5' CCTAGCTTTCCGATAAAGCTATTCAAGT 3' The Alu1 enzyme cuts at this sequence: 5' AGCT 3' sequence. How many DNA fragments will you get within the sequence above? One Two Three None
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- What would be the percentage of G, C, A, and T in each column? Have to calculate the nucleotide frequency from my sequence.In the following gel showing stained bands of the Alu insertion sequence, what is the genotype of individual 2? 941 bp 641 bp->>> 1 2 3 4 5 6 Homozygous for the 641 bp sequence that does not contain in the Alu insertion Heterozygous, containing one 941 bp sequence and one 641 bp sequence O Homozygous for the 941 bp sequence containing the Alu insertionGiven the template DNA strand 3’-TACCCTCAAGGGCAAACT-5’, provide the complimentary DNA strand, mRNA, tRNA, and protein using the figure that will post here
- 5’ TAAGCGTAACCCGCTAA CGTATGCGAAC GGGTCCTATTAACGCAC 3’ 3’ ATTCGCATTGGGCGATT GCATACGCTTG CCCAGGATAATTGCGTG 5’ Imagine that the double-stranded DNA molecule shown above was broken at the sites indicated by spaces in the sequence and that before the breaks were repaired the DNA fragment between the breaks was reversed. What would be the base sequence of the repaired molecule? Show the sequence, label the 5’ and 3’ ends and briefly explain the reasoning supporting your answerThis is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: top strand is the coding strand). 5'-AACGCATGAGAAAGCCCCCCGGAAGATCACCTTCCGGGGGCTTTATATAATTAGC-3' 3'-TTGCGTACTCTTTCGGGGGGCCTTCTAGTGGAAGGCCCCCGAAATATATTAATCG-5' Draw the structure of hairpin loop that will be formed during the end of transcription.5'-TAGCTGATCGAATATGCGGTCTCTATCTTCGTAGACGA-3' 3'-ATCGACTAGCTTATACGCCAGAGATAGAAGCATCTGCT -5' Determine the amino acids that will be encoded by this sequence Second letter First letter U C A G U UUU Phe UUC UUA UUG Leu CUU CUC CUA CUG Leu GUU GUC GUA GUG Val UCU UCC UCA UCGJ AUU AUC lle AUA ACA AUG Met ACG CCU CCC C CCA CCG ACU ACC GCU GCC GCA GCG Ser - Pro Thr Ala A UGU UACTyr Cys UGC. UAA Stop UGA Stop A UAG Stop UGG Trp G CAC His CAA Gin CAG GAUT GAC Asp GAA AAU Asn ACC Ser AGU AAG LYS AA Glu GAGJ Oa. N-Met-Arg - Ser-Leu-Ser - Ser-C Ob. N-Met-Pro-Arg - Asn-Asp - Ser-C d. N-Met-Lys - Val-Glu-Ala-C Oc. N-Asp-Pro-Lys - Ser - Val-Ile-C Oe. N- Met-Ala-Asp-Pro-Lys - Ser-C G CGU CGC CGA CGG AGA AGG. GGU GGC GGA GGG Arg SCAO Gly U UCAG UUA DUAG Arg G Third letter 13
- Here is a DNA coding strand’s sequence and direction: 5’-ATGCCGATATAG-3’ . What would be the amino acid sequence in the polypeptide encoded by this DNA?1. AsnIleGlyTyrGluProSerArgAsp 2. MetPheAsnSerGluProLysCys 3. SerArgGluTyrValValThrPheGly 4. MetPheSerThrAspGluValof estion 9 t of uestion THCA ▶ Sou 100- HC This reaction is Entropy is THC San Leafly ATA RNA polymerase SSSSSSSSSS ATTOGOGACATAA ATGACGGATCAGCCOCAAG UACUOCCUAGUC RNA Transcript TACTOCCTAGTCGGCOTTCOOCTTAACCOCTOTATIT (In this picture, RNA is being made by complementary base pairing with DNA.) This reaction is → Entropy is ◆