Hello, I don't understand how to solve 5-19 in the photo below. Because I can't find the correct elaboration on the solutions, I hope that you can show me how to get to this answer. I have added my own calculations in a photo for your insight. These are the correct answers: tmaxEA= 5,66 MPa tmaxCD = 8,91 MPa Thanks for your help! Julia
Hello, I don't understand how to solve 5-19 in the photo below. Because I can't find the correct elaboration on the solutions, I hope that you can show me how to get to this answer. I have added my own calculations in a photo for your insight. These are the correct answers: tmaxEA= 5,66 MPa tmaxCD = 8,91 MPa Thanks for your help! Julia
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Hello,
I don't understand how to solve 5-19 in the photo below. Because I can't find the correct elaboration on the solutions, I hope that you can show me how to get to this answer. I have added my own calculations in a photo for your insight.
These are the correct answers:
tmaxEA= 5,66 MPa
tmaxCD = 8,91 MPa
Thanks for your help!
Julia

Transcribed Image Text:220
CHAPTER 5 TORSION
5-18. The motor delivers a torque of 50 N m to the shaft
AB. This torque is transmitted to shaft CD using the gears
at E and F. Determine the equilibrium torque T' on shaft
CD and the maximum shear stress in each shaft. The
bearings B, C, and D allow free rotation of the shafts.
5-19. If the applied torque on shaft CD is T' = 75 N m,
determine the absolute maximum shear stress in each shaft.
The bearings B, C, and D allow free rotation of the shafts,
and the motor holds the shafts fixed from rotating.
A
50 mm
30 mm
B
35 mm
125 mm
T'
D
ont of botouid
nwode
Probs. 5-18/19 00
*5-20. The shaft has an outer diamoto
100

Transcribed Image Text:Teg=75 NM
Tco
deo
os5 1,47.07mu
EEP
0,125=63,7 Mpa
TEF = TEA
%3D
TEA= 63,7 MPa. g.2 10
5003NM
TEA = TAB
TAB= A SO0.3.r= 5003.0,015 760MPg
corect
TEA S,66 Mla
answer
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