Materials Science Engineering; CCT Diagram (a) Based on this diagram, what process should be used to make temperedmartensite? Be sure to specify cooling rate and any other treatments that wouldbe required.(b) Using the CCT curve below, what treatment would be required (cooling raterange) to achieve the highest possible yield strength in the as-cooled conditionwithout forming martensite? Identify the microconstituent and describe it.(c) Examine the CCT curve and determine if the alloy steel is hyper or hypoeutectiod. Explain your reasoningTemperature (°C)800Eutectoid temperature700600500----8.3°C/s1Bainite "nose"1400AusteniteFerriteAustenite1200Pearlite10.006°C/s10.02°C/s1000800400CriticalcoolingrateAustenite Bainite300600M (start)Austenite Martensite|200T14001M+F+I/P+B100200MM+FM+ BF+P+B110102103104105106Time (s)Figure 2: CCT diagram for 4043 alloy steel.Temperature (°F)

(a) Process to Make Tempered MartensiteTo create tempered martensite, you need to follow two main…

Answered: (a) Based on this diagram, what process…

Welding: Principles and Applications (MindTap Course List)

8th Edition

ISBN:9781305494695

Author:Larry Jeffus

Publisher:Larry Jeffus

Chapter26: Welding Metallurgy

Section: Chapter Questions

Problem 27R: What are the three steps in precipitation hardening?

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What are some possible defects in drawn sheet-metal parts? In blanking of a circular sheet-metal part, is the clearance applied to the punch diameter or the die diameter? What is martensite? Based on the TTT curve, what is it that should be avoided during martensitic process? What is the main condition for strengthening an alloy by precipitation?
Excellent combinations of hardness, streneth, and toughness are obtained from bainite. One heat treater austenitized a eutectoid steel at 750°C, quenched and haid the steal at 250°C for 15 min, and finaly permitted the staal to cool to room temperature. Did he produce the required bainitic structure? Use the diegram below in your answer Answer: Tie ReckvellChndre
Using the TTT diagram, what microstructure would be developed by rapidly cooling to 650°C and holding for 50 seconds, followed by rapid cooling to 500°C and holding for 5 seconds, followed by quenching to room temperature? (give relative percentages of each microstructure component) Using the TTT diagram, describe the entire thermal treatment that would generate a microstructure consisting of 50% bainite, and 50% martensite. On the CCT diagram to the right, what microstructure would be developed by following cooling curve (c), then heating to 700°C for at least a day? Temperature l"C)
What are the three steps in precipitation hardening?
Pls do it 30min An eutectoid steel is cooled slowly from 1000 °C to room temperature by the following different cooling rates: (i) 1 °C/s, (ii) 20 °C/s, (iii) 50 °C/s, (iv) 175 °C/s. Name the respective microstructural products for the above four cooling rates.
Below is a continuous cooling transformation curve for steel (upper) and for a silicate melt (lower). Describe the similarities and differences as follows. a. What is the critical cooling rate in each case? b. What phase(s) form in each case when the critical cooling rate is exceeded? c. What phase(s) form in each case if the cooling rate is very slow? 800 1400 Ae lemperature Austenite *peorlite begins 10FI 700 1200 Austenitepearlite complete 1600 1000 5009 800 Tronsformation stops 400 600 300 400 Austenite -mortenstic structure 200 -Isathermal dogram Continuous transformaton diogrom Constant rate coding curves - 100 200 Findl structure Mortensite Morlensite i peorlile Peorite (softer, coorser- 0.1 10? 10 Tronsformation time, seconds Continuous Cooling-Transformation (C-T)Diagram (Derived from the isothermal-transformation diagram for a plain-carbon eutectoid steel) 1200 Glass Crystallization begins 1100 1000 Critical cooling rate Glass-ceramic 900 Crystallization ends 800 700 102 10…
1. Why does the tensile strength of steel, which contains only austenite at room temperature, differ fromsteel that shows only pearlite in its microstructure? Give two important reasons for the difference. 2. What general prerequ_isites exist for the formation of martensite in steel? 3. What is an isothermal transformation of a material in the solid state condition? 4. Draw a typical isothermal transformation diagram for plain .carbon eutectoid steel and indicate thevarious decomposition products expected by simple diagrammatic drawing.
What is the advantage of nitriding? Select all correct answers. Some complex components can be nitride without difficulty. Better wear resistance. Better fatigue resistance. The cheapest method of case hardening. What is the correct definition of plastic deformation? The behavior of a material when its size changes by the addition of heat. The behavior of a material that deforms under load and returns to its original shape when the load is removed. Deformation caused by cleavage, where the material is actually pulled apart across atomic planes within the crystals or along the grain boundaries. The behavior of a material that deforms under load and does not fully return to its original shape when the load is removed.
In your own words describe the following heat treatment procedures for steels and, for each, the intended final microstructure: (a) full annealing (b) normalizing (c) quenching (d) tempering.
1. Using the TTT diagram for Eutectoid Steel, specify the constituents and their approximate percentages of a small specimen subjected to the following time-temperature treatments. All begin with a completely Austenized specimen: - Rapidly cool to 650°C, hold for 100 seconds, then quench to room temperature. Rapidly cool to 500°C, hold for 100 seconds, then quench to room temperature. - Rapidly cool to 350°C, hold for 100 seconds, then quench to room temperature. - Rapidly cool to 100°C, hold for 100 seconds, then quench to room temperature. - Rapidly cool to 500°C, hold for 4 seconds, quench to 300°C, hold for 200 seconds, then quench to room temperature.
Draw the iron carbon phase diagram and labeling all lines and areas. Then:- 1- find the melting point of cast iron with 2.2%C. 2- explain in detail the steps of solidification and transformation of cast iron with 3%C. 3- draw the expected microstructure of iron with 0.1%C ; 0.4%C; 0.83%C; 2%C; 4.3%C. 4-draw the cooling curve for hyper steel with 1.8%C. 5- find the percentage of liquid and solid for cast iron with 3.8%C at 1160 degree Celsius with the composition for each of them.
For each question, provide an explanation, identifying the correct choice ( it is marked in red) and explaining why it's the right answer, as well as why the other options are incorrect.

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