Chapter SH, Problem 9.8.3EP

To determine

The projected population of Belgrade in 2008.

Answer to Problem 9.8.3EP

Given:

Population =3422

Time = 8 years

Increment = 4.9%.

Calculation:

The projected population of Belgrade in 2008 will be:

  $\begin{array}{l}y=a{\left(1+r\right)}^t\\ y=3422{\left(1+0.049\right)}^8\\ y=5017.46\\ y\approx 5018\end{array}$

Explanation of Solution

Given:

Population =3422

Time = 8 years

Increment = 4.9%.

Calculation:

The projected population of Belgrade in 2008 will be:

  $\begin{array}{l}y=a{\left(1+r\right)}^t\\ y=3422{\left(1+0.049\right)}^8\\ y=5017.46\\ y\approx 5018\end{array}$