**The Restriction Endonuclease PstI**The restriction endonuclease **PstI** cuts DNA symmetrically on both strands at the sequence:- **CTGCAG**- **GACGTC**Upon digestion, the resulting DNA fragments have 3' overhanging ends of 4 nucleotides. **PstI** specifically cleaves the phosphodiester backbone, resulting in these overhangs. Below, in shorthand notation that displays the identity of the phosphates on the ends, are the two fragments formed from **PstI** digestion of the following double-stranded oligonucleotide:5′-pAATTGCTACTGCAGAACCGG-3′ 3′-TTAACGATGACGTCTTGGCCp-5′**Explanation:**1. **Overhangs**: The sequence is cut to produce 3' overhangs where the single-stranded segments extend beyond the opposing strand.2. **Fragment Representation**: When drawn, the two resulting fragments maintain the complementary overhangs for potential re-annealing or ligation.This exercise illustrates the specificity and effects of enzyme action on DNA sequences, highlighting the predictable nature of molecular interactions used in genetic engineering and molecular biology.

Restriction endonucleases are the enzymes that are used to form cuts inside the DNA molecule. It is…

Answered: 3 The restriction endonuclease PstI…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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pcc300ATAAADATATAOOTTAA 1. Use the genetic code table and the information in the diagram below to determine the amino acids that would make up the portion of the polypeptide shown. Include information for a key as well. DNA template 3' G CATA ACAGAGGATT-5' al bnsua AMAm pniwollot erfT E transcription s yd bnsita ebitgeqylog s sidmeaze of beae RNA strandUU UAOUOUU A-emoaodin 5'-CGUA AUUGUC UCCUUA- 3' J J JL erit o elinW (s) translation bluow terdt aspnso sigootiwsone polypeptide viemetis ns ebivo19 (d) ent ot etslanT Key:
Provide the sequences of the template and coding strands of a DNA double helix that was used toproduce this RNA: 5’-GUUACCGACUAU. Be sure to label the 5’ and 3’ ends.
17. Complete the following Central Dogma Grid Puzzles: First determine which DNA strand is the template (look at provided nucleotides). Label template and coding/sense (non-template) strand in first column. In the second column, label the 5' and 3' ends of DNA and RNA sequences and the amino (N) and carboxyl (C) ends of the polypeptide. The last four columns represent transcriptional and translational alignments (reading frame). This is from within a coding region so you don't have to find a start codon. Fill in all nucleotides and amino acids using the mRNA code table on the last page. a. On this first grid, assume that the DNA and RNA templates are read left to right. DNA strand C DNA strand G mRNA codon A U TRNA anticodon A polypeptide TRP
Where do you predict the N- and C-termini are located for Max? Match the words in the left column to the appropriate blanks in the sentences on the right. electrostatic dispersion negative C-terminus positive positively negatively N-terminus The Reset Help is interacting with the DNA. The first reason for this is because the a-amino group is positively charged and will interact favorably with the of the charge on the phosphodiester backbone of the DNA. The second reason is that this orientation also situates the partial end of the helical macrodipole for favorable interactions with the charged phosphodiester backbone of the DNA
2. H. Gobind Khorana deciphered the genetic code by (1) chemically synthesizing DNA molecules of known sequence, (2) using this synthetic DNA as a template to produce RNA in a reaction involving RNA polymerase and dNTPs, then finally (3) using this RNA in an in vitro translation experiment with the ribosome and amino acyl-tRNA (aa-tRNA) building blocks to produce peptides. For each single-stranded deoxyribonucleotide sequence Khorana synthesized (shown below), a single polypeptide was produced in the in vitro translation step (3): (1) Synthetic DNA d(TTT)n d(CCC)n d(AAA)n d(GGG)n d(AAACCC)n d(AC)n d(ACA)n a. (2) RNA encoded by synthetic DNA (3) Peptide product composition polylysine polyglycine polyphenylalanine polyproline Equal F and G Equal C and V polycysteine Fill in the RNA sequences that were produced by RNA polymerase in column (2). b. When Khorana conducted this work, one looming question in the field was whether or not the genetic code is overlapping or non-overlapping. In a…
What is the role of GelRed® in Agarose gel electrophoresis of DNA fragments? Please select the single answer that is most correct GelRed® moves down the agarose gel in response to the electric current and enables visualisation of the position of A the nucleic acids within in the agarose gel. GelRed® intercalates with the Nucleic acid and, under UV light, fluoresces to enable visualisation of the position of the nucleic acids in the agarose gel. GelRed® intercalates with the Nucleic acid and enables visualisation of the position of the nucleic acids in C the agarose gel. GelRed® intercalates with the amino acids in the agarose gel and enables visualisation of the position of their in D the agarose gel.
b. Now do this AGAIN assuming that the DNA and RNA templates are read right to left. DNA strand C DNA strand T G A MRNA codon C|A U TRNA anticodon G A polypeptide TRP
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Please help me, this is from practice, double check your answers, previous tutors got it wrong
13. please answer, i'll give thumbs up
25. Given the following mRNA codons and amino acids, construct a polypeptide from this DNA strand. DNA AAT GGT CCA CCG CTG 1TI 111 11 T Ou GGT GGC GIC MRNA Amino Acids UUA = leucine %3D GAC = asparginine GGU = glycine GGC = glycine CCA = proline %3D AMAM b iwi tant neto10 e 2obitoabun St

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