 bp sequence containing the Alu insertionGiven the template DNA strand 3’-TACCCTCAAGGGCAAACT-5’, provide the complimentary DNA strand, mRNA, tRNA, and protein using the figure that will post here5’-GATCAGCTGACTGGATCCGTCCTCAACGTCAGGATCCAGCTTCAAG-3’ 1. How many cuts do you expect this enzyme to make on the above DNA and how many fragments do you expect to see on your gel? Assume that they are all different sizes.
- 5’ TAAGCGTAACCCGCTAA CGTATGCGAAC GGGTCCTATTAACGCAC 3’ 3’ ATTCGCATTGGGCGATT GCATACGCTTG CCCAGGATAATTGCGTG 5’ Imagine that the double-stranded DNA molecule shown above was broken at the sites indicated by spaces in the sequence and that before the breaks were repaired the DNA fragment between the breaks was reversed. What would be the base sequence of the repaired molecule? Show the sequence, label the 5’ and 3’ ends and briefly explain the reasoning supporting your answerBM4_DNA AND PROTEIN S X /1FAIPQLSDP_g5B-629FSHNpGnTMIEppLS4A71zBd4vcUBqNUILubXONw/formResponse 4. What is the nitrogen base pair of Adenine in transcription? O Cytosine O Uracil O guanine O thymine 5. The central dogma of Molecular Biology states that There are four nitrogen bases in DNA, two purines (adenine and guanine) and two pyrimidines (cytosine and thymine). Which process is not included in the central dogma? duplication transcription translation O translocation LeadpleThis is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: top strand is the coding strand). 5'-AACGCATGAGAAAGCCCCCCGGAAGATCACCTTCCGGGGGCTTTATATAATTAGC-3' 3'-TTGCGTACTCTTTCGGGGGGCCTTCTAGTGGAAGGCCCCCGAAATATATTAATCG-5' Draw the structure of hairpin loop that will be formed during the end of transcription.
- Numbering the fragments left by cutting the DNA with BAM HI from left to right, which fragment will travel the furthest? BAM HI: GGATCC CCTAGG AATCGGATCCATTTGGACTAAAGGACCCGGATTGGATCCAGGGCCTTTAGTACC TTAGCCTAGGTAAACCTGATTTCCTGGGCCTAACCTAGGTCCCGGAAATCATGG O 3 O 2 4. 1.Here is a DNA coding strand’s sequence and direction: 5’-ATGCCGATATAG-3’ . What would be the amino acid sequence in the polypeptide encoded by this DNA?1. AsnIleGlyTyrGluProSerArgAsp 2. MetPheAsnSerGluProLysCys 3. SerArgGluTyrValValThrPheGly 4. MetPheSerThrAspGluVal