Chapter SH, Problem 2.2.21EP

To determine

The solution of the given expression.

Answer to Problem 2.2.21EP

  $t=-\frac{130}{9}$

Explanation of Solution

Given:

The given expression is:

  $-4\frac{5}{12}=t-\left(-10\frac{1}{36}\right)$

Calculation:

The solution can be calculated as:

  $\begin{array}{l}-4\frac{5}{12}=t-\left(-10\frac{1}{36}\right)\\ -\frac{53}{12}=t+\frac{361}{36}\\ t=-\frac{361}{36}-\frac{53}{12}\\ t=\frac{-361-159}{36}\\ t=-\frac{520}{36}\\ t=-\frac{130}{9}\end{array}$

Check:

Put $t=-\frac{130}{9}$ ,

  $\begin{array}{l}-4\frac{5}{12}=t-\left(-10\frac{1}{36}\right)\\ -\frac{53}{12}=-\frac{130}{9}-\left(-\frac{361}{36}\right)\\ -\frac{53}{12}=-\frac{130}{9}+\frac{361}{36}\\ -\frac{53}{12}=\frac{-520+361}{36}\\ -\frac{53}{12}=-\frac{53}{12}\end{array}$