Lab 9 KA

xlsx

School

Ohio State University *

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1113

Subject

Mechanical Engineering

Date

Dec 6, 2023

Type

xlsx

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Uploaded by SuperHumanBoulderFalcon35

Task 1 Power supply Fan Voltage (V) 6 0.082 0.002241333333 7 0.172 0.009861333333 8 0.208 0.014421333333 9 0.233 0.018096333333 10 0.253 0.021336333333 11 0.268 0.023941333333 12 0.285 0.027075 Task 2 Voltage across the Resistor (V) Power Output of the Wind Turbine (W) Wind Turbine Lab Name: Your team members: Date: Note: This lab requires an individual memo style report. See Blackboard for details. See Tasks 1-5 on three Excel pages. Include the data pages in your report. For safety do not put your face in front of the wind tunnel! Calculate the Electrical Power Output of the Wind Turbine . 1) Connect the turbine to a 3 ohm resistor. Connect a voltmeter (DMM set to DC volts) across the resistor. Make sure to watch the units on the DMM for voltage. Put the 3 blade (plastic) propeller on the turbine. 2) The formula for electrical power is P = V^2/R V = voltage across the resistor ( not the voltage on the power supply to the fan ) R = Resistance 3) Step through the voltages given on the chart below for the power supply to the fan to get a range of wind speeds. In Task 2 you will measure the wind speeds without the turbine. 4) In your report you will need a graph of Electrical Power Output vs. Fan Voltage. Calculate the Wind Input Power 1) Take out the wind turbine from the wind tunnel. 2) Step through the Fan Voltages again to record the Wind Velocity. Use the anemometer to get the Wind Velocity in m/s. Calculate the power in the wind. The formula for the input power in the wind is: 6 7 8 9 10 11 12 0 0.005 0.01 0.015 0.02 0.025 0.03 0.002241333333 333 0.009861333333 333 0.014421333333 333 0.018096333333 333 0.021336333333 333 0.023941333333 333 0.027075 Electrical Power Output vs. Fan Voltage Fan Voltage (V) Electrical Power Output (W)

2.101 13.867621433 Fan Voltage (V) 6 5.42 1346.882381706 7 6.85 2718.964434976 8 7.83 4060.851410164 9 8.61 5399.347343094 10 9.48 7207.038207402 11 9.89 8183.153301067 12 10.42 9570.507530346 Task 3 Fan Voltage (V) % Efficiency 6 0.000166408987 7 0.000362687103 8 0.000355130781 9 0.000335157792 10 0.000296048567 Radius of the propeller = Area of circle (m^2) = Wind Velocity (m/s) Power in the Wind (W) m/s. Calculate the power in the wind. The formula for the input power in the wind is: P = (1/2) p Av^3 P = Power in Watts p = density of air. Use 1.22 kg/m^3 A = Area of the circle that the propeller sweeps out A = π r^2 r = radius of propeller in meters v = Wind Velocity Your report should have a graph of Wind Power vs. Wind Velocity. 1)) Calculate the % Efficiency of the turbine. % e = ((Electrical power output from Task 1)/(Power in the wind from Task 2)) * 100 2) Your report will require a graph of % Efficiency vs. Wind Velocity for the Wind Turbine. See the next page for Tasks 4 and 5. Calculate the Turbine Efficiency 5.42 6.85 7.83 8.61 9.48 9.89 10.42 0 2000 4000 6000 8000 10000 12000 1346.8823817 0552 2718.9644349 7573 4060.8514101 6358 5399.3473430 9432 7207.0382074 0214 8183.1533010 6683 9570.5075303 4568 Wind Power vs. Wind Velocity Wind Velocity (m/s) Power in the Wind (W)

11 0.000292568555 12 0.000282900357

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Task 4 Blade Design Describe the Blade Design 1-heart butt 0.0186 0.00011532 heart butt 2- oval 0.0345 0.00039675 oval 3-rectangle 0.0447 0.00066603 rectangle 4-trapy zoidy 0.0574 0.001098253333333 trapy zoidy -best design/ more area Task 5 Hub at 30 degrees Hub at 45 degrees Voltage values go in the chart on the left. 1 Blade 0.0508 0.0574 2 Blades 0.1225 0.0881 3 Blades 0.1603 0.1007 Voltage on the resistor (V) Output Power from the Turbine (W) Design your own Wind Turbine Blades 1) Design 4 different types of blades. Cut your blades out of balsa wood. 2) One at a time test them in the turbine to find which blade gives the most electrical power output of the tu blades can be mounted in the 45 degree hub provided. Take a picture of the blades labeled with the blade nu include it in your report. 3) Put the turbine in the wind tunnel. Set the fan at 9 volts on the power supply. Calculate the power out did in Task 1. 4) In your report, explain what factors led to the best blade design. Determine the effects of hub angle and the number of blades. Measure the voltage for each of the combinati number of blades and hub angle below. In the bottom table calculate the power. In your report discuss what had the greatest effect and your explanation of what you observed. See the next page for Task 6 calculations.

Hub at 30 degrees Hub at 45 degrees Power Values go in the chart on the left. 1 Blade 0.000860213333333 0.001098253333333 2 Blades 0.005002083333333 0.002587203333333 3 Blades 0.008565363333333 0.003380163333333 See the next page for task 6. What were your observations? The largest blade had the highest voltage on the resistor, (with more area, comes more energy/force). Between the 30 degrees and 45 degress for voltages, the "1 blade" started out similiar for both degrees but as the number of blades grew the difference between voltages grew as well. Resulting in 30 degrees having higher voltages and thus higher power values.

changed voltage from 8 to 9 urbine. The umber and tput as you tions of

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Task 6 17123.29 2134.326 3000 8.219178 Include in your report the following calculations: Assume the average wind velocity for Columbus, Ohio is 5.5 m/s. A wind turbine located at Byers Mazda Subaru near I 270 on the north part of Columbus can generate 150000kWH in a year. It has a 69 ft. radius. Assume it turns continuously in a year. A) Estimate the efficiency of the turbine. Show your calculations. Watch the units. 3.281 ft = 1 meter. You will need to calculate the number of hours in a year for this calculation since you are given an energy per year ouput for the turbine. Show your work. You can use a separate sheet if you wish. velocity = 5.5m/s. 150000kWH -> WH = 150000000 WH 69ft->m = 69/3.281 = 21.03017m 150000000WH/ 8760 H (in a year) = 17123.29W (1/2)*(5.5)^3*(21.0312)*(1.22) = 2134.326 W 17123.29/2134.326 = 8.022809.. est 8.0 (sigfig) efficiency B) Assuming a single household uses about 50 kWH/day, how many households can be powered by this turbine? 50kWH -> 50000W 150000000/50000 = 3000 3000/365 = 8.219 households est 8 households

21.03017 8.022809