composite shaft AC is made by shrink-fitting a titanium-alloy sleeve of length L3 = 4 ft over segment BC of a 6-ft-long aluminum-alloy rod. This makes a three-component shaft, which is fixed against rotation at ends A and C. The shear moduli are G1 = G2 = 6 X 103 ksi and G3 = 4 X 103 ksi, respectively, and the diameters and d1 = d2 = (di)3 = 2 in., and (do)3 = 2.5 in. (a) Using the Displacement Method, determine the angle of ro- tation at B, og. produced by an applied torque Tg = 50 kip . in. (b) Determine the maximum shear stress (Tmax)1 in the alu- minum segment AB, (Tma)2 in the aluminum core segment BC, and (Tmax), in the titanium sleeve BC.
a composite shaft AC is made by shrink-fitting a titanium-alloy sleeve of length L3 = 4 ft over segment BC of a 6-ft-long aluminum-alloy rod. This makes a three-component shaft, which is fixed against rotation at ends A and C. The shear moduli are G1 = G2 = 6 X 103 ksi and G3 = 4 X 103 ksi, respectively, and the diameters and d1 = d2 = (di)3 = 2 in., and (do)3 = 2.5 in.
(a) Using the Displacement Method, determine the angle of ro- tation at B, og. produced by an applied torque Tg = 50 kip . in.
(b) Determine the maximum shear stress (Tmax)1 in the alu- minum segment AB, (Tma)2 in the aluminum core segment BC, and (Tmax), in the titanium sleeve BC.

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(a) Angle of Rotation at B (θB):
Using the Displacement Method, we can calculate the angular displacement at point B due to the applied torque Tg.
θB = Tg / (G1 * L1) + Tg / (G2 * L2)
Where:
- Tg = Applied torque = 50 kip.in
- G1 = Shear modulus of aluminum alloy in segment AB = 6 x 10^3 ksi
- G2 = Shear modulus of aluminum alloy in segment BC = 6 x 10^3 ksi
- L1 = Length of segment AB = 2 ft (given)
- L2 = Length of segment BC = 4 ft (given)
Substitute the values to calculate θB,
θB = (50 kip.in) / (6 x 10^3 ksi * 2 ft) + (50 kip.in) / (6 x 10^3 ksi * 4 ft)
θB = 0.0017 radians
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