EBK SYSTEM DYNAMICS3rd EditionPalm Publisher: YUZUISBN: 9780100254961
EBK SYSTEM DYNAMICS
Solutions for EBK SYSTEM DYNAMICS
Problem 3.2P:
A baseball is thrown horizontally from the pitcher’s mound with a speed of 90 mph. Neglect air...Problem 3.3P:
For the mass shown in Figure 3.1.3b. m=10 kg, =25 , v0=2 m/s, And =0.3 . Determine whether the mass...Problem 3.4P:
A particle of mass m=19 kg slides down a frictionless ramp starting from rest (see Figure P3.4)....Problem 3.5P:
A particle of mass m slides down a frictionless ramp starting from rest (see Figure P3.4). The...Problem 3.6P:
A radar tracks the flight of a projectile (see Figure P3.6). At time t, the radar measures the...Problem 3.7P:
Table 3.2.1 gives the inertia IO for a point mass in rotation. Suppose instead that a sphere of...Problem 3.8P:
A motor supplies a moment M to the pulley of radius R1 (Figure P3.8). A belt connects this pulley to...Problem 3.9P:
Figure P3.9 shows an inverted pendulum. Obtain the equation of motion in terms of the angle .Problem 3.10P:
The two masses shown in Figure P3.10 are released from rest. The mass of block A is 100 kg; the mass...Problem 3.11P:
The motor in Figure P3.11 lifts the mass mL by winding up the cable with a force FA . The center of...Problem 3.12P:
Instead of using the system shown in Figure 3.2.6a to raise the mass m2 . An engineer proposes to...Problem 3.13P:
Consider the cart shown in Figure P3.13. Suppose we model the wheels as solid disks. Then the wheel...Problem 3.14P:
Consider the cart shown in Figure P3.13. Suppose we model the wheels as solid disks. Then the wheel...Problem 3.15P:
Consider the spur gears shown in Figure P3.15, where I1=0.3kgm2 and I2=0.5kgm2 . Shaft 1 rotates...Problem 3.16P:
Consider the spur gears shown in Figure P3.15, where I1=0.1kgm2 and I2=2kgm2 . Shaft 1 rotates twice...Problem 3.17P:
Derive the expression for the equivalent inertia Ie felt on the input shaft, for the spur gears...Problem 3.19P:
The geared system shown in Figure P3.19 represents an elevator system. The motor has an inertia I1...Problem 3.23P:
For the geared system shown in Figure P3.23, assume that shaft inertias and the gear inertias I1 ,...Problem 3.24P:
For the geared system discussed in Problem 3.23, shown in Figure P3.23, the inertias are given in...Problem 3.25P:
The geared system shown in Figure P3.25 is similar to that used in some vehicle transmissions. The...Problem 3.26P:
Consider the rack-and-pinion gear shown in Figure P3.20. Use the free-body diagram method to obtain...Problem 3.28P:
The lead screw (also called a power screw or a jack screw) is used to convert the rotation of a...Problem 3.30P:
Derive the equation of motion of the block of mass m1 in terms of its displacement x (see Figure...Problem 3.31P:
Assume the cylinder in Figure P3.31 rolls without slipping. Neglect the mass of the pulleys and...Problem 3.35P:
A slender rod 1.4 m long and of mass 20 kg is attached to a wheel of mass 3 kg and radius 0.05 m. as...Problem 3.38P:
The pendulum shown in Figure P3.38 consists of a slender rod weighing 3 lb and a block weighing 10...Problem 3.40P:
A single link of a robot arm is shown in Figure P3.40. The arm mass is m and its center of mass is...Problem 3.41P:
3.41 It is required to determine the maximum acceleration of the rear-wheel-drive vehicle shown in...Problem 3.42P:
Figure P3.42 illustrates a pendulum with a base that moves horizontally. This is a simple model of...Problem 3.43P:
Figure P3.43 illustrates a pendulum with a base that moves. The base acceleration is at . Derive the...Browse All Chapters of This Textbook
Chapter 1 - IntroductionChapter 2 - Dynamic Response And The Laplace Transform MethodChapter 3 - Modeling Of Rigid-body Mechanical SystemsChapter 4 - Spring And Damper Elements In Mechanical SystemsChapter 5 - Block Diagrams, State-variable Models, And Simulation MethodsChapter 6 - Electrical And Electromechanical SystemsChapter 7 - Fluid And Thermal SystemsChapter 8 - System Analysis In The Time DomainChapter 9 - System Analysis In The Frequency DomainChapter 10 - Introduction To Feedback Control Systems
