.3 m Pa = 1100 kN Ma = 325 kN - m W12 X 106 K₂ = K₂ = 1.0 Ma = 325 kN - m Pa = 1100 kN W12 x 106 w = 158 kg/m A = 20100 mm² d = 328 mm br = 310 mm tw = 15.5 mm tr = 25.1 mm Ix= 388 x 106 mm²
.3 m Pa = 1100 kN Ma = 325 kN - m W12 X 106 K₂ = K₂ = 1.0 Ma = 325 kN - m Pa = 1100 kN W12 x 106 w = 158 kg/m A = 20100 mm² d = 328 mm br = 310 mm tw = 15.5 mm tr = 25.1 mm Ix= 388 x 106 mm²
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Problem 20. The member shown is part of a braced frame. Bending is about the x-axis and the steel is ASTM A992. For the member shown, the factor Cm that will be used to compute the amplification factor is
0.2
0.4
0.6
1.0
21. For the member shown in problem 20, using ASD, compute the moment amplification factor B1.
a 1.0
b 1.04
c 1.07
d 1.09
![←
4.3 m
Pa = 1100 kN
Ma = 325 kN - m
W12 X 106
K₂ = K₂ = 1.0
Ma = 325 kN - m
Pa = 1100 kN
W12 x 106
w = 158 kg/m
A = 20100 mm²
d = 328 mm
bf = 310 mm
tw = 15.5 mm
t+= 25.1 mm
lx = 388 x 106 mm²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F229caa69-8269-40d1-a2ab-7acd699e06f4%2Faff1184e-f88e-40a7-b550-d2bd6833015f%2Fdfqp7oe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:←
4.3 m
Pa = 1100 kN
Ma = 325 kN - m
W12 X 106
K₂ = K₂ = 1.0
Ma = 325 kN - m
Pa = 1100 kN
W12 x 106
w = 158 kg/m
A = 20100 mm²
d = 328 mm
bf = 310 mm
tw = 15.5 mm
t+= 25.1 mm
lx = 388 x 106 mm²
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