CHM 101L M3 Evaluate Antacids LabDone

Part A: Standardization of Potassium Permanganate, KMnO4 Solution Your Data Group I Group II Group III Mass of Na2C2O4 used 0.23 9 0.30 g 0.22g 0249 Initial buret reading Om L 3 mL 0 mL 0 mL Final buret reading 36.6 mL 28 mL 31.3mL 51.1mL Volume of KMnO4 used 36.6 mL 50 mL 31.3 mL 51.1mL 25+25

NaOH Concentration (M): 0.09669M   Trial 1: Inital Volume of NaOH: 0.55mL Final Volume of NaOH: 28.25 mL  Trail 2:  Intial Volume of NaOH: 18.1 mL Final Volume of NaOH: 46.1 mL   Concentration of HCl Solution Subtract the initial buret reading from the end point reading. Convert the readings to liters by dividing by 1000.     Solve this equation for the concentration of HCl:                  (CHCl)  (0.01000 liters )    =     (CNaOH)  (volume of NaOH in liters).                CNaOH is the normality of the NaOH you recorded from the bottle.       Average the two HCl concentrations.

GIVEN 5.0 mL of 2.0M barium chloride (BaCl2) 5.00 mL of sulfuric acid 5 mL of 1.0 M HCl

Use your average AA concentration to calculate the mass percent of acetic acid in vinegar.

Should be 3 answers in total. Will thumbs up! Next the student conducts two different runs: In RUN 1, 10.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 80.0 mL of wate In RUN 2, 20.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 70.0 mL of wate The following plots were obtained for each of the runs: [crystal orange] vs time (RUN 1) In[crystal orange] vs time (RUN 1) 0.0012 0.001 -2 y--0.4463x- 7.3334 y =-0.0002x + 0.0007 R- 0.6565 R = 0.893 0.0008 4 0.0006 -6 0.0004 -8 0.0002 0.0002 -12 time (hr) time (hr) 1/[crystal orange] vs time (RUN 1) 1/[crystal orange] vs time (RUN 2) 12000 25000 10000 20000 8000 15000 6000 y = 2000x + 1000 R =1 10000 y 4000x + 1000 R =1 4000 2000 5000 time (hr) time (hr) Figure 4. Kinetic traces for the reaction between crystal orange and sodium hydroxide. What is the order with respect to CO? | Select ] What is the order with respect to NaOH? | Select ] What is the value of the averaged rate constant for the reaction above? Give…

HP TrueVision HD 4 Texas Workfor Mộc Homework × W. College Physic mical App AN Careers eagleonline.hccs.edu/courses/188795/assignments/3601808 valnabie diler reD 4 dl 10.1Tam Constants | Periodic Table Part O Complete the fourth row. Complete the following table by calculating the missing entries and indicating whether the solution is acidic or basic. Express your answer using two decimal places. Acidic or [H+] [OH-] pH pOH basic? 7.4x10-3 ΑΣφ 3.3x10-10 M pH 8.25 5.73 Is to fa ho II 10 insert

What volume of a 36.0 wt% HC1 (FM 36.458) solution must be diluted to prepare 1.000 L of a 0.100 0 M HCl solution? The density of 36.0 wt% HC1 is 1.18 g/mL. O 11.7 mL O 8.58 mL O 1.20 mL O 10.1 mL 64.6 mL

Determine the amount in grams of KCI that exists in 20.3 g of a solution that contains 1.14 % KCl by mass X STARTING AMOUNT RESET 3 ANSWER ADD FACTOR * ( ) 0.001 1000 %m KCI 6.022 x 10²3 20.3 mol KCI 74.55 17.8 g solution 100 1.14 g KCI 1450 1 g KCl/mol 0.272 10 0.014 23.1 0.231 0.1 0.01 Tap here or pull up for additional resources

15 16 17 18 19 20 21 22 23 24 25 26 27 An aqueous solution at 25 °C has a OH concentration of 1. x 10 "M. Calculate the H,O' concentration. Be sure your answer has 1 significant digits. -10 M dh Submit Assignment Continue MacBook Air F12 F9 F10 888 O00 FB 30 F7 F5 F6 esc F4 F2 F3 F1 & @ # $ %3D 4 5 7 8 9 2 3

