attached 5. A mechanical oscillator with a quality factor of 2 comprises a mass of 50 to a spring of stiffness 3250 N/m. When the mass is subject to an oscillating driving force of magnitude 20 N, the resultant frequency of oscillation of the system is 50 Hz. a). Calculate the value of the mechanical resistance, Rm, for the system. b). What percentage of the maximum power is dissipated in the system when is it driven to oscillate at 50 Hz? c). State whether the system is underdamped, critically damped or overdamped when the driving force is turned off and justify your answer.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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ChapterMA: Math Assessment
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5. A mechanical oscillator with a quality factor of 2 comprises a mass of 50 g attached
to a spring of stiffness 3250 N/m. When the mass is subject to an oscillating driving
force of magnitude 20 N, the resultant frequency of oscillation of the system is 50 Hz.
a). Calculate the value of the mechanical resistance, Rm, for the system.
b). What percentage of the maximum power is dissipated in the system when is it
driven to oscillate at 50 Hz?
c). State whether the system is underdamped, critically damped or overdamped when
the driving force is turned off and justify your answer.
Transcribed Image Text:5. A mechanical oscillator with a quality factor of 2 comprises a mass of 50 g attached to a spring of stiffness 3250 N/m. When the mass is subject to an oscillating driving force of magnitude 20 N, the resultant frequency of oscillation of the system is 50 Hz. a). Calculate the value of the mechanical resistance, Rm, for the system. b). What percentage of the maximum power is dissipated in the system when is it driven to oscillate at 50 Hz? c). State whether the system is underdamped, critically damped or overdamped when the driving force is turned off and justify your answer.
2 = Wome
Jo Rm =
$197
11
2
10
таж Рас
२०
2x6.4
1
Rm
3350
11
Wom
||
FR
Ø
C
Q
N
A
X
ZRm
X
2
G.OS
6.4 Ns/w
W
11
m
SOO
2
31.4 W
L
3
E
R
5
T
6
@W.
FRm
2 (X=²+x²m²)
e
@ 50Hz:
Xm = mw.
So
Pow
~ (@sonz) =
% of
5.4 N
с) W ='
3230
=
(0.05 X ²x s
3250
0.05
2 x 50
20³ x64
2x(54²2
18.4
NJ
31
2X0.05)
Transcribed Image Text:2 = Wome Jo Rm = $197 11 2 10 таж Рас २० 2x6.4 1 Rm 3350 11 Wom || FR Ø C Q N A X ZRm X 2 G.OS 6.4 Ns/w W 11 m SOO 2 31.4 W L 3 E R 5 T 6 @W. FRm 2 (X=²+x²m²) e @ 50Hz: Xm = mw. So Pow ~ (@sonz) = % of 5.4 N с) W =' 3230 = (0.05 X ²x s 3250 0.05 2 x 50 20³ x64 2x(54²2 18.4 NJ 31 2X0.05)
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