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MENG 3331 Materials Science
Department of Mechanical Engineering
Sept. 20, 2023, Statesboro, Georgia, USA
Technical Report 4
CHARPY TEST
Bryce Cone
Georgia Southern Student
Sparks, GA, United States
Dylan Butler
Georgia Southern University
Albany, Georgia, United States
Scott Rhodes Georgia Southern University
Warner Robins, GA, United
States
Lawrence Almeter
Georgia Southern University
Dearing, GA, United States
A
BSTRACT
Charpy testing is a test used to study the toughness of
a material. In this test, a material is struck at different
temperatures to see how it absorbs energy and deforms. In this
test, the material is a mild steel kept at different temperatures,
71.4, -92.4, 209.5, -94.3, -0.6. All these measurements are
taken in degrees Fahrenheit. Each of the materials had a slight
notch made in them and were each placed in the Charpy testing
machine with the grove facing outward. The Charpy testing
machine consists of a giant swing hammer on a pendulum
which swings down and strikes the material. Upon conducting
the experiment, it was discovered that the boiled and the freezer
material had a more ductile behavior while the room temp and
dry ice material had a more brittle behavior. Ductile materials
under certain conditions can display brittleness.
N
OMENCLATURE
CVN
Charpy V-Notch Test
ft-lb
Energy [foot pounds]
INTRODUCTION
The Charpy test is performed by machining a V-notch into
a 10mm x 10mm x 55mm on one of the rectangular faces of the
sample. Next the pendulum will be set, and the sample will be
set center in the fixture with the notch facing away from the
point of impact/ towards the wall opposite of the side of the
hammer. Then the pendulum will be released causing the
hammer to smash into the sample allowing the Charpy test
machine to record the difference of the original height and the
highest point reached after the collision, which gives a
measured value of the energy absorbed due to the machine
being built in such a way that the pendulum is set at a
predetermined height and with a set weight [1].
The standardized Charpy test was developed in 1901 by
Georges Charpy who standardized S.B. Russell’s idea of
residual fracture energy [1]. These impact tests are carried out
generally only on materials whose brittle/ductile properties are
affected by temperature. Generally, the Charpy test is used to
show a ductile-brittle transition in a material due to change of
temperature. This ductile-brittle transition can be used to
determine the ductile-brittle transition temperature, which is the
temperature at which there is a large change in the energy
needed to fracture a material [1].
EXPERIMENTAL METHODS
To begin the Charpy test, pick out 5 soft steel samples
with a square face of 10x10 mm and 55mm long. Each sample
will need to be given a V-notch with the manual V-notch
Charpy machine. To do this, place the metal sample into the
slot and tighten up the pins to lock it in place. Now release the
pin on the machine and slowly crank the wheel down until the
blade has fully gone past the sample. Remove the sample and
repeat for all samples. Next will be to prep each sample for
what environment they are going into. One sample will be room
temperature, one goes into the freezer, two go into dry ice, and
1
Copyright © 2023 by ASME
one goes into boiling water. Once each sample is undergoing a
temperature change, it will be time to set up the Charpy
hammer. To do this the hammer will be lifted until it latches
onto the lever, once the hammer is latched, slide the safety onto
the lever which locks the lever in place. Now that the hammer
is set, take the room temperature sample and place it on the
little platform with the V-notch facing the opposite wall of the
hammer. Once the sample is set, release the safety and push the
lever forward. Once the hammer is released it will strike the
sample. Take the sample, examine it, and record the foot
pounds from the dial on the Charpy machine. This process will
be repeated for each sample after the desired temperature is
reached. The sample in the boiling water will boil for 20
minutes, the sample in the freezer should freeze for 45 minutes,
one dry ice sample stays in the box for 15 minutes and the other
stays in the dry ice for 35 minutes. DATA AND
R
ESULTS
Table 1 contains all measurements and results taken from
each sample test. Figure 1 shows the visual results of the
Charpy test. Figure 2 displays the trend of the data found in
Table 1. The two dry ice samples performed as expected during
the test. Both samples were brittle from the colder temperature
and therefore had the lowest absorption energy. The dry ice
sample prepared at 15 min had a higher absorbed energy of 34
ft-lb while the 35 min dry ice sample had a absorbed energy of
23 ft-lb. This was expected as the 35 min sample had longer to
cool down and become more brittle. Both dry ice samples fully
separated and broke in half during the collision. The room
temperature and boiled samples also performed as expected.
The room temperature sample had an absorption value of 63 ft-
lb that was in between the dry ice and the boiled samples. The
room temperature sample also broke completely in half. The
boiled sample had a high absorption energy of 195 ft-lb and did
not fully separate from the collision. The freezer sample
performed differently than expected. It should have had a value
somewhere between the dry ice samples and the room
temperature sample or between 34 and 63 ft-lb. However, it
had a higher absorbed energy than the boiled sample at 203 ft-
lb and it did not break in half during the collision. Figure 3
shows the expected data trend including a theoretical freezer
value of around 40 ft-lb. The lower shelf, transitional
temperature, and upper shelf are more distinguishable in this
figure.