Sample Solutions for this Textbook
We offer sample solutions for EBK SYSTEM DYNAMICS homework problems. See examples below:
Concept Used: 1 slug = 32.2 pounds. 32.2 lb = 143 N. 1 lb = 0.453592 kg. Calculation: The weight of...Given Information: Function f(θ)=sinθ Consider the following data. Function f(θ)=sinθ Angles, θ=π4...Given Information: Data is given by: x:2530354045y:02505007501000. Calculation: From the given data...Given: Half-life of carbon -14 is 5500 years Concept Used: Fraction of carbon -14 remaining time at...Given: yy¨+5y˙+y=0. Concept Used: An ordinary differential for y=y(t) is said to be linear if it can...Given: F(s)=6s2+9. Concept Used: Laplace transform of function f(t) is defined as...Given: F(s)=5ss2+9. Concept Used: Laplace transform of function f(t) is defined as...Given: The signal in frequency domain is given as shown below. X(s)=6s(s+4) Concept Used: The...Given: The given equation is as: x¨+8x˙+15x=30 With initial conditions as follows: x(0)=10 and...
Given: The given model equations are as: x˙=−4x+2y +f(t)and y˙=−9y−5x+g(t). Concept Used: Laplace...Given: The given model equation is as: 7x˙+5x=4g˙(t) Where, g(t)=us(t) and the initial conditions...Given: m=2,a=g, s=h and u=0 The height of the platform from the ground is 10 feet. The height of the...Given: Weight of a rear wheel = 500 lb. Weight of front wheel = 800 lb. Weight of the body = 9000...Given: Roller radius = R Inertia of roller = mR22 Mass of roller = m Weight of roller = 800N...Given: Wheel radius, R = 0.05m Mass of rod, m = 20kg Length of rod, L = 1.4m Mass of the wheel is...Given: Friction of the pivot and mass of the scale arm are neglected. Concept used: For an objects’...Given information: The number of turn in a coil is 6, the diameter of the coil is 4 in, the diameter...Write the expression for equality condition of potential energy and kinetic energy for Rayleigh’s...Given information: The mass of the block on an inclined plane is 50 kg, the angle of inclination is...Given information: The value of step function is 5000 and the equation of motion is...Given information: The damping coefficient is c and friction is negligible. The figure below shows...Figure (1) shows the free body diagram of the system. Figure-(1) Consider a point A on the system...Figure (1) shows the free body diagram of the system shown in part (a). Figure-(1) Here, the...Given: A spring with stiffness k, and a damper with damping coefficient c, are attached to a...Given: A spring with stiffness k, and a damper with damping coefficient c, are attached to a...Given: The masses are m1=20 kg and m2=60 kg The spring constant are k1=3×104 N/m and k2=6×104 N/m...Given: The given block diagram is as shown in figure (i). Concept Used: The given block diagram is...Given: The block diagram for the model with input R(s) and the output as C(s). Concept Used: The...Given: The transfer function of the system is as shown: Y(s)F(s)=s+2s2+4s+3 With given initial...Given information: The given relation between the voltage and current is, vs=Rei All resistors are...Given: The speed control system for the field-controlled motor has been given as shown in figure 1:...Given information: The given parameters for the armature-controlled motor are as follows: KT=Kb=0.05...Given: The given parameters for an armature-controlled motor are as: Kb=KT=0.2 N⋅m/A, c=5×10−4...Given: The electrical and mechanical sub-system of the speaker system is shown in figure below:...Given information: The area of the left side is 10 in2, the area of right side is 30 in2, the weight...Calculation: The figure below shows the pump curve and the line for steady-state flow. Figure-(1)...Calculation: Write the radial resistance of the pipe. Rp=ln(rori)2πkL...... (I) Here, the inner...Given information: The initial