SAMPLE: CANE VINEGAR % acidity in label: 4.5% %purity of KHP: 99.80% FORMULA WEIGHT of KHP: 204.22 g/mol STANDARDIZATION OF NAOH SOLUTION TRIAL 1 TRIAL 2 TRIAL 3 Weight of KHP, g Initial volume of NaOH, mL Final volume of NaOH, mL 0.1012 0.1004 0.09987 5.00 10.01 4.95 9.99 14.93 Molarity of NaOH Average Molarity of NaOH ANALYSIS OF ACETIC ACID IN A VINEGAR SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of vinegar, mL 1.00 1.00 1.00 Initial volume of NaOH, mL 14.98 22.90 30.87 Final volume of NaOH, mL 22.84 30.77 38.75 Molarity of acetic acid Average molarity of acetic acid ANALYSIS OF CARBONIC ACID IN A SODA SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of soda, mL 20.0 20.0 20.0 Initial volume of NaOH, mL 20.20 22.05 23.93 Final volume of NaOH, mL 22.03 23.89 25.8 Molarity of carbonic acid Average molarity of carbonic acid

If you use [KMnO4]=0.0252 M, Concentration of FeSO4 7 H2O = 5.70 g/L Using a 100-mL graduated cylinder, 50 mL sample of FeSO4*7 H₂O will be measured out. To each sample of FeSO4 7 H2O, add 10.0 mL of H2SO4 and 10 mL of H3PO4 Concentration of SnCl2 2 H2O 2.85 g/mL Using a 100-mL graduated cylinder, 50.0 mL sample of SnCl2 2 H₂O will be measured out. No additional acid is needed. #1 KMnO4 #1 KMnO4 Sample # Initial buret, mL Final buret, mL FeSO4*7 H2O 12.05 21.51 SnCl2 2 H₂O 0.07 9.54 Question) Answer the following questions. b) Determine mol of electron lost per mol of Sn ion. 1) In this case, your answer should be in decimal notation (for example, 0.123, not 1.23*10^-1) with the correct number of significant figures. Also follow the unit specified in each question. Do NOT put its unit in your answer because its unit is shown already in the questions.

1. Answer the following questions based on the table: Pickling Vinegar Conc NaOH (M) 0.1005 Trial #1 Trial #2 Trail #3 Trial #4 Volume Vinegar (mL) 2.00 2.00 2.00 2.00 Initial Volume NaOH (mL) 0.32mL 0.22 1.02 0.44 Final Volume (mL) 24.25mL 24.20 25.00 24.45 Volume NaOH added (mL) 23.93mL 23.98mL 23.98mL 24.01mL a) Calculate the Average Volume NaOH used...show the trials that have %difference within 1% of each other. If you need to discard any trials- make sure to note this. b) Mass percentage of acetic acid in vinegar using your average volume of NaOH from Q1: (include a balanced reaction equation and show all work) c) % error calculation. Show ybur work in full. See Appendix B for details. (Reminder: Regular vinegar is 5.25% listed on bottle, pickling vinegar is 7.34% listed on bottle) d) In the titration of vinegar, a student uses 12.36 mL of NaOH(aq) (Molarity 0.100 M) to titrate a 2.00 mL sample of vinegar. If the student used lithium hydroxide (Molarity: 0.200 M) instead, what…

EXPERIMENT 2: Preparation of ca 0.1 mol.dm3 HCI Solution Pre-calculation: mHCl solution = 1,16 x 103 x 32 = 3,712 x 10² g 100 CHCI-soluion = 3,712 x 102 36,46 x 1dm3 = 10,18 mol.dm 3 CV1 = C2V2 0,1 mol.dm-3 x 500 mL 10,18 mol.dm3 VHC-Solution = C2V2 = = 4,9 mL Task: Calculate the volume of the same to 1000 cm to make a 0.05 mol.dm3 HCl solution at room temperature. centrated HCl as from the above exp iment which can be diluted

