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EXPERIMENT 2: Preparation of ca 0.1 mol.dm HCI Solution Pre-calculation: mHC-solaton = 1,16 x 103 x 32 = 3,712 x 102 g 100 !3! CHCL = 3,712 x 102 36,46 x 1dm3 %3D = 10,18 mol.dm 3 CV = C2V2 0,1 mol.dm3 x 500 mL 10,18 mol.dm3 %3D HCI-solution = 4,9 mL %3D C1 Task: Calculate the volume of the same concentrated HCl as from the above experiment which can be diluted to 1000 cm to make a 0.05 mol.dm HCl solution at room temperature.

EXPERIMENT 2: Preparation of ca 0.1 mol.dm HCI Solution Pre-calculation: mHC-solaton = 1,16 x 103 x 32 = 3,712 x 102 g 100 !3! CHCL = 3,712 x 102 36,46 x 1dm3 %3D = 10,18 mol.dm 3 CV = C2V2 0,1 mol.dm3 x 500 mL 10,18 mol.dm3 %3D HCI-solution = 4,9 mL %3D C1 Task: Calculate the volume of the same concentrated HCl as from the above experiment which can be diluted to 1000 cm to make a 0.05 mol.dm HCl solution at room temperature.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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EXPERIMENT 2: Preparation of ca 0.1 mol.dm3 HCI Solution Pre-calculation: mHCl solution = 1,16 x 103 x 32 = 3,712 x 10² g 100 CHCI-soluion = 3,712 x 102 36,46 x 1dm3 = 10,18 mol.dm 3 CV1 = C2V2 0,1 mol.dm-3 x 500 mL 10,18 mol.dm3 VHC-Solution = C2V2 = = 4,9 mL Task: Calculate the volume of the same to 1000 cm to make a 0.05 mol.dm3 HCl solution at room temperature. centrated HCl as from the above exp iment which can be diluted
Transcribed Image Text:EXPERIMENT 2: Preparation of ca 0.1 mol.dm3 HCI Solution Pre-calculation: mHCl solution = 1,16 x 103 x 32 = 3,712 x 10² g 100 CHCI-soluion = 3,712 x 102 36,46 x 1dm3 = 10,18 mol.dm 3 CV1 = C2V2 0,1 mol.dm-3 x 500 mL 10,18 mol.dm3 VHC-Solution = C2V2 = = 4,9 mL Task: Calculate the volume of the same to 1000 cm to make a 0.05 mol.dm3 HCl solution at room temperature. centrated HCl as from the above exp iment which can be diluted
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