4.7 worksheet answers

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SCH 4U1 4.7 Intermolecular Forces – Worksheet - ANSWERS 1. Draw the following substances. Then, identify all the intermolecular forces present in pure samples of the following substances: a) SO 2 london dispersion, dipole dipole b) H 2 O london dispersion, dipole dipole, hydrogen bonding c) CH 2 Cl 2 london dispersion, dipole dipole d) SCO london dispersion, dipole dipole e) PCl 3 london dispersion, dipole dipole f) XeF 4 london dispersion 2. Based on the intermolecular forces present, predict the relative boiling points of each of the substances below. Arrange each series of substances in order of increasing boiling point. State your reasons for the order you use (identify the forces and explain how they affect the boiling point). a. methoxymethane (CH 3 OCH 3 ), ethanol (CH 3 CH 2 OH), and propane (CH 3 CH 2 CH 3 ) lowest bp: propane (CH 3 CH 2 CH 3 ) < methoxymethane (CH 3 OCH 3 )< ethanol (CH 3 CH 2 OH) highest bp Dimethyl ether cannot form hydrogen bonds (no O-H bond), but is polar and has dipole-dipole forces. Ethanol can form hydrogen bonds. propane is nonpolar, so it has only London dispersion forces. The boiling point increases as the strength of the intermolecular forces increase: London dispersion < dipole-dipole forces < hydrogen bonds [All have similar molar masses: 46.07g/mol, 46.07g/mol and 44.09g/mol respectively.] b. Br 2 , Cl 2 , I 2 lowest bp: Cl 2 < Br 2 < I 2 highest bp All are nonpolar molecules so only London dispersion forces are present. London dispersion forces get stronger as molar mass increases. 3. Rank the following substances in terms of increasing boiling points: water, CH2O, methane, CO2 methane, CO 2 , CH 2 O, water 4. Rank the following compounds from lowest to highest boiling point: calcium carbonate, methane, methanol (CH4O), dimethyl ether (CH 3 OCH 3 ). By using intermolecular forces, we can tell that these compounds will rank: methane (Van der Waals forces), dimethyl ether (dipole-dipole forces), methanol (hydrogen bonding), calcium carbonate (ionic bonds that are much stronger than any of the 3 intermolecular forces). 5. Compare the solubility of each of the following pairs of compounds in water. Which compound if any, would be soluble? Explain why.
a) HBr vs. Br 2 HBr is polar and thus would be soluble in water. Br 2 is non-polar therefore it would not be soluble in water. b) HBr vs. HF HF is more polar than HBr (due to the difference in the electronegativites in the bonds), and HF is able to hydrogen bond, where HBr has weaker dipole-dipole forces. Thus, although both compounds would be soluble in water since they are polar, HF would be more soluble. c) NCl 3 vs NF 3 NCl 3 is a non-polar molecule since the molecule only contains non-polar bonds, thus it would be insoluble in water. NF 3 is a polar molecule and thus it would be soluble in water. 6. If you have samples of HBr and Br 2 and you accidentally mixed them together, would you expect them to mix or separate into layers? Since HBr is a polar molecule and Br 2 is a non-polar molecule, the two samples will not mix together, instead they will form separate layers. 7. Complete the following online quizzes: http://highered.mheducation.com/sites/0070938539/student_view0/chapter6/study_quiz_2.html http://highered.mheducation.com/sites/0070938539/student_view0/chapter6/study_quiz_3.html
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