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- Mass spectrometry of an unknown compound revealed a molecular ion at m/z 100.09. The IR spectrum, the ¹³C NMR spectrum, and the ¹H NMR spectrum are shown below. Draw the structure of this compound. 4000 220 3000 200 180 160 2000 M 1500 Wavenumbers (cm-¹) 140 120 100 1H 80 6H 1000 40 3H 20 ppm 500arrow_forwardIndicate two basic differences that exist between the spectra of 1H y 13C in NMR.arrow_forwardA compound (L) with the molecular formula C9H10 reacts with bromine and gives an IR absorption spectrum that includes the following absorption peaks: 3035 cm ¹(m), 3020 cm ¹(m), 2925 cm ¹(m), 2853 cm ¹(w), 1640 cm ¹1(m), 990 cm ¹(s), 915 cm ¹(s), 740 cm ¹(s), 695 cm ¹(s). The ¹H NMR spectrum of L consists of: Doublet 3.1 ppm (2H) Multiplet 5.1 ppm Multiplet 7.1 (5H) ppm Multiplet 4.8 ppm Multiplet 5.8 ppm The UV spectrum shows a maximum at 255 nm. Propose a structure for compound L. Edit Drawing harrow_forward
- The 1H NMR spectra of two carboxylic acids with molecular formula C3H5O2Cl are shown below. Identify the carboxylic acids. (The “offset” notation means that the farthest-left signal has been moved to the rightby the indicated amount to fit on the spectrum; thus, the signal at 9.8 ppm offset by 2.4 ppm has an actual chemical shift of 9.8 + 2.4 = 12.2 ppm.)arrow_forwardIdentify the structures of isomers H and I (molecular formula C8H11N).a.Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and 1497 cm−1b.Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and 1492 cm−1arrow_forwardShown below is th carbon NMR spectrum of a compound of the formula C7H14. The compound decolorizes a solution of bromine in dichloromethane. Assign a structure to this hydrocarbon. Correlation of spectrum with number of hydrogen atoms attached to each carbon=arrow_forward
- The 13C-NMR spectrum of 3-methyl-2-butanol shows signals at d 17.88 (CH3), 18.16 (CH3), 20.01 (CH3), 35.04 (carbon-3), and 72.75 (carbon-2). Account for the fact that each methyl group in this molecule gives a different signal.arrow_forwardTreatment of compound C (molecular formula C9H12O) with PCC affords D (molecular formula C9H10O). Use the 1H NMR and IR spectra of D to determine the structures of both C and D.arrow_forwardThe 1H-NMR spectrum of compound B,C7H14O , consists of the following signals: δ 0.9 (t, 6H), 1.6 (sextet, 4H), and 2.4 (t, 4H). Draw the structural formula of compound B.arrow_forward
- Draw the structure for C5H10O with 1H NMR signals: δ 1.2 (s, 6H), 2.1 (bs, 1H), 5.0 (dd, 1H), 5.2 (dd, 1H), and 5.9 (dd, 1H).arrow_forwardDeduce the structure of this compound.arrow_forwardFollowing is the 1H-NMR spectrum of compound O, molecular formula C7H12. Compound O reacts with bromine in carbon tetrachloride to give a compound with the molecular formula C7H12Br2. The 13C-NMR spectrum of compound O shows signals at d 150.12, 106.43, 35.44, 28.36, and 26.36. Deduce the structural formula of compound O.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning