Chapter SH, Problem 11.5.13EP

To determine

The solution of the given expression.

Answer to Problem 11.5.13EP

  $3c-2$

Explanation of Solution

Given:

The given expression is:

  $\left(27c^2-24c+8\right)÷\left(9c-2\right)$

Calculation:

The expression cannot be factored, therefore using long division; the expression can be simplified as:

  $\begin{array}{l}9c-2\begin{array}{c}\hfill 3c-2\\ \hfill \overline{)27c^2-24c+8}\end{array}\\ \underset{\_}{27c^2-6c}\\ -18c+8\\ \underset{\_}{-18c+4}\\ -4a-12\\ \underset{\_}{-4a-12}\\ 4\end{array}$

Hence, quotient will be $3c-2$