Chapter SH, Problem 8.2.23EP

To determine

The solution of the given equation.

Answer to Problem 8.2.23EP

  $b=0orb=\frac{3}{2}$

Explanation of Solution

Given:

The given polynomial is:

  $8b^2-12b=0$

Calculation:

The solution of the given polynomial will be:

  $\begin{array}{l}8b^2-12b=0\\ 4b\left(2b-3\right)=0\\ 4b=0or2b-3=0\\ b=0orb=\frac{3}{2}\end{array}$

Check:

Put $b=0,$

  $\begin{array}{l}8b^2-12b=0\\ 8{\left(0\right)}^2-12\left(0\right)=0\\ 0=0\end{array}$

Put $b=\frac{3}{2},$

  $\begin{array}{l}8b^2-12b=0\\ 8{\left(\frac{3}{2}\right)}^2-12\left(\frac{3}{2}\right)=0\\ 2\left(9\right)-6\left(3\right)=0\\ 18-18=0\\ 0=0\end{array}$