temperature of water is 120°F, the length of copper pipe is 6 ft,...Calculation: Write the expression for the rate of heat transfer in terms of total thermal...Calculation: Write the expression for the thermal capacitance of the first mass. C1=dq1dT1dq1=C1dT1...Given: The equation of motion for the rocket sled is, 6v˙=2700−24v v(0)=0 Concept Used: Use Laplace...Given information: The given model equation is as: 2x˙+x=10f(t) With initial conditions as follows:...Given: The given model equation is as: x¨+4x˙+8x=2us(t) With initial conditions as follows: x(0)=0...Given: The given model equation is as: 3x¨+21x˙+30x=f(t) With initial conditions as follows: x(0)=0...Given: The given model equation is as: 3x¨+21x˙+30x=4t With initial conditions as follows: x(0)=0...Given Information: Transfer function is given by, T(s)=Y(s)F(s)=2514s+18. Input signal is,...Given: T(s) =8s(s2+10s+100), f(t)=6sin9t. Concept Used: Using the final value theorem Calculation:...Given: The circuits are as shown below: Concept Used: Kirchhoff’s current and voltage laws are...Given: The displacement produced by the cam is given by the following figure Figure 1 Figure 2 Where...Given: To consider a Traffic light as a device A device or process is said to be in a closed loop if...Given: The proportional integral controller of the first order plant is as shown below: Where, the...Given: The proportional integral controller of first order plant is as shown below: Where, the...Given: The I controller with an internal feedback loop of first order plant is as shown below:...Given: The I controller with an internal feedback loop of first order plant is as shown below:...Given: The proportional integral controller of first order plant is as shown below: Where, the...Given: The proportional integral controller of first order plant is as shown below: Where, the...Given information: The characteristic equation is given as 3s2+12s+k=0 for k≥0. Concept Used: Root...Given: 1+G(s)H(s)=s(s+5)+K for K≥0. Concept Used: Root Locus technique. Calculation: The...Given: 1+G(s)H(s)=s(s+5)+K for K≥0. Concept Used: Root Locus technique. Calculation: The...Given: The equation is Gp(s)=4p(s2+4ζs+4)(s+p). ζ=0.5,p=1. Concept Used: Ultimate cycle technique of...Given information: The transfer function of the plant is Gp(s)=Θ(s)Φ(s)=15s2−6. For a closed loop...Given: m=0.5 kgk=500 N/mY=4 mmf=3 Hz Concept Used: Displacement transmissibility. Calculation: The...Given information: The main mass is m1. Write the expression for force of mass 1....Given information: The main mass is m1. Write the expression for force of mass 1....Given information: The stiffness of suspension 1 is 1.95×104 N/m, the stiffness of the suspension 2...
More Editions of This Book
Corresponding editions of this textbook are also available below:
System Dynamics
1st Edition
ISBN: 9780073016030
System Dynamics (mcgraw-hill Mechanical Engineering)
1st Edition
ISBN: 9780256114492
SYSTEM DYNAMICS (OPTIONAL PRINT UPGRADE)
4th Edition
ISBN: 9781264262250
SYSTEM DYNAMICS (LOOSELEAF)
4th Edition
ISBN: 9781260443981
SYSTEM DYNAMICS
4th Edition
ISBN: 9780078140051
SYSTEM DYNAMICS CONNECT
4th Edition
ISBN: 9781265781651
SYSTEM DYNAMICS CONNECT W/LL COMBO
4th Edition
ISBN: 9781265824532
SYSTEM DYNAMICS (LOOSELEAF)-W/CONNECT
4th Edition
ISBN: 9781264094042
SYSTEM DYNAMICS-CONNECT ACCESS
4th Edition
ISBN: 9781260443950
EBK SYSTEM DYNAMICS
3rd Edition
ISBN: 8220100254963
System Dynamics
3rd Edition
ISBN: 9780073398068
System Dynamics
3rd Edition
ISBN: 9780077509125
SYSTEM DYNAMICS>LOOSELEAF<
3rd Edition
ISBN: 9781260163087
System Dynamics (Looseleaf) (Custom)
14th Edition
ISBN: 9781259114151
SYSTEM DYNAMICS CONNECT
3rd Edition
ISBN: 9781264201730
SYSTEM DYNAMICS LL+CONNECT
3rd Edition
ISBN: 9781264201891
System Dynamics
2nd Edition
ISBN: 9780071267793
System Dynamics
2nd Edition
ISBN: 9780073529271
System Dynamics
2nd Edition
ISBN: 9780077417260
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