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Use your average AA concentration to calculate the mass percent of acetic acid in vinegar.

Use your average AA concentration to calculate the mass percent of acetic acid in vinegar.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Use your average AA concentration to calculate the mass percent of acetic acid in vinegar.

Results Quantity Trial 1 Trial 2 Trial 3 M NaOH 0.992 M 0.992 M 0.992 M V initial buret 0 ml 15 ml 30 ml V Final buret 13.1 ml 28.2 ml 47.9 ml Vep = VNAOH added = Vf - Vi (47.9ml-30ml)= (13.1ml-0ml)= 13.1 ml (28.2ml-15ml)= 13.2ml 17.9ml Vep = VNAOH in L 0.0131 L 0.0132 L 0.0179 L moles NaOH= (0.992M)(0.0131 L)= | (0.992M)(0.0132 L)= | (0.992M)(0.0179 L)= MNAOH x VNaOH 0.0129 mol 0.0130 mol 0.178 mol moles AA = moles 0.0129 mol 0.0130 mol 0.178 mol NaOH Vsample = Vacid 0.0150 L 0.0150 L 0.0150 L Actual molarity of 0.0129mol/0.0150L= 0.0130mol/0.0150L= 0.0178mol/0.0150L= AA 0.86 M 0.87 M 1.186 M Average Molarity of AA: (0.86M)(0.87M)(1.186M)=0.887 M
Transcribed Image Text:Results Quantity Trial 1 Trial 2 Trial 3 M NaOH 0.992 M 0.992 M 0.992 M V initial buret 0 ml 15 ml 30 ml V Final buret 13.1 ml 28.2 ml 47.9 ml Vep = VNAOH added = Vf - Vi (47.9ml-30ml)= (13.1ml-0ml)= 13.1 ml (28.2ml-15ml)= 13.2ml 17.9ml Vep = VNAOH in L 0.0131 L 0.0132 L 0.0179 L moles NaOH= (0.992M)(0.0131 L)= | (0.992M)(0.0132 L)= | (0.992M)(0.0179 L)= MNAOH x VNaOH 0.0129 mol 0.0130 mol 0.178 mol moles AA = moles 0.0129 mol 0.0130 mol 0.178 mol NaOH Vsample = Vacid 0.0150 L 0.0150 L 0.0150 L Actual molarity of 0.0129mol/0.0150L= 0.0130mol/0.0150L= 0.0178mol/0.0150L= AA 0.86 M 0.87 M 1.186 M Average Molarity of AA: (0.86M)(0.87M)(1.186M)=0.887 M
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