Table 1. Steel Sample Data
Sample
Time [min]
Temperatur
e [°F]
Absorbed Energy
[ft-lb]
Dry Ice
35
-94.3
23
Dry Ice
15
-92.4
34
Freezer
45
-0.6
203
Room -
71.4
63
Temp
Boiled
20
209.5
195
Figure 1. Fracture Surface of Samples at Different
Temperatures
Figure 2. Absorbed Energy vs Temperature Curve
Figure 3. Theoretical Absorbed Energy vs Temperature
Curve
DISCUSSION
The following experiment requires an individual to be
quick when working with material because in order to get the
2
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most accurate result the material must be tested quickly after
the temperature has been taken. This experiment requires one
trial for each of the 5 temperatures of material. The first piece
of material tested was room temperature steel. Its temperature
was recorded at 71.4° F and its absorbed energy is 63 ft-lb.
Next was the first dry ice material which was recorded at -
92.4°F and it absorbed 34 ft-lb. This temperature is obtained by
letting the steel bar sit in dry ice for 15 minutes. The boiled
steel was 209.5° and withstood 195 ft-lb of force. This
temperature was reached by allowing the steel bar to sit in
boiling water for 20 minutes. The second dry ice material had a
recorded temperature of -94.3°F and withstood 23 ft-lb of
force. This temperature was achieved by letting the steel bar sit
in dry ice for 35 minutes. The final piece of material tested was
the freezer material. The recorded temperature was -.06° F and
it withstood 203 ft-lb of force. The temperature was recorded
after letting the bar sit in the freezer for 45 minutes. Before
testing it was believed that the colder materials would handle
more force but after testing the freezer sample, the hypothesis
was incorrect. There are many reasons as to why the test for the
freezer material could be invalid. It could have taken too long
to transfer material from the freezer to the testing station, the
notch could have been off center, and a tougher material could
have been used since the given samples were unlabeled and
could have been a variety of different steels.
CONCLUSION
The Charpy test is done by a big hammer on a
pendulum and is released to strike a metal sample. After
performing the test 5 times on metal subjects with each a
different temperature. It was observed that the 71.4° Fahrenheit
sample absorbed 63 ft/lb. The 209.5° Fahrenheit sample
absorbed 195 ft/lb. The -94.3° Fahrenheit sample absorbed 23
ft/lb. The -92.4° Fahrenheit sample absorbed 34 ft/lb. The -0.6°
Fahrenheit sample absorbed 203 ft/lb. Q
UESTIONS
1.
The notch is necessary for the notched-bar impact
testing in order for the samples to perform similarly to
each other and to give more accurate testing results.
The notch gives a consistent striking target that is
easily controllable by the depth of the notch.
2.
The sharper the point in the notch the faster the crack
will develop due to the smaller radius. The notch also
needs to be centered as best as possible so that the
tests have less variability. The faster the hammer
swings, the more kinetic energy it will have. So the
speed needs to be consistent in order to correctly find
the energy absorbed by the material.
3.
In general, the colder the temperature, the more brittle
the mild steel should be resulting in lower toughness.
Raising the temperature increases the ductility, which
increases the amount of energy the material can
absorb, therefore making the toughness of the material
greater.
4.
E
=
ΔPE
+
ΔKE ΔKE
=
0
Since v
1
=
v
2
=
0
E
=
mgh
=(
60
lb
/
32.2
ft
/
s
2
)(
32.2
ft
/
s
2
)
¿
R
EFERENCES
[1]
"Charpy
Impact
Test."
Wikipedia
,
Wikimedia
Foundation,22,Oct.,2022,
en.wikipedia.org/wiki/Charpy_impact_test. Accessed 20
Sept. 2023.
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7
8
9
10
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13
14
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Stress, psi
Stress, psi
80000
70000
60000
50000
40000
30000
20000
10000
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Would you advise the use of this material over one with a Weibull Modulus of 19.6 and a mean failure stress of 270 MPa, if you
anticipate that the peak stress on the material could be 255 MPa?
Sample
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
Select one or more:
Failure Stress (MPa)
297
293
270
300
260
286
265
295
4
293
280
288
263
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Mild steel 1
Young;s modulus 1219.5
Yield strain and stress (0.4101,500.08)
Failure stress and strain :not able to find because the given data shows the experiment did not reach the failure point.
if the material stress and strain does not reach a failure point ,what dose it means , does it means that the material is more stronger?
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A
B
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force
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D
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a.
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Length (mpm
1
2
4
6.
7
50
58
70
74
82
9n
102
125
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of steel or
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Diamond
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Gray Cast iron 40
FC Brass 360
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Length (mm)
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(Ib)
Al
(in.)
00000
3,000
6,000
0.00167
0.00333
7,500
0.00417
9,000
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0.0090
0.040
12,000
0.26
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a)
Plot the data as engineering stress versus engineering strain.
b)
Compute the modulus of elasticity.
c)
Determine the yield strength at a strain offset of 0.002.
d)
Determine the tensile strength of this alloy.
e)
What is the approximate ductility, in percent elongation?
f)
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g)
Compute from the data and plot true stress versus true strain diagram.
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50,000
45,000
40,000
35,000
30,000
25,000
20,000
15,000
10,000
5,000
0
O
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Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY