I am trying to derive the Jacobian matrix, the J_J2 in the image. Can you help me calculate the partial derivatives? მმ.მaმე:მყმმayმagმayJJ2 =მმყმმa-მa-მთ.მემყმ ax =3J2μR Earth275x5.1ay =3J2μR Earth275y5az =3J2μR Earth2755r2223

Answered: Image /qna-images/answer/d33635e3-9a5d-4fa9-8e85-3043907838f8.jpg

Answered: მ მ. მa მე: მყ მ მay მag მay JJ2 = მ მყ…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A motor drives four loads, two have rotational motion and two have translational motion. The momentof inertia of the motor is 1.2kg-m^2. The motor runs at a speed of 1000rpm. The table below shows thedetails of the four loads. Calculate the power developed by the motor. (Load ;Type of Motion; Speed; Inertia / Mass; Torque / Force) 1; Rotational; 200 rpm; 7 kg-m^2; 10 N-m 2; Rotational; 200 rpm; 5 kg-m^2; 6 N-m 3; Translational; 10 m/s; 10 kg; 20 N4; Translational; 10 m/s; 20 kg; 30 N
True or False
Damian’s car weighs 2000kg. The spring has a natural unstretched length of 2m and a spring constant of k = 80000N/m. Hooke's law can be written as T = kd. Where T is the tension force in newtons, k is the spring constant and d is the length in metres. Let x(t) be the position of the front of Damian’s car and let y(t) be the position of the back of Eva’s 4WD. We will assume that the position of Eva’s car is a known function of time. Q1 a) Create a sketch of the positions of the vehicles similar to the one given and add the positions x and y. b) What is the extension of the spring in terms of x(t) and y(t)? Be careful to take into account that the unstretched length of the spring is 2m.
Thermodynamics
*For questions a) and b), you must answer directly on the graph on the next page when required to do so (figure 2.2)* You must pump 5°C water from a large open-air reservoir to another at a rhythm of 1 1/s. The pipe linking both reservoirs is one inch in diameter, has a Hazen-Williams coefficient of 140 and measures 1 km (975 m of which are found after the pump displayed on figure 2.1). Singular head loss can be neglected. Based on figures 2.1 and 2.2, you must: a) Select the most adequate pump to complete your project: b) Identify the point of operation (minimum 3 points must be calculated on the pipe characteristic curve); c) Determine if cavitation could be an issue. N.B. presume atmospheric pressure to be 101.3 kPa. 6 m Figure 2.1 Pump configuration P 2 m 15 m
None
Got this wrong. please help and show work then round the final answer to 3 sig figs.
۳۸% ۱۰:۲۱ ص docs.google.com/forms 10 نقاط Resolve the 300 N into two components at the u and v axis 300N 20 70° Fu = 109.1 N, Fv= 244.5 N O Fu = 300.2 N, Fv= 217.5 N O Fu = 154.1 N, Fv= 219.3 N O Fu = 203.2 N, Fv= 267.7 N O
BME2223-ENGINEERING MECHANICS MIDTERM E) 1) Find V.(V× B) for B = 3x²yî – 2xyzĵ + 5y²z³k
4. Determine which of the following systems has the highest magnitude of torque using cross product vector operations. Also, use the right hand rule to find the direction of the torque of each system. Use the symbol 2 for torques whose directions are towards the page and 2 for torques whose directions come out of the page. 10cms 10 c F-20n ww 10 ma
account_circle Science PhysicsQ&A LibraryA child’s toy consists of a m = 31 g monkey suspended from a spring of negligible mass and spring constant k. When the toy monkey is first hung on the spring and the system reaches equilibrium, the spring has stretched a distance of x = 17.6 cm, as shown in the diagram. This toy is so adorable you pull the monkey down an additional d = 7.6 cm from equilibrium and release it from rest, and smile with delight as it bounces playfully up and down. 1. Calculate the speed of the monkey, ve, in meters per second, as it passes through equilibrium. 2. Derive an expression for the total mechanical energy of the system as the monkey reaches the top of the motion, Etop, in terms of m, x, d, k, the maximum height above the bottom of the motion, hmax, and the variables available in the palette. 3. Calculate the maximum displacement, h, in centimeters, above the equilibrium position, that the monkey reaches. A child’s toy consists of a…
a javelin thrower releases their 600-g javelin 2.0 m above the ground traveling at an angle of 30∘∘ above the horizontal. top-rated javelin throwers do throw at about a 30∘∘ angle, not the 45∘∘ you might have expected, because the biomechanics of the arm allow them to throw the javelin much faster at 30∘∘ than they would be able to at 45^\circ$. in this throw, the javelin hits the ground 70 m away. Calculate the initial speed of the throw.

SEE MORE QUESTIONS

Recommended textbooks for you

Elements Of Electromagnetics

Mechanical Engineering

ISBN:

9780190698614

Author:

Sadiku, Matthew N. O.

Publisher:

Oxford University Press

Mechanics of Materials (10th Edition)

Mechanical Engineering

ISBN:

9780134319650

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Thermodynamics: An Engineering Approach

Mechanical Engineering

ISBN:

9781259822674

Author:

Yunus A. Cengel Dr., Michael A. Boles

Publisher:

McGraw-Hill Education

Elements Of Electromagnetics

Mechanical Engineering

ISBN:

9780190698614

Author:

Sadiku, Matthew N. O.

Publisher:

Oxford University Press

Mechanics of Materials (10th Edition)

Mechanical Engineering

ISBN:

9780134319650

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Thermodynamics: An Engineering Approach

Mechanical Engineering

ISBN:

9781259822674

Author:

Yunus A. Cengel Dr., Michael A. Boles

Publisher:

McGraw-Hill Education

Control Systems Engineering

Mechanical Engineering

ISBN:

9781118170519

Author:

Norman S. Nise

Publisher:

WILEY

Mechanics of Materials (MindTap Course List)

Mechanical Engineering

ISBN:

9781337093347

Author:

Barry J. Goodno, James M. Gere

Publisher:

Cengage Learning

Engineering Mechanics: Statics

Mechanical Engineering

ISBN:

9781118807330

Author:

James L. Meriam, L. G. Kraige, J. N. Bolton

Publisher:

WILEY

SEE MORE TEXTBOOKS

მ მ. მa მე: მყ მ მay მag მay JJ2 = მ მყ მ მa- მa- მთ. მე მყ მ ax = 3J2μR Earth 275 x 5. 1 ay = 3J2μR Earth 275 y5 az = 3J2μR Earth 275 5 r2 22 3