Please show work for practice problem 12 The following data were collected from a 0.4 in. diameter test specimen of polyvinyl chloride (initial length \( l_0 = 2.0 \) in.): Stress-strain curve also: Determine Tensile Strength.| Load (lb) | Gage Length (in.) | Stress (psi) | Strain (in./in.) ||-----------|-------------------|--------------|------------------|| 0 | 2.00000 | 0 | 0.0 || 300 | 2.00746 | 2,387 | 0.00373 || 600 | 2.01496 | 4,773 | 0.00748 || 900 | 2.02374 | 7,160 | 0.01187 || 1200 | 2.032 | 9,547 | 0.016 || 1500 | 2.046 | 11,933 | 0.023 || 1660 | 2.070 (max load) | 13,865 | 0.035 || 1600 | 2.094 | 12,729 | 0.047 || 1420 | 2.12 (fracture) | - | - |**Graph/Diagram Explanation:**The graph shown is a stress-strain curve, which plots the stress in kilopounds per square inch (ksi) against the strain (inches per inch). The x-axis represents strain, and the y-axis represents stress. The curve starts at the origin (0,0) and initially follows a linear path, indicating the elastic region where stress is directly proportional to strain. As the curve progresses, it begins to plateau, showing the material's transition into the plastic region. The maximum point on the curve (peak stress) represents the ultimate tensile strength of the material prior to fracture. The graph illustrates both the proportional limit and the regions of elastic and plastic deformation.

Given To find -Tensile strengthThe tensile strength is the maximum mechanical tensile stress with which a specimen can be loaded. It is also the stress at maximum load. Therefore tensile strength is given by

Answered: The following data were collected from…

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The following data were collected from a 0.4in. diameter test specimen of poly uinyl chloride (initial length (lo) 2.0 in.): Stress-strain curve also: Determine Tensile Strength

Elements Of Electromagnetics

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Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Concept explainers

Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

Please show work for practice problem 12

The following data were collected from a 0.4 in. diameter test specimen of polyvinyl chloride (initial length \( l_0 = 2.0 \) in.): Stress-strain curve also: Determine Tensile Strength.

| Load (lb) | Gage Length (in.) | Stress (psi) | Strain (in./in.) |
|-----------|-------------------|--------------|------------------|
| 0 | 2.00000 | 0 | 0.0 |
| 300 | 2.00746 | 2,387 | 0.00373 |
| 600 | 2.01496 | 4,773 | 0.00748 |
| 900 | 2.02374 | 7,160 | 0.01187 |
| 1200 | 2.032 | 9,547 | 0.016 |
| 1500 | 2.046 | 11,933 | 0.023 |
| 1660 | 2.070 (max load) | 13,865 | 0.035 |
| 1600 | 2.094 | 12,729 | 0.047 |
| 1420 | 2.12 (fracture) | - | - |

**Graph/Diagram Explanation:**

The graph shown is a stress-strain curve, which plots the stress in kilopounds per square inch (ksi) against the strain (inches per inch). The x-axis represents strain, and the y-axis represents stress. The curve starts at the origin (0,0) and initially follows a linear path, indicating the elastic region where stress is directly proportional to strain. As the curve progresses, it begins to plateau, showing the material's transition into the plastic region. The maximum point on the curve (peak stress) represents the ultimate tensile strength of the material prior to fracture. The graph illustrates both the proportional limit and the regions of elastic and plastic deformation.

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