To enter exponential values, use the format 1.0e-5. Solution 1.10 M Acetic acid (mL) 0.900 M Sodium acetate (mL) [H30*] (M) 1 8.00 2.00 2 7.00 3.00 3 6.00 4.00 4 5.00 5.00 4.00 6.00 6. 3.00 7.00 7 2.00 8.00 8 1.00 9.00 LO

assignmentProblemID=142966924&offset3=next CHE154-H Gen Chem II Bronikowski S20 Part A Determine the percent ionization of a 0.245 M solution of benzoic acid (K, = 6.5 x 1) Express your answer using two significant figures. > View Available Hint(s) 1 ΑΣφ ха Хь х IXI X•10" Submit Previous Answers

Can someone check to see if #9 through #12 are correct with the information provided

I need help on questions 1-2? If you can't help me on question 2, then you can help me on question 1.

I need help with the calculations for this lab.

I need help with questions 1-4? Also if I'm wrong on question 1 can you do it again? If not you can continue with questions 2-4?

Using the average volume of HCl from #2, calculate the average concentration of your unknown acid. Avg. volume of HCl → 16mL

1.What is the volume of NaOH? And the 2.concantration of NaOH?

please help me find concentration   Concentration of TZ stock solution (μMμM) 42.06

Fill in the table

Sea X Assignments: ANATO X Gi 0220907135028396%20(1).pdf 2 CD Page view Human Anatomy X A Read aloud *20220907135028396 X TAdd text Draw 4 You prepare four solutions: Solution 1: Reactants + enzyme at #0 (about 100°F) and pH 7 Chemistry Check your recall lab. x V Highlight UNIT 2 65 3 Decompression sickness (also known as the bends) is a condition that affects divers and others operating under pressurized conditions. It occurs when gases such as nitrogen (N₂) come out of solution in the blood. This can lead to symptoms including joint pain, shortness of breath, and paralysis. Severe cases may result in death. a What type of molecule (ionic, polar covalent, nonpolar covalent) is nitrogen gas? b The liquid medium of blood is water. What type of compound (ionic, polar covalent, nonpolar covalent) is water? c What happens when molecules such as nitrogen gas mix with water? How does this explain the problems we see with decompression sickness?

What is the molarity of an aqueous solution that contains 0.0720 g CaH.O2 per gram of solution . The density of the solution is 1.04 g/mL STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 62.08 0.001 1.21 x 10-3 6.022 x 1023 1.04 1.12 1 1.21 4650 0.0720 1000 g solution/mL g C2HO2 g solution mol C2H6O2 g C:H6O2/g solution g C2H6O2/mol L solution M C2H&O2 mL solution

Determination of unknown acid concentration     Trial 1 Trial 2 Trial 3 Unknown Acid number Volume of acid used (mL) 25 mL 25 mL 25 mL Initial buret reading (mL) 50 mL 50 mL 50 mL Final buret reading (mL) 14.8 mL 15 mL 14.5 mL Volume of NaOH used (mL) 50 mL 50 mL 50 mL Molarity of NaOH       Calculated molarity of HCl (M)               Show a sample calculation of HCl molarity   AVERAGE MOLARITY OF Unknown HCl Show a sample calculation of NaOH molarity

Determination of known acid concentration     Trial 1 Trial 2 Trial 3 Volume of acid used (mL) 25 mL HCl 25 mL HCl 25 mL HCl Initial buret reading (mL) 50 mL 50 mL 50 mL Final buret reading (mL) 30 .7 mL 31.1 mL 29.3 mL Volume of NaOH used (mL) 50 mL 50 mL 50 mL Molarity of NaOH       Calculated Molarity of HCl   Show a sample calculation of HCl molarity   Average concentration of HCl from Trials 1,2, and 3   The “true” concentration of HCl is 0.10 M. The calculated average concentration of HCl is ______________M. The % error is = (???? − ?????)/????? ? 100