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50 h = Pbot = wd+ √₂-50 ft T only unknown Prot 50 рзд. water glycerin s.g=1.26 'd HW: '50' s.g= I₂ Jg=1.268₁ би = 1.26x62.414 Local atmospheric pressure = 780 mmHg = Pa at the bottom reads 50 psig даде Temperature of water and glycerin is 68°F 7=6244, 8₂ Determine the depth of water (Id in the tank.

50 h = Pbot = wd+ √₂-50 ft T only unknown Prot 50 рзд. water glycerin s.g=1.26 'd HW: '50' s.g= I₂ Jg=1.268₁ би = 1.26x62.414 Local atmospheric pressure = 780 mmHg = Pa at the bottom reads 50 psig даде Temperature of water and glycerin is 68°F 7=6244, 8₂ Determine the depth of water (Id in the tank.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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50 h = Pbot =Vw dt 8₂-50¹ ft T only unknown only 50 psig water glycerin 5.g=1.26 HW: '50' Sg= Le Jg= 1.268₁ =1.26x X62.4 16 Local atmospheric pressure = 780 mm Hg at the bottom reads 50 psig gage = Pa Temperature of water and glycerin is 68°F X=62411,89 ft³ Determine the depth of water (d in the tank.
Transcribed Image Text:50 h = Pbot =Vw dt 8₂-50¹ ft T only unknown only 50 psig water glycerin 5.g=1.26 HW: '50' Sg= Le Jg= 1.268₁ =1.26x X62.4 16 Local atmospheric pressure = 780 mm Hg at the bottom reads 50 psig gage = Pa Temperature of water and glycerin is 68°F X=62411,89 ft³ Determine the depth of water (d in the tank.
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