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5) 2 PbS04 → IN PbSO3 + 02 Type 6) _ Al + Fe2O3 → Fe + _Al2O3 5 Type 7) SF6 → S + F2 Typ 51 D 032 8) _ C2H4 + 02 → CO₂ + _ H₂O 9) _ KClO3 → KCl + _ 02 Typ 31392 Тур 10) - Pb(NO3)2 + NaCl → NaNO3 + PbCl2 Ty 10 +8=80 = Oxygen 11) What type of = Carbon 12) Using the key provided, write the complete chemical formula show

5) 2 PbS04 → IN PbSO3 + 02 Type 6) _ Al + Fe2O3 → Fe + _Al2O3 5 Type 7) SF6 → S + F2 Typ 51 D 032 8) _ C2H4 + 02 → CO₂ + _ H₂O 9) _ KClO3 → KCl + _ 02 Typ 31392 Тур 10) - Pb(NO3)2 + NaCl → NaNO3 + PbCl2 Ty 10 +8=80 = Oxygen 11) What type of = Carbon 12) Using the key provided, write the complete chemical formula show

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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5) 2 PbS04 → IN PbSO3 + 02 Type 6) _ Al + Fe2O3 → Fe + _Al2O3 5 Type 7) SF6 → S + F2 Typ 51 D 032 8) _ C2H4 + 02 → CO₂ + _ H₂O 9) _ KClO3 → KCl + _ 02 Typ 31392 Тур 10) - Pb(NO3)2 + NaCl → NaNO3 + PbCl2 Ty 10 +8=80 = Oxygen 11) What type of = Carbon 12) Using the key provided, write the complete chemical formula show
Transcribed Image Text:5) 2 PbS04 → IN PbSO3 + 02 Type 6) _ Al + Fe2O3 → Fe + _Al2O3 5 Type 7) SF6 → S + F2 Typ 51 D 032 8) _ C2H4 + 02 → CO₂ + _ H₂O 9) _ KClO3 → KCl + _ 02 Typ 31392 Тур 10) - Pb(NO3)2 + NaCl → NaNO3 + PbCl2 Ty 10 +8=80 = Oxygen 11) What type of = Carbon 12) Using the key provided, write the complete chemical formula show
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