Concept explainers
Interpretation:
The structure is to be proposed for the compound
Concept introduction:
舧 Nuclear Magnetic Resonance (NMR) is one of the most capable analytical techniques used for determining the functional groups and how the atoms are structured and arranged in a molecule.
舧 Few elements, such as
舧 In
舧 Induced magnetic field consists of electricity generated from movement in a magnetic field.
舧
舧 In
舧 The splitting of the molecules is determined by the
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Organic Chemistry
- Deduce the structures of compounds A and B, two of the major components of jasmine oil, from the given data. Compound A: C9H10O2; IR absorptions at 3091–2895 and 1743 cm-1; 1H NMR signals at 2.06 (singlet, 3 H), 5.08 (singlet, 2 H), and 7.33 (broad singlet, 5 H) ppm. Compound B: C14H12O2; IR absorptions at 3091–2953 and 1718 cm-1; 1H NMR signals at 5.35 (singlet, 2 H) and 7.26–8.15 (multiplets, 10 H) ppm.arrow_forwardAlpha-phellandrene, C₁0H16, is a pleasant-smelling chiral compound that may be obtained from the leaves of eucalyptus trees. It has the molecular formula C₁0H16 and a UV absorption maximum at 263 nm. On hydrogenation with a palladium catalyst, an achiral hydrocarbon with the formula C10H20 is obtained. Ozonolysis of alpha-phellandrene, followed by treatment with zinc and acetic acid, produces the following two compounds: CHIC-CH HOCHSCHICH CH(CH3)2 Propose a structure for alpha-phellandrene.arrow_forwardAlpha-phellandrene, C₁0H₁6, is a pleasant-smelling chiral compound that may be obtained from the leaves of eucalyptus trees. It has the molecular formula C₁0H16 and a UV absorption maximum at 263 nm. On hydrogenation with a palladium catalyst, an achiral hydrocarbon with the formula C₁0H20 is obtained. Ozonolysis of alpha-phellandrene, followed by treatment with zinc and acetic acid, produces the following two compounds: 0 || CH3C-CH 0 || ● Propose a structure for alpha-phellandrene. (+ || HCCH₂CHCH I CH(CH3)2 • You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. n [ ]# ?arrow_forward
- Identify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?arrow_forward-Ocimene is a pleasant-smelling hydrocarbon found in the leaves of certain herbs. It has the molecular formula C10H16 and a UV absorption maximum at 232 nm. On hydrogenation with a palladium catalyst, 2,6-dimethyloctane is obtained. Ozonolysis of -ocimene, followed by treatment with zinc and acetic acid, produces the following four fragments: (a) How many double bonds does -ocimene have? (b) Is -ocimene conjugated or nonconjugated? (c) Propose a structure for -ocimene. (d) Write the reactions, showing starting material and products.arrow_forwardCompound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forward
- 1,3,5,7-Cyclooctatetraene, C8H8, is an unusual hydrocarbon in that it reacts with exactly 2 equivalents of potassium to give A, C8H8K2, which can be isolated as a white solid. A exhibits a single proton NMR signal. Draw the structure of A.arrow_forwardIn an aqueous solution containing sodium bicarbonate, aniline reacts quickly withbromine to give 2,4,6-tribromoaniline. Nitration of aniline requires very strong conditions,however, and the yields (mostly m-nitroaniline) are poor.(a) What conditions are used for nitration, and what form of aniline is present under theseconditions?arrow_forwardCompound A undergoes an acid-catalyzed hydrolysis. One of the products (B) that is isolated gives the following 1H NMR spectrum. Identify the compounds A and Carrow_forward
- A solution of acetone [(CH3)2C=O] in ethanol (CH3CH2OH) in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm−1, and the 1H NMR spectrum is given here. What is the structure of the product?arrow_forwardTreatment of W with CH3Li, followed by CH3I, affords compound Y(C7H14O) as the major product. Y shows a strong absorption in its IRspectrum at 1713 cm−1, and its 1H NMR spectrum is given below. (a)Propose a structure for Y. (b) Draw a stepwise mechanism for theconversion of W to Y.arrow_forward(a) The Friedel-Crafts reaction of benzene with 2-chloro-3-methylbutane in the presence of AlCl3 occurs with a carbocation rearrangement. Give mechanistic explanation and the product formed. (b) Predict the product(s) will be formed from the following reactions: (i) Bromination of p-methylbenzoic acid (ii) Sulphonation of m-bromoanisole (iii) Friedel-craft acylation of o-bromonitrobenzenearrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning