Chapter SH, Problem 6.2MPS

To determine

To find: The time the employee spends doing each type of service.

Answer to Problem 6.2MPS

The number of hours the employee spent on installation is $15$ hrs and that on troubleshooting is $25$ hrs.

Explanation of Solution

Given information:

The given charge of a computer is $40\$$ per hour for installation $60\$$ per hour troubleshooting.

The busiest employee worked for $40$ hours and has brought $\$2100$ .

Calculation:

Let the total hours to spent in installation to $x$ and the for troubleshooting be $y$ .

The total hours spent is,

  $x+y=40$

The equation for the income is,

  $40x+60y=2100$

Solve the equations.

  $\begin{array}{c}x+y=40\\ 40x+60y=2100\end{array}$

  $\begin{array}{c}20y=500\\ y=25\end{array}$

Put $y=25$ in $x+y=40$ .

  $\begin{array}{c}x+25=40\\ x=40-25\\ x=15\end{array}$

Therefore, the number of hours the employee spent on installation is $15$ hrs and that on troubleshooting is $25$ hrs.