Please explain step by step in neat hand writing so I can understand **Chemical Equilibrium Question**In this exercise, you will calculate the equilibrium constant, \( K_c \), for the following chemical reactions based on provided data.**Given Reactions:**1. \( \frac{1}{2}\text{N}_2(g) + \text{O}_2(g) \rightleftharpoons \text{NO}_2(g) \) - \( K_c = 1.04 \times 10^{-3} \)2. \( \text{N}_2(g) + 2\text{O}_2(g) \rightleftharpoons \text{N}_2\text{O}_4(g) \) - \( K_c = 7.42 \times 10^{-18} \)**Tasks:**Calculate \( K_c \) for each of the following reactions:(a) \( 2\text{NO}_2(g) \rightleftharpoons \text{N}_2(g) + 2\text{O}_2(g) \)(b) \( \text{N}_2(g) + 2\text{O}_2(g) \rightleftharpoons \text{N}_2\text{O}_4(g) \)(c) \( 2\text{NO}_2(g) \rightleftharpoons \text{N}_2\text{O}_4(g) \)**Note:** Assume that the reactions are at equilibrium and that the provided equilibrium constants are applicable. Use principles of chemical equilibrium to determine the relationship between the given and calculated \( K_c \) values.

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4) ½N2(g) + 02(g)= NO2(g) Kc = 1.04 x 10 N2(g) + 202(g) =N204(g) Kc=7.42 x 1018 %3D Calculate Kc for each of the following. (a) 2NO2(g)= N2(g) + 202(g) (b) N2(g) + 202(g) N2O4(g) (c) 2NO2(g) = N2O4(g)

4) ½N2(g) + 02(g)= NO2(g) Kc = 1.04 x 10 N2(g) + 202(g) =N204(g) Kc=7.42 x 1018 %3D Calculate Kc for each of the following. (a) 2NO2(g)= N2(g) + 202(g) (b) N2(g) + 202(g) N2O4(g) (c) 2NO2(g) = N2O4(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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