Chapter SH, Problem 7.3.13EP

To determine

The solution of given expression and result in both, scientific notation and standard form.

Answer to Problem 7.3.13EP

  $\begin{array}{l}58.65\\ \text{Standard Form: 58}\text{.65}\\ \text{Scientific Notation: 5}\text{.865}\times {10}^1\end{array}$

Explanation of Solution

Given:

The given expression is:

  $\left(2.3\times {10}^{-2}\right)\left(2.55\times {10}^3\right)$

Calculation:

The solution of the given expression will be:

  $\begin{array}{l}=\left(2.3\times {10}^{-2}\right)\left(2.55\times {10}^3\right)\\ =5.865\times {10}^{-2+3}\\ =5.865\times {10}^1\\ =58.65\\ \text{Standard Form: 58}\text{.65}\\ \text{Scientific Notation: 5}\text{.865}\times {10}^1\end{array}$