2. The diagram shows a conical section fabricated from pure aluminum. It is of circular cross section having diameter D = ax¹/2, where a = 0.5 m¹/2. The small end is located at x1 = 25 mm and the large end at x2 = 125 mm. The end temperatures are T₁ = 600 K and T₂ = 400 K, while the lateral surface is well insulated. (a) Derive an expression for the temperature distribution T(x) in symbolic form, assuming one dimensional conditions. Sketch the temperature distribution. (b) Calculate the heat rate qx. Answer: Pure Aluminum (500K): k= 236 W/m·K. (b). 5.76kW

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Chapter3: Transient Heat Conduction
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Problem 3.4P
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2. The diagram shows a conical section fabricated from pure aluminum. It is of circular cross
section having diameter D = ax¹/2, where a = 0.5 m¹/2. The small end is located at x1 = 25 mm and
the large end at x2 = 125 mm. The end temperatures are T₁ = 600 K and T₂ = 400 K, while the
lateral surface is well insulated.
(a) Derive an expression for the temperature distribution T(x) in symbolic form, assuming one
dimensional conditions. Sketch the temperature distribution.
(b) Calculate the heat rate qx.
Answer: Pure Aluminum (500K): k= 236 W/m·K. (b). 5.76kW
Transcribed Image Text:2. The diagram shows a conical section fabricated from pure aluminum. It is of circular cross section having diameter D = ax¹/2, where a = 0.5 m¹/2. The small end is located at x1 = 25 mm and the large end at x2 = 125 mm. The end temperatures are T₁ = 600 K and T₂ = 400 K, while the lateral surface is well insulated. (a) Derive an expression for the temperature distribution T(x) in symbolic form, assuming one dimensional conditions. Sketch the temperature distribution. (b) Calculate the heat rate qx. Answer: Pure Aluminum (500K): k= 236 W/m·K. (b). 5.76kW
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